Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 4213
31 votes

Which number fields are monogenic? and related questions

To add to Keith's answer, there are various classes of number fields which are known to be not monogenic. For instance, the following paper Marie-Nicole Gras, Non monogénéité de l'anneau des entiers …
j.c.'s user avatar
  • 13.6k
14 votes

Why is every quadratic subfield of a Galois extension of the rationals with the quaternions ...

To expand slightly my brief comment. Regard $L$ as a subfield of $\mathbb{C}$. Let $L'=\mathbb{R}\cap L$. Then the index $|L:L'|=1$ or $2$. In the former case all quadratic subfields of $L$ are real. …
Robin Chapman's user avatar
1 vote

Given an integer n and a finite extension K of Q , find a polynomial of degree n that is irr...

Your "$x^n-\alpha$" approach is the "ramified" way to go: the extension you get localizes to a totally ramified extension of the local field $K_{\mathfrak{p}}$, which has degree $n$, so the global ext …
Robin Chapman's user avatar
12 votes

Dirichlet's theorem for number fields

To expand on the excellent comments a bit, one needs both a bit more and a bit less than Chebotarev's density theorem. :-) Let's take a number field $K$, and a nonzero ideal $\mathfrak{N}$ of the rin …
Robin Chapman's user avatar
9 votes

number fields generated by units of number fields

The rank of the unit group of $K$ is $r+s-1$ where $r$ and $2s$ are the numbers of real and complex embeddings of $K$. As $r+2s=n$ this rank is less than $n=r+2s$, the degree of $K$. It follows that t …
Robin Chapman's user avatar