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A generating function is a way of encoding an infinite sequence of numbers by treating them as the coefficients of a formal power series. Tag questions involving generating functions in this.
7
votes
0
answers
139
views
A differential equation and recurrence related to P-partitions
I am interested in polynomials $G_n(z)$ defined by the recurrence
$$G_{n+1}(z) - 2G_n(z) + (1-nz)G_{n-1}(z)=0$$
for $n\ge1$ with the initial values $G_0(z) = 1$ and $G_1(z) = 1$.
The next few values a …
5
votes
5 different ways to define the same family of integer sequences
Here is a proof that $a_1(n, p, q) = a_2(n,p,q)$.
The generating function for the Stirling numbers of the second kind is
$$\sum_{n=i}^\infty {n\brace i}\frac{x^n}{n!}= \frac{(e^x-1)^i}{i!}.$$
Also
$$\ …
11
votes
Accepted
Reference request: Gessel interview's generating function identities
Result 1 can be found in N. G. de Bruijn, Asymptotic Methods in Analysis, Dover, New York, 1981, p. 71.
Result 2 follows from a formula of E. M. Wright, though he didn't state it in this form. A discu …
4
votes
Accepted
$R$-recursion for the A307389
Let
\begin{equation*}
A(x,q) = e^{qx}A(x)=e^{(q+1)x+(e^x-1)^2/2}
\end{equation*}
and define $a(n,q)$ by
\begin{equation*}
A(x,q) = \sum_{n=0}^\infty a(n,q) \frac{x^n}{n!}.
\end{equation*}
Then $a(n,0) …
4
votes
Accepted
General case of the some $R$-recursions
Let
$$
A(x,q)=\sum_{i=0}^{\infty}\frac{x^i}{\prod\limits_{j=0}^{i}(1-f(q+j)x)},
$$
so that $A(x) = A(x,0)$. Define $a(n,q)$ by
$$A(x,q) = \sum_{n=0}^\infty a(n,q) x^n,$$
so that $a(n) = a(n,0)$.
I wil …
0
votes
Second order recurrence relation for third order polynomial root
Here's a sketch of a proof, using Lagrange inversion, of the equation $(27x^2/4-1)F^3+3F-2=0$, where
$$F(x) = \sum_{n=0}^\infty \binom{3n/2}{n}x^n.$$
One form of Lagrange inversion says that if $h(x) …
5
votes
Accepted
Representing PSET as species
See Gilbert Labelle, On asymmetric structures, Discrete Math. 99 (1992), 141–164.
12
votes
Series involving power of the index
There are many ways to prove the formula
$$ \sum_{n=1}^{\infty} \frac{n^{n-1}}{n!}(xe^{-x})^n = x.\tag{1}$$
As Alexandre Eremenko noted, one approach is Lagrange inversion.
Another can be found at htt …
6
votes
Accepted
Tanglegrams and functional equations of M. Somos
In my lecture slides that Tewodros cites, I studied symmetric functions that I called $g_m$, where $m$ is a positive integer, that have constant term 1 and satisfy
$$ -L_m[g_m] = p_1,$$
where $L_m$ is …
4
votes
Accepted
$0,1$-matrices with $1$ in every row/column vs. all $0,1$-matrices
If you multiply both sides by $e^{x+y}$ there's a simple bijective proof: In a nutshell, every 0-1 matrix consists of a matrix with a 1 in every row and column together with some all-zero rows and col …
2
votes
Accepted
Closed form for odd part of Bernoulli Polynomial generating function, $\sum_{k=0}^{\infty}B_...
Using Pietro Majer's bisection formula we find by a straightforward computation (I did it with Maple, but I'm sure it could be done without too much difficulty by hand) that the OP's formula for
$$\su …
5
votes
What alternatives are there to the binomial poset theory of generating function families?
For Bender and Goldman's theory of prefabs, see http://www.iumj.indiana.edu/docs/20060/20060.asp.
Michael Henle's theory of dissects
is introduced in Dissection of generating functions,
Studies in App …
40
votes
The "square root" of a graph?
These numbers count balanced signed graphs (without loops). A signed graph is a graph in which every edge has a sign, either positive or negative. It is balanced if every cycle has an even number of n …
6
votes
The number of permutations of given order
The exponential generating function for permutations of order dividing $k$ is
$$\exp\biggl(\sum_{d\mid k} \frac{x^d}{d}\biggr).$$
See, e.g., L. Moser and M. Wyman, On solutions of $x^d = 1$ in symmetr …
4
votes
A special type of generating function for Fibonacci
I started writing this before Richard's answer appeared, with which it overlaps a lot, but I still have something to add.
Let us look at a more general problem: Suppose that $G(x) = 1+g_1x+g_2x^2+\cd …