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The Riemann zeta function is the function of one complex variable $s$ defined by the series $\zeta(s) = \sum_{n \geq 1} \frac{1}{n^s}$ when $\operatorname{Re}(s)>1$. It admits a meromorphic continuation to $\mathbb{C}$ with only a simple pole at $1$. This function satisfies a functional equation relating the values at $s$ and $1-s$. This is the most simple example of an $L$-function and a central object of number theory.

6 votes
0 answers
264 views

Best explicit bound on $\zeta'(1+it)/\zeta(1+it)$

Assume the Riemann hypothesis. We know that $$\left|\frac{\zeta'(1+it)}{\zeta(1+it)}\right| \leq 2 \log \log t + O(1)$$ (see, e.g., Thm. 13.13 in Montgomery-Vaughan). What is the best explicit bound o …
H A Helfgott's user avatar
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3 votes
1 answer
173 views

Bounding the second moment of $|\zeta(\sigma+i t)|^2$ for $0<\sigma<1$

Let $$I(\sigma,T)=\int_0^T |\zeta(\sigma+ i t)|^2 dt.$$ Unconditional bounds and asymptotics for $I(\sigma,T)$, $1/2\leq \sigma <1$, have been known since Hardy and Littlewood (see Chapter 7 of Titchm …
H A Helfgott's user avatar
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2 votes
0 answers
139 views

Mean values of $\zeta(s)$ for $\Re(s)=1/2$ vs $\Re(s)\ne 1/2$

Say I have a good estimate for the $L^2$ mean of the Riemann zeta function $\zeta(s)$ for $\Re s = 1/2$, $|t|\leq T$: $$\int_0^T |\zeta(1/2+i t)|^2 = T \log T - T (1 + \log 2 \pi - 2\gamma) + O(T^\alp …
H A Helfgott's user avatar
  • 20.2k
4 votes
1 answer
319 views

Integrals involving $1/|\zeta(1+i t)|^2$: closed expressions?

Is there by any chance anything resembling a closed expression for, say, the integral $$I = \frac{1}{2 \pi} \int_{-\infty}^\infty \frac{dt}{|\zeta(1+i t)|^2 t^2} ?$$ It is easy to show (by Plancherel) …
H A Helfgott's user avatar
  • 20.2k
4 votes
1 answer
573 views

$\sum_{d\leq x} (\mu(d)/d) \log x/d$: elementary estimates?

Let $$F(x) = \sum_{d\leq x} \frac{\mu(d)}{d} \log \frac{x}{d}.$$ s it possible/feasible to give an elementary proof of the fact that $F(x)= 1 + o(1)$ (and, ideally, $1+O(1/\log x)$, or better)? By " …
H A Helfgott's user avatar
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7 votes
0 answers
171 views

Fully explicit version of Atkinson's formula?

Let $$I(T)=\int_0^T \left|\zeta\left(\frac{1}{2} + i t\right)\right|^2 dt$$ and let $E(T)$ be $I(T)$ minus what turn out to be its main terms: $$E(T) = I(T)- T \log \frac{T}{2 \pi} - (2 \gamma - 1) T. …
H A Helfgott's user avatar
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11 votes
1 answer
499 views

Second moment estimates for $\zeta(s)$: different methods?

What are some different ways to achieve the bound $$\int_0^T \left|\zeta\left(\frac{1}{2} + i t\right)\right|^2 dt = T \log \frac{T}{2 \pi} + (2 \gamma - 1) T + E(T)$$ with an error term $E(T) = O(T^{ …
H A Helfgott's user avatar
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8 votes
2 answers
948 views

Better trigonometrical inequalities for $\zeta(s)$?

The inequality $$3 + 4 \cos \theta + \cos 2 \theta \geq 0$$ plays a key role in the proof of the classical zero-free region of the Riemann zeta function. Are there other inequalities of the form $$\su …
H A Helfgott's user avatar
  • 20.2k
20 votes
4 answers
1k views

Bound on $L^2$ norm of $1/\zeta(1+i t)$?

What sort of bounds (explicit of preference) can one give for $$\int_T^{2 T} \frac{dt}{|\zeta(1+i t)|^2} \;\;\;\;\;?$$ Some obvious points: One can give a pointwise bound $\frac{1}{|\zeta(1+ it)|} \l …
H A Helfgott's user avatar
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9 votes
1 answer
584 views

Double sum of negative powers of integers: a direct approach?

Let $\alpha,\beta\in (0,1\rbrack$, $\alpha\ne \beta$. I wish to estimate $$\sum_{m\leq x} \frac{1}{m^\alpha} \sum_{n\leq x/m} \frac{\log(x/mn)}{n^\beta}.$$ There is an obvious approach, namely, to est …
H A Helfgott's user avatar
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8 votes
2 answers
754 views

$L_2$ bounds for tails of $\zeta(s)$ on a vertical line

Let $0<\sigma\leq 1$. Let $T$ be large. How can we give good explicit $L^2$ bounds on the tails of $\zeta(\sigma+it)$? That is, we want to bound the quantity $$\int_{\sigma-i\infty}^{\sigma-iT} + \int …
H A Helfgott's user avatar
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12 votes
0 answers
387 views

Computing Mertens' function in time O(sqrt(x)) - in practice

As far as I know, there is one way currently known to -- in principle -- compute the Mertens function $M(x) = \sum_{n\leq x} \mu(n)$ in time essentially $O\left(x^{1/2}\right)$, namely, a modification …
H A Helfgott's user avatar
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3 votes
0 answers
160 views

$\zeta(s) = \sum_{n\leq x} n^{-s} - x^{1-s}/(1-s) + ...$ through bounded-order Euler-Maclaurin?

It is a basic classical result (Titchmarsh Thm 4.11; credited to Hardy-Littlewood) that, uniformly for $\Re s \geq \sigma_0>0$, $t\leq 6 x$ (say), $$\zeta(s) = \sum_{n\leq x} \frac{1}{n^s} - \frac{x^{ …
H A Helfgott's user avatar
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4 votes
1 answer
321 views

$\zeta(s) = 1 + X^{1-s}/(s-1) + ...$?

Let $s = \sigma+ i t$ with $0\leq \sigma\leq 1$, $|t|\leq X$, where $1\leq X<2$. It is easy to use the Euler-Maclaurin formula to prove a result of the form $$\left|\zeta(s) - 1 - \frac{X^{1-s}}{s-1}\ …
H A Helfgott's user avatar
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3 votes
2 answers
366 views

Explicit bound on $\zeta(s)$ inside a zero-free region?

Does anybody know of a place in the literature where one can find an explicit result of the form $|\zeta(\sigma+it)|\leq C \log t$ for $t$ within a zero-free region (assuming $t$ is larger than an exp …
H A Helfgott's user avatar
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