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For questions about matchings in graph theory. A matching on a graph is a set of edges such that no two edges share a common vertex.

19 votes

Is there a version of König's theorem for tripartite 3-graphs?

This is a special case of Ryser's Conjecture, which states that in an $r$-partite, $r$-uniform hypergraph (with $r>1$) $\tau \leq (r-1) \nu$, where $\tau$ is the size of a minimum cover and $\ …
Tony Huynh's user avatar
  • 32.1k
15 votes

Are all almost regular graphs obvious?

Here is an expansion of joro's answer. Claim. $K_{n, n+1}$ is obvious if and only if $n+1$ is even. Proof. If $n+1$ is even, we can add a perfect matching on the vertices on the right to obtain a …
Tony Huynh's user avatar
  • 32.1k
13 votes
Accepted

Maximum matching in a graph with no "shortcuts"

Yes, your conjecture is true, even without the assumption that $G$ does not contain shortcuts. The following proof is due to Sam Fiorini. Proof. Let $P \subseteq \mathbb{R}^{E(G^\star)}$ be the mat …
Tony Huynh's user avatar
  • 32.1k
13 votes
Accepted

Berge-Fulkerson conjecture --- the planar case

The Berge-Fulkerson conjecture holds for planar graphs. Here is a proof. Let $G$ be a bridgeless cubic planar graph. The dual graph $G^*$ is a triangulation. By the Four Colour Theorem, $G^*$ has a …
Tony Huynh's user avatar
  • 32.1k
11 votes

An analysis proof of the Hall marriage theorem

As requested in the comments, there is a standard proof of Hall's Marriage Theorem from the max-flow min-cut theorem. Let $G$ be a bipartite graph satisfying Hall's condition, with bipartition $(A,B) …
Tony Huynh's user avatar
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10 votes
Accepted

Are all numbers from $1$ to $n!$ the number of perfect matchings of some bipartite graph?

No. For all $n \geq 3$, there is no $G \in \mathcal{G}_{2n}$ with $f(G)=n!-1$. To see this, note that $f(K_{n,n})=n!$ and $f(K_{n,n}-e)=n!-(n-1)!$, where $K_{n,n}-e$ is $K_{n,n}$ minus an edge. Thu …
Tony Huynh's user avatar
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10 votes

Number of matchings of even cycles

Here is a bijective proof. Label the vertices of $C_{2n}$ as $1, 2, \dots, n, 1', 2', \dots, n'$ in clockwise order and let $M$ be a matching of size $k<n$ in $C_{2n}$. Since $M$ is not a perfect mat …
Tony Huynh's user avatar
  • 32.1k
8 votes

Maximum number of perfect matchings in a planar graph?

An old conjecture of Lovász and Plummer is that for every cubic graph $G$ with no cut-edge, the number of perfect matchings in $G$ is exponential in the number of vertices. Chudnovsky and Seymour pro …
Tony Huynh's user avatar
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7 votes
Accepted

A graph $G$ with two $K_6$ subgraphs, in which any one-factor of $G$ induces a one-factor in...

Here is a proof that $G$ does not exist. Let $M_1$ be a (red) 1-factor which contains a 1-factor $M_1'$ of the first $K_6$, and $M_2$ be a (blue) 1-factor which contains a 1-factor $M_2'$ of the seco …
Tony Huynh's user avatar
  • 32.1k
5 votes

Maximum matchings in infinite graphs

No, this is not possible. Here is an elaboration of Eric Wofsey's comment. Suppose it is possible and let $M$ be a maximal (under inclusion) matching of $G$ (this exists by Zorn's lemma). Then $| …
Tony Huynh's user avatar
  • 32.1k
5 votes
Accepted

Clutters with no maximum-size matchings

Yes, this is possible. For each prime $p$ and $c \in \{0,1, \dots, p-1\}$ let $A_{c,p}=\{c+kp \mid k \in \mathbb{Z}\}$. Clearly, the set of all $A_{c,p}$ is a clutter $\mathcal C$ with ground set $\ …
Tony Huynh's user avatar
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4 votes
Accepted

Stable marriages for infinite bipartite graphs

Your formal version does not look correct. For each boy $b$, there should be a total order $\leq_b$ on the set of girls $G$ (this is the preference order for $b$) and for each girl $g$, there should …
Tony Huynh's user avatar
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4 votes

Expanding Hall's theorem

Let $G$ be a bipartite graph with bipartition $(L,R)$. A necessary and sufficient condition for each vertex on the left to be matched to two vertices on the right is $|N_G(X)| \geq 2|X|$ for all $X \ …
Tony Huynh's user avatar
  • 32.1k
4 votes

How many perfect matchings in a regular bipartite graph?

In the case that $2d$ divides $n$, one can take $G$ to be $\frac{n}{2d}$ disjoint copies of $K_{d,d}$. This graph has $(d!)^{n/2d}$ perfect matchings, and as Gjergji's answer shows, this is the worst …
Tony Huynh's user avatar
  • 32.1k
4 votes
Accepted

2-approximation algorithm for Minimum Maximal Matching (MMM) problem

There is an easy $2$-approximation algorithm for finding a minimum size maximal matching. Simply find any maximal matching. Note that a maximal matching $M$ can be found greedily. Initialize $M=\em …
Tony Huynh's user avatar
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