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A C*-algebra is a complex Banach algebra together with an isometric antilinear involution satisfying (a b)* = b* a* and the C*-identity ‖a* a‖ = ‖a‖². Related tags: [banach-algebras], [von-neumann-algebras], [operator-algebras], [spectral-theory].

5 votes

unitization-process of unital- and non-unital $C^*$-algebras

The question is already answer but there is a point I want to add: Some time ago I wrote a paper about the Gelfand duality for non-unital algebra within constructive mathematics, my proof goes throug …
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1 vote
Accepted

Certain groupoid and its $C^{*}$ algebra

I will explain how I ended up with the description given in my comment above. Let $\{1, \dots ,n \}$ be your finite subset of $\mathbb{R}$ (only their order is important, we do not really care about …
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3 votes

$C^*$-algebra which is not von Neumann, but satisfies the property that ever self-adjoint el...

Every monotone closed $C^*$-algebras has this property. And they are not all von-Neumann algebras. Although the counter-exemple are rather enormous objects. In fact as commutative sub-algebra of $AW^ …
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5 votes

Relation between norm of any element of $C^*$-algebra in terms of self adjoint elements

The norm of the self adjoint part is not sufficient: Even if $b$ and $c$ commutes (which should be the easiest case) then it corresponds (by looking at the commutative algebra generated by $b$ and $c$ …
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10 votes

Is this a functor on the category of $C^{*}$ algebras?

This paper proves that there is no functor from the category of C* algebra (and morphisms) to the category of locales/topological spaces/a lot of other things that extend the gelfand duality and send …
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4 votes
0 answers
134 views

References for a lemma about compact operators on a Hilbert module

I am looking for a reference for the following result: If $A$ and $B$ are C* algebras, $H$ is a right Hilbert $A$-modules, $\phi :A \rightarrow B$ is a morphism, and assume that there is a map $\eta …
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1 vote
Accepted

On the second dual of $C[0,1]$

It is easy to see that $\int \psi d\delta_t$ where $\delta_t$ is the Dirac mass at $t$ is $\psi(\{t\})$ So you are starting from a $T \in C([0,1])^{**}$ and you are attaching to it the function $t \m …
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2 votes

C*-bimodules: the mess with definitions

As far as I'm concerned $C^*$ bimodules generally denote those you attributed to A.Connes. Such a bi-module define (by tensorization over B) a functor from $B$ $C^*$-modules to $A$ $C^*$-modules. Any …
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4 votes

A Possible characterization of F.D or AF commutative $C^{*}$ algebras

I don't know what are the motivation for the formulaton in terms of $C^*$ algebras, but you are essentially asking for hausdorff compact/locally compact spaces such all their compact/locally compact q …
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2 votes

Comparision of two $C^{*}$ algebras associated to a non vanishing vector field on a compact ...

It depends if you use the monodromy groupoid or the holonomy groupoid (Is there a more canonical choice for this construction ? ). Basically, the monodromy groupoid is exactly the same as the action …
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8 votes
Accepted

How the modular theory of von Neumann algebras, deal with generating C*-algebras?

All groups algebra are trivial examples because for them the modular time evolution is (can be chosen) trivial: the modular time evolution attached to a state is trivial if and only if the state is a …
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5 votes
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Counterexample to Riesz representation for Hilbert modules

Take $A= \mathcal{C}([0,1])$ and $H$ the ideal of $A$ of functions that vanish at $0$. $H$ is a Hilbert $A$ module (as any ideal, with the natural multiplication of $A$ and the scalar product $(x,y)= …
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10 votes
Accepted

A C*-algebra enjoying some different C*-norms

No that's not possible (except the trivial case). Any $*$-homomorphism between $C^*$-algebras is automatically contractive, and if it is injective then it is isometric. You can apply this to the ident …
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2 votes
1 answer
220 views

Non-perfect type one C^*-algebra, and a lemma in Fourier analysis

I would like to know if the following is true : Let $\mathcal{H}$ be the complex Hilbert space $L^2([0,1])$ for the Lebesgue measure. Let $q$ be the orthogonal projection on the subspace of $\mathcal{ …
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4 votes

Noncommutative version of Littlewood's First Principle

Here is one half of an answer, but it was too long for a comment. I'll edit if I manage to finish it... When you have a $C^*$ algebra $C$ included in a von Neumann algebra $B$ ( and you might want to …
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