Skip to main content

All Questions

Filter by
Sorted by
Tagged with
5 votes
0 answers
114 views

Extreme no loop conjecture for group algebras

Let $A=KG$ be a group algebra for a finite group $G$. Let $S$ be a simple $A$-module. The extreme no loop conjecture predicts that $Ext_A^1(S,S) \neq 0$ implies $Ext_A^i(S,S) \neq 0$ for infinitely ...
2 votes
1 answer
97 views

When is $N^{*} \otimes_K M$ projective for a local Hopf algebra?

Given a finite dimensional local Hopf algebra $A$ over a field $K$ and two finite dimensional indecomposable modules $N$ and $M$. Is it known when the module $N^{*} \otimes_K M$ is projective? Can ...
4 votes
0 answers
69 views

Auslander-Solberg algebras from non-rigid modules

Let $A$ be a Nakayama algebra and $M$ be the direct sum of all indecomposable $A$-modules $N$ with $Ext_A^1(N,N) \neq 0$. The following is suggested by computer experiments with QPA: Question: Is ...
2 votes
1 answer
169 views

Combinatorial problem on periodic dyck paths from homological algebra

edit: I added conjecture 2 that looks much more accessible. Here is the elementary combinatorial translation of the problem (read below for the homological background): Let $n \geq 2$. A Nakayama ...
2 votes
0 answers
51 views

Selfinjective algebras with loops

Given a selfinjective finite dimensional algebra $A$ with an indecomposable module $M$ with $Ext_A^1(M,M) \neq 0$. Question: Is A derived equivalent to an algebra with a loop in the quiver in ...
2 votes
0 answers
53 views

Strong no loop conjecture for uniserial modules

Let $A$ be a an Artin algebra. The strong no loop conjecture states that a simple $A$-module with $Ext_A^1(S,S) \neq 0$ has infinite projective dimension. This conjecture was recently proved for ...
2 votes
0 answers
45 views

On monomial and $\Omega^d$-finite algebras

Let $Q$ be a finite quiver and $I$ a monomial admissible ideal of the path algebra $KQ$ for a field $K$. Then an algebra $A=KQ/I$ is called a monomial algebra. It is well known that monomial algebras ...
1 vote
0 answers
55 views

$\mathrm{Ext}^1$-ordering on ${}^IW^{\Sigma_\mu}$

Let $\mathfrak{g}$ be a finite dimensional complex semisimple Lie algebra with Cartan subalgebra $\mathfrak{h}$. Let $W$ be the associated Weyl group and let $\Phi$ be its root system. We write $\Phi^+...
4 votes
1 answer
149 views

Testing whether a module generates $K_0(\mbox{mod-}A)$

Given a representation-finite (connected) quiver algebra $A$ and a module $M$. Is there a good way to test whether the set $\{ [N] \mid N \in \mathrm{add}(M) \}$ generates $K_0(\mbox{mod-}A)$? Can ...
4 votes
0 answers
82 views

On strongly simply connected quiver algebras

Let $A$ be a representation-finite quiver algebra. In this case $A$ is simply connected if and only if its first Hochschild cohomology vanishes by a result of Buchweitz and Liu. $A$ is called strongly ...
2 votes
0 answers
69 views

Stable m-Calabi Yau property for Frobenius categories

Let $C$ be a Frobenius category. The stable category $\underline{C}$ is called $m$-Calabi Yau in case it is Hom-finite and there is a functorial duality $D \underline{Hom}(X,Y)=\underline{Hom}(Y,\...
2 votes
0 answers
73 views

Equivalence from a tilting module

Let $A$ be a finite dimensional algebra. For a subcategory $C$ of $mod-A$ let $\overline{C}$ be the objects $X \in mod-A$ such that there exists an exact sequence $0 \rightarrow C_n \rightarrow ... \...
2 votes
0 answers
56 views

Characterisation of representation-directed algebras

A representation-directed algebra $A$ over a field $K$ has the property that for every indecomposable module $M$ we have $\mathrm{End}_A(M) \cong K$ and $\mathrm{Ext}_A^i(M,M)=0$ for all $i>0$. ...
16 votes
2 answers
694 views

How complicated can a finite double complex over a field be?

A finite complex over a field $k$ is pretty simple: it's the direct sum of its homology with a split-exact complex. How complicated can a finite double complex be? Does it make a difference if $k$ is ...
4 votes
0 answers
88 views

Minimal injective coresolution in the stable Auslander algebra

Let $A$ be a finite dimensional (connected) quiver algebra. Let $T(A)$ denote the full subcategory of coherent functors from $mod-A$ to $Ab$ that vanish on projective objects. $T(A)$ is equivalent to ...
5 votes
0 answers
140 views

Open problems about Morita and derived invariants

Are there properties of rings of which one does not know whether they are Morita or derived invariances? For a recent such example for Morita invariance, see https://www.sciencedirect.com/science/...
3 votes
0 answers
48 views

