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Questions about the branch of algebra that deals with groups.

11 votes
1 answer
262 views

Example of three dimensional atoroidal Poincaré duality group with some pathology

I am looking for a 3-manifold which is closed, aspherical, orientable, and atoroidal. And additionally I want to see an example that does not admit a fixed-point-free action on a simplicial tree. As a …
Peter Kropholler's user avatar
5 votes

A torsionfree group with infinite cohomological dimension and no infinitely generated free a...

Ian Agol's answer is complete and achieves more than is required. It is perhaps worth pointing out that if you just want an example that meets the Title Criteria you can take $G$ to be the free produc …
Peter Kropholler's user avatar
12 votes
1 answer
390 views

What is the least $n\ge1$ for which there is an $n$-dimensional closed flat manifold with pe...

In answer to the question "Is there a flat manifold with trivial first homology?" I proposed choosing a finite perfect group $P$ and a surjection $\phi:F\to P$ where $F$ is a free group of finite rank …
Peter Kropholler's user avatar
8 votes
0 answers
249 views

In search of a quick proof that groups acting freely on $\mathbb R$-trees are linear

Many years ago I had the idea to use non-standard analysis to prove that a group acting freely on an $\mathbb R$-tree must be linear. The heuristic went like this: A non-standard model $G^*$ of the g …
Peter Kropholler's user avatar
5 votes
0 answers
160 views

Cohomology of a countable directed union of groups

It's puzzled me for a long time why two arguments in group cohomology look connected but no immediate visible connection is available. First, it is a theorem that if a group $G$ is the union of a chai …
Peter Kropholler's user avatar
7 votes

Is there a flat manifold with trivial first homology?

Here is an idea for making examples. Let $F$ be a free group and let $N$ be a normal subgroup of $F$. Then $F/[N,N]$ is torsion-free. To see this, suppose $w\in F$ has finite order modulo $[N,N]$, and …
Peter Kropholler's user avatar
1 vote

In Galois theory, why solvable groups must have their quotient groups be Abelian?

A solvable group is, by definition, a group with a finite series of normal subgroups such that the successive factor groups are abelian. It is the content of the Fundamental Theorem of Galois Theory t …
Peter Kropholler's user avatar
6 votes

Group extensions with non-abelian kernel

There is an account of the general theory of group extensions with non-abelian kernel in Gruenberg's Springer Lecture Notes 143, Cohomological Topics in Group Theory: here he refers to his own paper ' …
Peter Kropholler's user avatar
12 votes
1 answer
427 views

Group extensions with non-abelian kernel

If $N$ is a normal subgroup of $G$ then there is a coupling: that is, a representation of $G/N$ in $\operatorname{Out}(N)$. In that case, the extensions of $N$ by $G/N$ affording the same coupling are …
Peter Kropholler's user avatar
6 votes
0 answers
206 views

Amenable groups with all subgroups finitely generated

Does anyone know an example of an amenable group with all subgroups finitely generated that is not elementary amenable?
Peter Kropholler's user avatar