Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with nt.number-theory
Search options not deleted
user 3634
Prime numbers, diophantine equations, diophantine approximations, analytic or algebraic number theory, arithmetic geometry, Galois theory, transcendental number theory, continued fractions
3
votes
Special cases of Dirichlet's theorem
I found this generalization of the "$3 \pmod{4}$" version while teaching number theory a few years ago.
Let $G$ be a proper subgroup of $(\mathbb{Z}/n)^\times$. Then there are infinitely many primes …
- 12.5k
11
votes
Collecting proofs that finite multiplicative subgroups of fields are cyclic
Lemma: Let $G$ be a finite abelian group, and let $x\in G$ with maximal order. Then for any other element of $y\in G$, $|y|$ divides $|x|$.
Proof. If not, then there is an element $y\in G$ and a pr …
3
votes
What arrangement of unit cubes minimizes surface area?
Here are some ideas about the related question: for fixed $k$, how many cubes can you arrange while keeping the surface area $\leq k$?
If the surface of an arrangement contains three or more sides …
- 12.5k
4
votes
The prime numbers modulo $k$, are not periodic
Suppose the primes are periodic mod $k$, and let $p$ be a prime divisor of $k$. Then there must be infinitely many primes of the form $p + nk$, which is divisible by $p$. Bad news.
EDIT:
More prec …
- 12.5k