Endomorphism ring of a generator-cogenerator over acyclic algebras

Let $A$ be an acyclic quiver algebra, $M$ a generator-cogenerator and $B=End_A(M)$. Questions: Does $B$ have finite global dimension? Does $B$ have finite global dimension in case $M=A \oplus D(A)$? ...
4 votes
0 answers
58 views

Interpretation of stable Hom in Nakayama algebras

Let $A$ be a Nakayama algebra with Kupisch series $[c_0,c_1,...,c_{n-1}]$ and Jacobson radical $J$ (given by quiver and relations). As is well known every indecomposable $A$-module is of the form $e_i ...
9 votes
0 answers
123 views

Cartan determinant of stable categories

Let $A$ be a finite dimensional algebra with finitely many indecomposable non-projective modules $M_1, M_2,...,M_n$. Let $a_{i,j}:=\dim(\underline{Hom_A}(M_j,M_i))$ (the dimension of the stable Homs ...
5 votes
0 answers
91 views

Bound on the sum of projective and injective dimension

Recall that a finite dimensional algebra is called piecewise hereditary in case it is derived equivalent to an abelian hereditary category. In proposition 1.2. of https://link.springer.com/article/10....
6 votes
1 answer
204 views

On the injective dimension of $A$ as a bimodule

(Note: I modified the question and instead of looking at simple modules in the question, I look at all indecomposable modules.) Let $A$ be a finite dimensional algebra over a field $K$ given by an ...
8 votes
2 answers
1k views

When is the exterior algebra a Hopf algebra?

I have several questions on the exterior algebra of a vector space: Q1:When has the exterior algebra A (viewed just as an algebra, not considered as a graded algebra) of an $n$-dimensional vector ...
5 votes
1 answer
186 views

(Stable) Auslander algebras in a specific example

Let $k$ be a field and $Q$ be the quiver with two vertices 1 and 2 and three arrows: $a$ from 2 to 1, $b$ from 2 to 1 and $c$ from 2 to 2. Let $I_1=\langle ab-c^2,ba\rangle$ and $I_2=\langle ab-c^2,c^...
5 votes
0 answers
125 views

Stable equivalence and stable Auslander algebras

Let $A$ be a representation-finite finite dimensional quiver algebra and $M$ the basic direct sum of all indecomposable $A$-modules. Recall that the Auslander algebra of $A$ is $End_A(M)$ and the ...
3 votes
0 answers
427 views

When is the stable category abelian

For which Artin algebras $A$ is the stable module (that is the module category modulo projectives) category of finitely generated modules abelian? If you like you may take rings that are not Artin ...
2 votes
1 answer
203 views

Proving indecomposability of special modules

I'm reading the following paper: http://math0.bnu.edu.cn/~huwei/paper/Holm-Hu-1.pdf On page 795 and 796 there are the definitions (in a diagrammatical way) of some $A_n$ modules, whereupon $A_n:=k[x,...
2 votes
0 answers
60 views

$\Omega$-periodic modules in selfinjective algebras

Given a representation infinite (connected) selfinjective algebra $A$ with an indecomposable $\Omega$-periodic module $M$. Does $A$ then have infinitely many indecomposable $\Omega$-periodic ...
2 votes
0 answers
65 views

Constructing stable equivalences for finite dimensional algebras

Given a finite dimensional (non-selfinjective) algebra $A$. Is there a method (for example using QPA) to construct algebras stable equivalent to $A$? Such a thing is easily possible for derived ...
4 votes
0 answers
85 views

Deciding whether two algebras are derived equivalent

Given two finite dimensional quiver algebras $A$ and $B$ (over a nice field in case that helps, for example a finite field). Question: Can an there be a finite algorithm that decides whether $A$ ...
4 votes
0 answers
43 views

Cartan determinants of minimal Auslander-Gorenstein algebras

Iyama and Solberg introduced minimal Auslander-Gorenstein algebras as algebras having finite dominant dimension ($\geq 2$) equal to the Goreinstein dimension in https://www.sciencedirect.com/science/...
4 votes
4 answers
596 views

Homology of solvable (nilpotent) Lie algebras

Let $\mathfrak{g}$ be a solvable Lie algebra over $\mathbb{C}$ and $\lambda\in(\mathfrak{g}/[\mathfrak{g},\mathfrak{g}])^*$ be a character of $\mathfrak{g}$. I'm interested in calculating homology for ...
3 votes
0 answers
106 views

Bounds for the finitistic dimension

The finitistic dimension of an algebra is defined as the supremum of all projective dimensions of modules having finite projective dimension. For finite dimensional algebras $A$ with radical cube ...
4 votes
0 answers
71 views

Koszul and quadratic algebras with Gorenstein dimension 2

In proposition 2.19. of http://inmabb.criba.edu.ar/revuma/pdf/v48n2/v48n2a05.pdf it was mentioned that a finite dimensional algebra of global dimension 2 is quadratic if and only if it is Koszul. ...
3 votes
0 answers
61 views

Number of algebras stably equivalent to a given algebra

For $n \geq 2$ let $B_n$ be the algebra of upper triangular matrices over a field $K$. Recall that two algebras are said to be stably equivalent in case their module categories modulo projectives are ...
3 votes
0 answers
96 views

When is the category of complexes of finite type?

