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Homotopy theory, homological algebra, algebraic treatments of manifolds.
22
votes
to what extent does the category Cov(X) determine a topological space X?
If $X$ is a sober space, you can retrieve $X$ up to homeomorphism from $Cov(X)$. (Nitpick: this is not very good notation; it is very easy to misread it as the category of covering spaces over $X$. I …
5
votes
Accepted
A $G$-space as a coend
It doesn't seem to be true. Suppose we take $G = \{-1, 1\}$ with the discrete topology, acting on $X = \mathbb{R}$ by usual multiplication. Here $X^G$ consists of a single point $0$. The coend amounts …
14
votes
Comparisons of convenient categories for algebraic topology
From the nLab (although I was the author of these words):
A reasonably large class of examples, including the examples of compactly generated spaces and sequential spaces, is given in the article by …
11
votes
Accepted
is there a universal property that characterises the join of two categories?
It's a special case of what's called a collage or cograph construction. Recall that a profunctor or bimodule between categories $B$, $A$ is a functor $R: A^{op} \times B \to Set$. The cograph of $R$ i …
10
votes
Abelian groups as fundamental groups of topological groups
I'd like to add a quick little explanation to Georges's already sufficient answer (I'm sure this explanation is in Baez's post, but it can be said in a few lines here).
One of the morals of the famo …
43
votes
Accepted
Fundamental groups of topological groups.
Here is an example: a product of infinitely many $\mathbb{RP}^\infty$'s.
The crucial thing thing to see is that $\mathbb{RP}^\infty$ (or, easier to see, its universal cover $S^\infty$) has a group s …
9
votes
Cobordism categories that don't involve manifolds
Here is one type of example, basically inspired by the manifold-type examples but so general that they are not actually categories of manifolds. Let $B$ be any small category with finite coproducts, a …
3
votes
A topological groupoid structure on a pair $(X,A)$
Note: This answer had been sent to Ali in private email (the question had been closed while I was composing it). Now that the question has been reopened, the answer may be given here. (This has been e …
4
votes
Automorphisms of the rooted tree operad
I think the answer to the question as literally stated is "the trivial group", but I think there are related inquiries which get into some deep combinatorics.
One way of thinking about the rooted tr …
6
votes
Has this kind of question in topology a special name?
Perhaps the mapping class group of $X$? There is an extensive theory for mapping class groups and their computations. The mapping class group of the (2-dimensional) torus is $SL_2(\mathbb{Z})$.
7
votes
Accepted
Reference for Stasheff Operad
Why not look at Stasheff's original paper? He does give a point-set model (where $K_{n+2}$ is a compact convex semialgebraic subset of $\mathbb{R}^n$) and describes explicitly the substitution maps $\ …
3
votes
On the fundamental group of a finite CW complex
What Richard Kent said, although it probably deserves to be expanded on.
Suppose for simplicity that $X'$ is obtained from a CW complex $X$ by attaching an $n$-disk $D^n = \{x: |x| \leq 1\}$ along a …
13
votes
3
answers
704
views
Can a homotopy inverse of the map from a Lie group to loops on its classifying space be give...
Let $G$ be the compact Lie group $SO(n)$. There are some classical constructions of the classifying bundle of $G$ based upon on direct limits of Grassmann and Stiefel manifolds:
$$BG \simeq \underse …
10
votes
A canonical and categorical construction for geometric realization
As to "why is the unit interval the canonical interval?", there is an interesting universal property of the unit interval given in some observations of Freyd posted at the categories list, characteriz …
2
votes
Accepted
For a universal covering morphism $p:E\rightarrow B$, how to prove $E$ connected implies $B$...
Here is a general claim: in an extensive category $\mathbf{C}$, if $p: E \to B$ is an epimorphism and $E$ is connected (i.e., $\hom(E, -): \mathbf{C} \to \text{Set}$ preserves finite coproducts), then …