Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 26522

Abelian varieties are projective algebraic varieties endowed with an Abelian group structure. Over the complex numbers, they can be described as quotients of a vector space by a lattice of full rank. They are analogs in higher dimensions of elliptic curves, and play an important role in algebraic geometry and number theory.

12 votes
0 answers
428 views

Average ranks of abelian surfaces

Most people nowadays believe that over a fixed global field, $50$% of the elliptic curves have $0$ rank, $50$% have rank $1$, and $0$% have higher rank. A significant advance in this direction has bee …
Vesselin Dimitrov's user avatar
12 votes
1 answer
587 views

The torsion point count in higher dimension

It is an easy consequence of the Serre open image theorem that for the torsion point count on elliptic curves, the following possibilities arise. If $E/\bar{\mathbb{Q}}$ is an elliptic curve without …
Vesselin Dimitrov's user avatar
11 votes
Accepted

Nakai-Moishezon theorem for abelian varieties

On an abelian variety (regardless of the characteristic), an effective divisor with positive self-intersection is ample. To be more precise, it suffices here to recall that on any simple abelian varie …
Vesselin Dimitrov's user avatar
11 votes
0 answers
373 views

What are the possible bad reductions for an abelian variety of dimension $g$ and a maximal e...

Perhaps the most basic fact about abelian varieties with CM is they have an everywhere potential good reduction (Serre-Tate). On the face of it it might appear that there isn't much more to be added t …
Vesselin Dimitrov's user avatar
8 votes
0 answers
502 views

Points of minimum Arakelov height and harmonic arithmetical varieties

Added. (28/2) To put it less pompously (and more vaguely, less concretely), I wanted to relate the impression that it is the general rule that an Arakelov (i.e., geometric) height on an arithmetical v …
4 votes
Accepted

Orders of reductions of rational points on elliptic curves

For example, is it known that there is an infinite sequence of rational primes $p_i$ and primes $P_i$ of (the ring of integers of) $K$ such that $p_i$ divides the order of the reduction of $x$ modu …
Vesselin Dimitrov's user avatar
3 votes
0 answers
271 views

The uniform boundedness of rational torsion for traceless abelian surfaces over a function f...

The function field analog of the theorem of Mazur-Kamienny-Merel (giving a universal bound in $[K:\mathbb{Q}]$ for the size of the $K$-rational torsion of an elliptic curve) is immediate just from the …
Vesselin Dimitrov's user avatar
2 votes

Purely additive reduction of Jacobian of Hyperelliptic curve

It is all about the $g$-cuspidal singularity $y^2 = x^{2g+1}$ of the special fibre, and how this singularity affects the Picard group in terms of the Picard group of the normalization (which is an abe …
Vesselin Dimitrov's user avatar
2 votes
0 answers
160 views

Must the coordinates of a polynomial iteration have about the same size?

Original post. The following statements seem plausible (not to say intuitively obvious), but I do not see how to prove them. Let us say that a polynomial mapping of $\mathbb{C}^2$ is reducible if ei …
Vesselin Dimitrov's user avatar
2 votes
1 answer
369 views

Is the canonical height of a totally p-adic point on an abelian variety bounded away from zero?

Inspired by the result of Schinzel and Smyth that a totally real number other than $0$ and $\pm 1$ has height at least $\frac{1}{2}\log \Big( \frac{1+\sqrt{5}}{2} \Big) = 0.240659\ldots$, Bombieri and …
Vesselin Dimitrov's user avatar