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Complex, contact, Riemannian, pseudo-Riemannian and Finsler geometry, relativity, gauge theory, global analysis.

34 votes
Accepted

Why "Classification" of 4 manifolds is NOT possible?

I'm guessing that you heard this from someone whose reasoning goes "Every finite presentation of a group can be made to give the $\pi_1$ of a smooth 4-manifold. If we could put any 4-manifold into the …
Allen Knutson's user avatar
5 votes

extension of Riemannian metric on real affine variety

I'm guessing that you mean that $X$ is a scheme defined over $\mathbb R$, with real points $X_{\mathbb R}$, and complex points $X_{\mathbb C}$ that you also denoted $X$. (I won't.) I'll assume that $ …
Allen Knutson's user avatar
5 votes

On the generalized Gauss-Bonnet theorem

Mathai and Quillen have a theorem that computes the Euler characteristic as an integral of a form defined using a section of and a connection on the tangent bundle. If one scales the section by a fact …
Allen Knutson's user avatar
6 votes

Fixed submanifold of G-manifold

As Mariano's comment indicates, you need more conditions. The usual one is that $G$ is a torus. Using $G$ compact, you can average a metric to get a $G$-invariant metric. Then the exponential map giv …
Allen Knutson's user avatar
18 votes
Accepted

Oriention-Reversing Diffeomorphisms of a Manifold

Such an endomorphism of $M$ gives an automorphism of the cohomology ring that acts by $-1$ on top cohomology. The cohomology ring of your example $M = {\mathbb C \mathbb P}^{2n}$ doesn't have such aut …
Allen Knutson's user avatar
4 votes

How should one present curl and divergence in an undergraduate multivariable calculus class?

I agree that it's very confusing that curl is again a vector field, and that there's this wacky determinant. I recommend doing the 2-d version, and "discovering" that curl is more naturally thought of …
Allen Knutson's user avatar
9 votes

Are the associative grassmannian and the quaternionic projective plane diffeomorphic?

To expand on Oscar's answer: the principal $SO(4)$ bundle over $G_2/SO(4)$ gives us $$ \qquad \qquad \qquad \ldots \to \pi_2(G_2) \to \pi_2(G_2/SO(4)) $$ $$ \to \pi_1(SO(4)) \to \pi_1(G_2) \to \pi_1(G …
Allen Knutson's user avatar
11 votes

Yang-Mills and Chern-Simons functionals as Morse functions

There's a generalization of Morse-Bott called Morse-Bott-Kirwan that you can read about in Kirwan's book. Basically this condition guarantees that the unstable sets are manifolds, but not the stable …
Allen Knutson's user avatar
3 votes

How can one show $G/T$ is a coadjoint orbit for a compact Lie group $G$ and $T$ its maximal ...

Use the Haar measure on $G$ (compact!) to average a metric, obtaining a $G\times G$-invariant metric, and thus an identification $\mathfrak g \cong \mathfrak g^*$. Also, the geodesic spray $\mathfrak …
Allen Knutson's user avatar
3 votes

Orientability of orbit type strata of Lie group actions

In your question, you may as well take $M=M_j=$ a ($G$-invariant) tubular neighborhood of a single orbit $G/S$. Near the point $S/S$, the space looks like $\mathfrak g/\mathfrak s \times N$, where $N$ …
Allen Knutson's user avatar
2 votes
Accepted

Moduli space of flat connections over a torus

Check out Almost commuting elements in compact Lie groups by Borel, Freedman, and Morgan. "We describe the components of the moduli space of conjugacy classes of commuting pairs and triples of elemen …
Allen Knutson's user avatar
10 votes
1 answer
409 views

Is there much theory of superalgebras acting on manifolds by alternating polyvector fields?

Usual story: vector fields on $M$, with their Lie bracket, form a Lie algebra. We can consider "actions" of some other Lie algebra ${\mathfrak g}$ on $M$ by looking at Lie homomorphisms ${\mathfrak g} …
Allen Knutson's user avatar
9 votes

Structure of Kähler cone

Flag manifolds $G/B$ are nice: the Kähler cone is the positive Weyl chamber, with edges coming from the Poincaré duals of the Schubert divisors.
Allen Knutson's user avatar
6 votes

Is it true that all sphere bundles are some double of disk bundle?

The connected double cover of $S^1$ (boundary of the Möbius strip) is an $S^0$ bundle that is not the double of the unique $0$-disc bundle over $S^1$.
Allen Knutson's user avatar
6 votes
Accepted

What is the Explicit Relationship between Coadjoint Orbits and Flag Manifolds?

Let $K$ be a maximal compact subgroup of $G$. Then $K$ acts transitively on each $G/P$, and up to $K$-isomorphism, the $K$-spaces obtained exactly match those occurring as coadjoint orbits of $K$ (act …
Allen Knutson's user avatar

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