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The Laplacian matrix is the representation of a graph in matrix form.
3
votes
Courant nodal domain Theorem for sums of eigenfunctions?
On a Riemann surface $\Sigma$, consider the space $H_\lambda$ spanned by eiigenfunctions corresponding to eigenvalues $\leq \lambda$. By Weyl's asymptotic formula we know that
$$ \dim H_\lambda \s …
14
votes
Accepted
Closed formula for heat kernel
Yes there is. Here is how you do it. First find an orthogonal change in variables
$$ x_j=\sum_{jk} s_{jk}y_k $$
$(s_{jk})$ orthogonal matrix, so that in the new coordinates we have
$$ \sum_{i, …
4
votes
High multiplicity eigenvalue implies symmetry?
Suppose that $(M,g)$ is a compact Riemann manifold and for any positive integer $N$ there exists an eigenvalue of the Laplacian that has multiplicity $>N$. …
4
votes
Why should the map $-\Delta^{-1}$ be continuous?
The Laplacian defines an isomorphism $\Delta E\to H^{-1}$ with inverse $\Delta^{-1}$. …
4
votes
Explicit eigenvalues of the Laplacian
In principle, one can compute the spectrum of any homogeneous compact Riemannian manifold because in this case the problem is essentially representation theoretic. However, performing this computation …
8
votes
Accepted
laplace equation on manifolds with boundary
The most common boundary conditions in the case of Laplacian are the Dirichlet and the Neumann conditions.
The only tricky part in the case with boundary is regularity along the boundary. …
3
votes
Criteria for Positivity of Pseudoddifferential Operators on Manifolds
If $A$ is a symmetric partial differential operator of order $2k$ on a compact manifold whose principal symbol is positive definite, then for $\lambda\gg 0$ the operator $A+\lambda$ is positive d …
5
votes
Exotic spectrum of Laplace operator
For a generic metric on an $m$-dimensional the manifold the eigenvalues of the Laplacian are all simple. …