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Homotopy theory, homological algebra, algebraic treatments of manifolds.
22
votes
Accepted
Entering to the K-theory realm
I think that doing algebraic K-theory properly certainly requires a good background on stable homotopy theory, that is to say the homotopy theory of spectra. Unfortunately there are not many textbooks …
5
votes
Accepted
The contravariant mapping space represented by a homotopical classifying space (e.g. BG)
Let $G$ be a topological group and $X$ be a paracompact Hausdorff topological space. For simplicity let us assume that $G$ has the homotopy type of a CW complex, although a lot of this answer does not …
16
votes
Accepted
Algebraic topology and homotopy theory with simplicial sets instead of topological spaces
It depends on what you mean by "all results". Of course results regarding manifolds or vector bundles do not admit statements completely internal to the world of simplicial sets (although most of them …
11
votes
Accepted
Roadmap for L-Theory
I apologize for the self promotion -- I hope the content of this answer can be useful anyway...
My favourite introduction to L-theory is Lurie's notes on Algebraic L-theory and surgery (warning: aggr …
3
votes
Accepted
(Algebraic) cobordism and the rank function
Let me first write what happens for classical cobordism. You are basically asking whether the map $\operatorname{MU}\to H\mathbb{Z}$ factors through the projection $\operatorname{ku}\to H\mathbb{Z}$. …
6
votes
Spectral sequences in algebraic topology
My favourite reference for understanding spectral sequences is
Boardman, J. Michael. "Conditionally convergent spectral sequences." Contemporary Mathematics 239 (1999): 49-84 (pdf).
I don't think I …
15
votes
Accepted
Are Spanier-Whitehead duals of general spaces expressible through some generalization of nor...
Let $X$ be a finite complex. Then the functor
$$\lim_X:\operatorname{Fun}(X,\operatorname{Sp})\to \operatorname{Sp}$$
sending a local system of spectra $E$ to its limit preserves all colimits. Indeed …
8
votes
Given a complex vector bundle with rank higher than 1, is there always a line bundle embedde...
I think thinking in terms of classifying spaces will help clarify the situation. We know that a rank $n$ complex vector bundle $V$ on $X$ is the same thing as a homotopy class of maps $f:X\to BU_n$. A …
8
votes
Accepted
On the definition of A-theory
Since the question remains unanswered, let me copy Tom Goodwillie's comment:
If you allow finitely dominated instead of finite, it changes only π0. Analogously, in defining K(R) if you use finitely g …
8
votes
Good reference for topological Hochschild homology
As a first introduction I like these notes by Achim Krause and Thomas Nikolaus. They do require some familiarity with spectra and stable homotopy theory though.
6
votes
Accepted
Action of fundamental group on homotopy fiber
(This answer is written in a model-independent fashion -- translate to your favourite formalism).
For every path $\gamma:[0,1]\to B$ you get an isomorphism in the homotopy category $X_{\gamma0}\xrigh …
9
votes
Accepted
Contractible chain complex from non-contractible space
These are known as acyclic spaces (note that since $\tilde C_*(X)$ is a bounded below complex of projectives, it being contractible is equivalent to its homology being trivial).
There's an extensive …
12
votes
Accepted
How to construct the Moore spectrum?
What you're missing is that $[\mathbb{S},\mathbb{S}]=\mathbb{Z}$. Let now $R$ be the infinite matrix of integers representing $\rho$. Note that since $\rho$ takes value in $\bigoplus_{I_1}\mathbb{Z}\s …
7
votes
Accepted
Morphisms from $bstring$ to $X\otimes \mathbb{Q}$ and sequences $s_n\in\pi_n(X)\otimes \math...
This is an assemblage of known results, I'll try to put a reference for all of them.
By a classical theorem of Serre all stable homotopy groups are finite in positive degree. In particular we have $ …
4
votes
Accepted
Higher categorical analogue of the equivalence between the category of representations of a ...
I think you made a sign mistake, and asked for a left adjoint to $\Omega^\infty$ since the monoid ring is a left along to the forgetful functor.
If so then the answer is yes. $\Sigma^\infty_+:\mathr …