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The Laplacian matrix is the representation of a graph in matrix form.

3 votes

Courant nodal domain Theorem for sums of eigenfunctions?

On a Riemann surface $\Sigma$, consider the space $H_\lambda$ spanned by eiigenfunctions corresponding to eigenvalues $\leq \lambda$. By Weyl's asymptotic formula we know that $$ \dim H_\lambda \s …
Liviu Nicolaescu's user avatar
14 votes
Accepted

Closed formula for heat kernel

Yes there is. Here is how you do it. First find an orthogonal change in variables $$ x_j=\sum_{jk} s_{jk}y_k $$ $(s_{jk})$ orthogonal matrix, so that in the new coordinates we have $$ \sum_{i, …
Liviu Nicolaescu's user avatar
4 votes

High multiplicity eigenvalue implies symmetry?

Suppose that $(M,g)$ is a compact Riemann manifold and for any positive integer $N$ there exists an eigenvalue of the Laplacian that has multiplicity $>N$. …
Liviu Nicolaescu's user avatar
4 votes

Why should the map $-\Delta^{-1}$ be continuous?

The Laplacian defines an isomorphism $\Delta E\to H^{-1}$ with inverse $\Delta^{-1}$. …
Liviu Nicolaescu's user avatar
4 votes

Explicit eigenvalues of the Laplacian

In principle, one can compute the spectrum of any homogeneous compact Riemannian manifold because in this case the problem is essentially representation theoretic. However, performing this computation …
Liviu Nicolaescu's user avatar
8 votes
Accepted

laplace equation on manifolds with boundary

The most common boundary conditions in the case of Laplacian are the Dirichlet and the Neumann conditions. The only tricky part in the case with boundary is regularity along the boundary. …
Liviu Nicolaescu's user avatar
3 votes

Criteria for Positivity of Pseudoddifferential Operators on Manifolds

If $A$ is a symmetric partial differential operator of order $2k$ on a compact manifold whose principal symbol is positive definite, then for $\lambda\gg 0$ the operator $A+\lambda$ is positive d …
Liviu Nicolaescu's user avatar
5 votes

Exotic spectrum of Laplace operator

For a generic metric on an $m$-dimensional the manifold the eigenvalues of the Laplacian are all simple. …
Liviu Nicolaescu's user avatar