Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options answers only not deleted user 25510

Questions about dimensions of possibly highly irregular or "rough" sets, Hausdorff–Besicovitch dimension and related concepts such as box-counting or Minkowski–Bouligand dimension.

6 votes
Accepted

Hausdorff dimension of convex set in ${\bf R}^n$

Yes. The boundary even has a locally finite Haudsorff $(m-1)$-measure. No. A convex function of 1 variable has increasing derivative, but this derivative can have a dense set of jumps. In general, …
Alexandre Eremenko's user avatar
5 votes

Plane curve with continuously increasing Hausdorff dimension

I do not have a reference but can propose a proof of Proposition 1 which is independent of and simpler than Proposition 2. Let us first construct a non-closed curve, namely a graph of a convex functi …
Alexandre Eremenko's user avatar
3 votes

Hausdorff dimension of Julia sets of quadratics not in the Mandelbrot set.

At some points of the boundary of M, the Hausdorff dimension is not continuous, these are points of "parabolic implosion", see MR2521938.
Alexandre Eremenko's user avatar
2 votes

Hausdorff measure of the zero set

Yes, it is true. If the zero set has Hausdorff dimension $<n-1$ then almost every line in the direction of a coordinate axis will not intersect the set. This easily follows from the definition of the …
Alexandre Eremenko's user avatar
0 votes

Fractal questions: Weierstraß-Mandelbrot

The word "fractal" has no established commonly accepted definition. (Some definitions involve self-similarity, others only Hausdorff dimension). You should specify what exactly you mean by Weierstra …
Alexandre Eremenko's user avatar