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Hamiltonian systems, symplectic flows, classical integrable systems

5 votes
Accepted

Is there a relationship between the moduli space of spatial polygons and the moduli space of...

Yes. I assume that your $M_n$ is what is more usually denoted $\overline{M_{0,n}}$. Then the answer is yes, there is a natural map $\overline{M_{0,n}} \twoheadrightarrow M_L$, for each $L$. Specifica …
Allen Knutson's user avatar
3 votes
Accepted

Condition on moment polytope for a toric manifold to be Fano

The basic answer is "yes, of course, because the toric variety is uniquely determined by the polytope. But no, because it's the wrong polytope for the question of Fanoness." The question is whether t …
Allen Knutson's user avatar
4 votes
Accepted

Unique Equivariant Symplectic Structure for the Full Flag Manifold of $SU(3)$?

If $G$ acts on $M$ (both compact and finite-dimensional) preserving the symplectic form, and $M$ is simply-connected, the action is Hamiltonian. Then $M$ maps symplectomorphically to a coadjoint orbit …
Allen Knutson's user avatar
4 votes
Accepted

Moment maps and flat degenerations of toric varieties

I assume you mean that $T$ acts preserving each fiber. Then the flatness says that the multigraded Hilbert polynomial is constant. As the Duistermaat-Heckman measure is the leading-order behavior of t …
Allen Knutson's user avatar
4 votes
Accepted

Relation between volume of reduced space and phase space

Not a lot. Instead you should generalize $Vol(M)$, the pushforward of Liouville measure to a point, to $Vol_G(M)$, the pushforward along the moment map. I'll assume $G=T$ for convenience. The result i …
Allen Knutson's user avatar
8 votes
Accepted

How to find faces of polytope defined by a Weyl orbit

The faces are all of the following form: $w W_P / Stab_W(\xi)$, where $W_P$ varies over the subgroups generated by subsets of the simple reflections. In particular, for $\xi$ regular, the number of th …
Allen Knutson's user avatar
4 votes
Accepted

Coadjoint orbits and homogeneous symplectic $G$-manifolds

Certainly, if $G$ has a central extension, $G$ will act on the coadjoint orbits of the central extension. So I think your question might be "When can we be sure that our group has no central extension …
Allen Knutson's user avatar
9 votes
Accepted

Information from Moment Polytopes

Here's two natural things to ask about any compact group action on a compact manifold: (1) what are the (finitely many) conjugacy classes of stabilizer groups? Assume our group is a torus, so we can o …
Allen Knutson's user avatar
4 votes

Compact Kaehler manifolds that are isomorphic as symplectic manifolds but not as complex man...

If $M \to X$ is smooth and proper, and $M$ is K\"ahler, then the fibers are all symplectomorphic. (Proof: the Levi-Civita connection generates symplectomorphisms.) The family of elliptic curves was al …
Allen Knutson's user avatar
7 votes
Accepted

Non-Abelian Duistermaat-Heckman Measure (not just a reference request)

Hello again. Yes, it's true. The more general statement you want is, let $X$ be projective with a $K$-equivariant ample line bundle ${\mathcal O}(1)$. For each $n$, let $\mu_n$ be a measure on ${\ma …
Allen Knutson's user avatar
6 votes

Example in Guillemin-Sternberg's Convexity Paper

That particular example is about branching from $SO(5)$ to $SO(4)$. In general, the branching rule from $SO(n)$ to $SO(n-1)$ is multiplicity-free and well-known; it's in, e.g., Zhelobenko's book. So t …
Allen Knutson's user avatar
4 votes

What is a Lagrangian submanifold intuitively?

Since you've already gotten lots of classical mechanical answers, I'll give my favorite source of Lagrangians. Let $\sigma$ be a holomorphic section of a Hermitian line bundle $\mathcal L$ with curvat …
Allen Knutson's user avatar
3 votes

Why are the following varieties symplectomorphic?

Let $F\to E\to B$ be a smooth proper fibration over a connected manifold $B$, where the total space is symplectic and the fibers are smooth and symplectic. Then one can use Moser's theorem to generat …
Allen Knutson's user avatar
0 votes

Two versions of hamiltonian reduction

It depends on whether you think of the symplectic form as giving you a map $TX \to T^*X$ or vice versa. When you restrict to $\mu^{-1}(\chi)$, you only have a "presymplectic form", which gets you a ma …
Allen Knutson's user avatar
17 votes

Understanding moment maps and Lie brackets

I believe the following way (Kostant's, 1970) to be the best way to think about the Hamiltonian condition. First, "why" is there a central extension $H^0(M; {\mathbb R}) \to C^\infty (M) \to symp(M)$ …
Allen Knutson's user avatar

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