For a ring $R$ define the category of complexes of length $n \geq 2$ as the category $C_n(R)$ with objects the complexes of the form $0 \rightarrow X_n \rightarrow \cdots X_1 \rightarrow 0$ with the ...
4 votes
2 answers
453 views

Global dimension of the tensor algebra

Let $R$ be a semisimple ring with a non-zero $R$-bimodule V. Let $T_R(V):= \bigoplus\limits_{k=0}^{\infty}{V^{\otimes_k}}$ be the tensor algebra of $V$. Question 1: Is there a simple proof that $...
7 votes
1 answer
462 views

On a problem for determinants associated to Cartan matrices of certain algebras

This is a continuation of Classification of algebras of finite global dimension via determinants of certain 0-1-matrices but this time with a concrete conjecture and using the simplification suggested ...
7 votes
0 answers
266 views

Closed formula for some dimension

This question has a background from representation theory/homological algebra, but I state everything in elementary terms here: Call an n-CNak an n-tupel $[c_0,c_1,...,c_{n-1}]$ where $c_0=c_1=...=c_{...
6 votes
1 answer
689 views

Tensor product of bimodules

Im not sure whether this question is appropriate for MO, but I do not have much experience with bimodules (or I forgot many things). Let $A$ be a finite dimensional (connected) algebra over a field $...
11 votes
2 answers
558 views

Classification of algebras of finite global dimension via determinants of certain 0-1-matrices

I restrict to the elementary problem that is equivalent to give a classification when Morita-Nakayama algebras have finite global dimension (see the end of this post for some background). A Morita-...
2 votes
0 answers
69 views

Do the values of the global dimension constitute an interval?

Let $Q$ be a fixed finite connected quiver and $k$ a fixed field. Set $Z_Q:= \{ gldim(kQ/I) < \infty | I $ an admissible ideal $\}$. Question: Is $Z_Q$ an intervall? This is true for example in ...
6 votes
2 answers
269 views

Derived invariance of the Cartan determinant

The Cartan matrix $C$ of a finite quiver algebra $A$ with points $e_i$ is defined as the matrix having entries $c_{i,j}=\dim(e_i A e_j)$. The Cartan determinant is defined as the determinant of the ...
4 votes
0 answers
98 views

Bound for the global dimension of higher Auslander algebras

Let algebras be finite dimensional and connected. Recall that an algebra $A$ is called a higher Auslander algebra in case it the dominant dimension coincides with the global dimension and both ...
7 votes
1 answer
370 views

Gorenstein symmetric conjecture for arbitrary rings

The Gorenstein symmetric conjecture states that for Artin algebras $A$ one has the the regular module has finite injective dimension as a right module if and only if it has finite injective dimension ...
4 votes
1 answer
159 views

Question on $n$-regular modules

Let $A$ be finite dimensional connected algebra. A simple module $S$ is called $n$-regular in case $pd(S)=n$, $Ext_A^i(S,A)=0$ for $i=0,1,...,n-1$ and $Ext_A^n(S,A)$ being a simple $A$-left module. ...
4 votes
0 answers
66 views

Periodic modules in Frobenius algebras

Let $A$ be a finite dimensional Frobenius algebra and assume there exists an indecomposable periodic module $M$, that is $\Omega^n(M) \cong M$ for some $n$. Question: Does this imply that there is ...
1 vote
0 answers
57 views

Modules with arbitrary large complexity

Let $A$ be a finite dimensional algebra with a module $M$ who has minimal injective coresolution $(I_i)$. Define the complexity $cx(M)$ as $cx(M):= \inf \{ t \geq 0 | \dim(I_i) \leq a i^{t-1}$ for all ...
2 votes
0 answers
29 views

Complexity of the regular module

Let $A$ be a finite dimensional algebra with a module $M$ who has minimal injective coresolution $(I_i)$. Define the complexity $cx(M)$ as $cx(M):= \inf \{ t \geq 0 | \dim(I_i) \leq a i^{t-1}$ for all ...
3 votes
0 answers
156 views

Weak generators of the right-bounded derived category of a finite-dimensional algebra

The setup: Let $A$ be a finite-dimensional $k$-algebra over some field $k$. Let $\mathcal{B} = Hot^-(Proj \, A)$ denote the homotopy category of cochain complexes of (possibly infinitely generated) ...
3 votes
0 answers
134 views

Proving that the exterior algebra is symmetric via the polynomial ring

Recall that a finite dimensional algebra $A$ over a field $K$ is called Frobenius in case $A \cong D(A)$ as right modules, and it is called symmetric in case $A \cong D(A)$ as bimodules (where $D=...

1
3 4
5
6 7
10