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Non-commutative rings and algebras, non-associative algebras, universal algebra and lattice theory, linear algebra, semigroups. For questions specific to commutative algebra (that is, rings that are assumed both associative and commutative), rather use the tag ac.commutative-algebra.

1 vote
2 answers
229 views

Invertibility of all left multiplication maps in non-unital rings

Suppose that $R$ is a ring, not necessarily commutative nor associative. Assume that for every non-zero $a \in R$, the left multiplication map $$ \lambda_a \colon R \to R \colon x \mapsto ax $$ is inv …
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2 votes

Tits-Kantor-Koecher construction for Jordan algebra of symmetric bilinear form

This is contained in Jacobson's Blue Book (Structure and Representations of Jordan Algebras, AMS Colloquium Publications, 1968), as Exercise 1 on p. 342, for arbitrary fields, and with no assumptions …
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2 votes

polarization/linearization as in jordan forms

The principle of polarizing is given by what you wrote yourself in the third paragraph. If $p$ is a homogeneous polynomial of degree $n$, then: The clearest formulation is to take $p(x+ \lambda y) …
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4 votes

Group representation with algebra structure

A classification is too much to hope for, but the representation theory tells you whether such an algebra structure can exist: if $V$ is your $G$-representation, then an algebra product corresponds to …
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3 votes
2 answers
919 views

Skew fields inside quaternion division algebras

Suppose that $Q$ is a quaternion division algebra with center $k$, where $k$ is an arbitrary commutative field (let's say with $\operatorname{char}(k) \neq 2$ if necessary). Assume that $D$ is an arbi …
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7 votes

An algebra map between Hopf algebras that does not commute with the counit

Such a map can certainly exist. For instance, take the $k$-algebra $G = k \times k$, with $$ \begin{aligned} &\Delta(1,0) = (1,0) \otimes (1,0) + (0,1) \otimes (0,1), \\ &\Delta(0,1) = (1,0) \otimes ( …
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12 votes

Simplest examples of rings that are not isomorphic to their opposites

Here is an explicit example of a central simple algebra over $\mathbb{Q}$ not isomorphic to its opposite (which is merely a detailed example of what Pete explained). First take a cubic cyclic Galois …
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18 votes
4 answers
2k views

For which rings $R$ is $\mathrm{SL}_n(R)$ generated by transvections?

Let $R$ be a commutative ring $R$ with $1$, and $n \geq 2$ an integer. Under which conditions is the group $\operatorname{SL}_n(R)$ generated by transvections? (A transvection is a matrix with $1$ e …
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12 votes
Accepted

For which rings $R$ is $\mathrm{SL}_n(R)$ generated by transvections?

I'm answering my own question based on the excellent reference given by Max and the additional comments of Jim Humphreys. There is nothing new in my answer, but I think it's useful to close the questi …
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6 votes
Accepted

Chirality of octonion algebras

Perhaps this is more a question about the Fano plane than about the (real) octonions. Notice that the automorphism group of the Fano plane is the simple group $\operatorname{GL}(3, \mathbb{F}_2) \cong …
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12 votes
1 answer
1k views

Divisibility and factorization in rings that are not integral domains

In my course notes for an undergraduate course "Algebra I", I wrote at the point when I'm introducing the notion of divisibility in rings (in a section on unique factorization): We want to study f …
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12 votes

Applications of Jordan algebras

They turn up quite often in the study of (exceptional) linear algebraic groups. The most famous instance of this is the fact that algebraic groups of type $F_4$ are precisely the automorphism groups o …
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3 votes
1 answer
303 views

ABA-product of matrices and length of chains of principal inner ideals

Let $k$ be a field, $p,q$ positive integers, and let $R$ be the space of $(p \times q)$-matrices over $k$, and $S$ be the space of $(q \times p)$-matrices over $k$. For every matrix $A \in R$, we defi …
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6 votes

Cayley-Dickson form of a quaternion

I believe there is a good reason why mathematicians don't use the terminology "simplex-part" and "perplex-part": they are not canonical! Indeed, algebraically there is no way to distinguish the elemen …
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16 votes

vector to diagonal matrix

I'm not sure whether it answers your question, but here is a "matrix procedure" to transform the column vector $v$ into a diagonal matrix $D$: Let $E_i$ be the $n \times n$ matrix with a $1$ on posit …
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