4
$\begingroup$

Let $A$ be a finite dimensional Frobenius algebra and assume there exists an indecomposable periodic module $M$, that is $\Omega^n(M) \cong M$ for some $n$.

Question: Does this imply that there is an indecomposable periodic module $N$ that is a submodule of $A$?

$\endgroup$

0

You must log in to answer this question.

Browse other questions tagged .