Search Results
Search type | Search syntax |
---|---|
Tags | [tag] |
Exact | "words here" |
Author |
user:1234 user:me (yours) |
Score |
score:3 (3+) score:0 (none) |
Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
Views | views:250 |
Code | code:"if (foo != bar)" |
Sections |
title:apples body:"apples oranges" |
URL | url:"*.example.com" |
Saves | in:saves |
Status |
closed:yes duplicate:no migrated:no wiki:no |
Types |
is:question is:answer |
Exclude |
-[tag] -apples |
For more details on advanced search visit our help page |
For questions about matchings in graph theory. A matching on a graph is a set of edges such that no two edges share a common vertex.
19
votes
Is there a version of König's theorem for tripartite 3-graphs?
This is a special case of Ryser's Conjecture, which states that in
an $r$-partite, $r$-uniform hypergraph (with $r>1$)
$\tau \leq (r-1) \nu$,
where $\tau$ is the size of a minimum cover and $\ …
15
votes
Are all almost regular graphs obvious?
Here is an expansion of joro's answer.
Claim.
$K_{n, n+1}$ is obvious if and only if $n+1$ is even.
Proof. If $n+1$ is even, we can add a perfect matching on the vertices on the right to obtain a …
13
votes
Accepted
Maximum matching in a graph with no "shortcuts"
Yes, your conjecture is true, even without the assumption that $G$ does not contain shortcuts. The following proof is due to Sam Fiorini.
Proof. Let $P \subseteq \mathbb{R}^{E(G^\star)}$ be the mat …
13
votes
Accepted
Berge-Fulkerson conjecture --- the planar case
The Berge-Fulkerson conjecture holds for planar graphs. Here is a proof.
Let $G$ be a bridgeless cubic planar graph. The dual graph $G^*$ is a triangulation. By the Four Colour Theorem, $G^*$ has a …
11
votes
An analysis proof of the Hall marriage theorem
As requested in the comments, there is a standard proof of Hall's Marriage Theorem from the max-flow min-cut theorem. Let $G$ be a bipartite graph satisfying Hall's condition, with bipartition $(A,B) …
10
votes
Accepted
Are all numbers from $1$ to $n!$ the number of perfect matchings of some bipartite graph?
No. For all $n \geq 3$, there is no $G \in \mathcal{G}_{2n}$ with $f(G)=n!-1$. To see this, note that $f(K_{n,n})=n!$ and $f(K_{n,n}-e)=n!-(n-1)!$, where $K_{n,n}-e$ is $K_{n,n}$ minus an edge. Thu …
10
votes
Number of matchings of even cycles
Here is a bijective proof.
Label the vertices of $C_{2n}$ as $1, 2, \dots, n, 1', 2', \dots, n'$ in clockwise order and let $M$ be a matching of size $k<n$ in $C_{2n}$. Since $M$ is not a perfect mat …
8
votes
Maximum number of perfect matchings in a planar graph?
An old conjecture of Lovász and Plummer is that for every cubic graph $G$ with no cut-edge, the number of perfect matchings in $G$ is exponential in the number of vertices. Chudnovsky and Seymour pro …
7
votes
Accepted
A graph $G$ with two $K_6$ subgraphs, in which any one-factor of $G$ induces a one-factor in...
Here is a proof that $G$ does not exist. Let $M_1$ be a (red) 1-factor which contains a 1-factor $M_1'$ of the first $K_6$, and $M_2$ be a (blue) 1-factor which contains a 1-factor $M_2'$ of the seco …
5
votes
Maximum matchings in infinite graphs
No, this is not possible. Here is an elaboration of Eric Wofsey's comment.
Suppose it is possible and let $M$ be a maximal (under inclusion) matching of $G$ (this exists by Zorn's lemma). Then $| …
5
votes
Accepted
Clutters with no maximum-size matchings
Yes, this is possible. For each prime $p$ and $c \in \{0,1, \dots, p-1\}$ let $A_{c,p}=\{c+kp \mid k \in \mathbb{Z}\}$. Clearly, the set of all $A_{c,p}$ is a clutter $\mathcal C$ with ground set $\ …
4
votes
Accepted
Stable marriages for infinite bipartite graphs
Your formal version does not look correct. For each boy $b$, there should be a total order $\leq_b$ on the set of girls $G$ (this is the preference order for $b$) and for each girl $g$, there should …
4
votes
Expanding Hall's theorem
Let $G$ be a bipartite graph with bipartition $(L,R)$. A necessary and sufficient condition for each vertex on the left to be matched to two vertices on the right is $|N_G(X)| \geq 2|X|$ for all $X \ …
4
votes
How many perfect matchings in a regular bipartite graph?
In the case that $2d$ divides $n$, one can take $G$ to be $\frac{n}{2d}$ disjoint copies of $K_{d,d}$. This graph has $(d!)^{n/2d}$ perfect matchings, and as Gjergji's answer shows, this is the worst …
4
votes
Accepted
2-approximation algorithm for Minimum Maximal Matching (MMM) problem
There is an easy $2$-approximation algorithm for finding a minimum size maximal matching. Simply find any maximal matching. Note that a maximal matching $M$ can be found greedily. Initialize $M=\em …