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5 votes
0 answers
146 views

Is every linear Lie group of bounded geometry?

$\newcommand\norm[1]{\lVert#1\rVert}$Given any point $p$ of a smooth Riemannian manifold $M$ there exists $r\in (0,\infty]$ such that the Riemannian exponential is a diffeomorphism in the geodesic ...
Marco's user avatar
  • 293
3 votes
1 answer
203 views

Free $S^1$-action on compact homogeneous spaces

Let $M = G/K$ be a compact homogeneous space, i.e. $G$ a connected compact Lie group, and $K$ a closed subgroup inside $G$ that contains no nontrivial normal subgroup of $G$. If $r(G) > r(K)$ (...
abracadabra12345's user avatar
1 vote
0 answers
196 views

Homogeneous metrics on compact Lie groups

Given a differentiable manifold $M$, a Riemannian metric $g$ on $M$ is called homogeneous if its isometry group acts transitively on $M$. In that case, given any group $G$ acting transtitively on $(M,...
emiliocba's user avatar
  • 2,446
2 votes
2 answers
213 views

Riemannian homogeneous equivalent to linear group orbit

Let $ M $ be a smooth manifold. Recall that a manifold $ M $ is smooth homogeneous if there exists a Lie group acting transitively on $ M $. Recall that a manifold $ M $ is Riemannian homogeneous if ...
Ian Gershon Teixeira's user avatar
8 votes
1 answer
610 views

Are invariant forms on homogeneous spaces necessarily closed?

Take a compact homogeneous space $G/K$, and a left $G$-invariant differential $k$-form $\omega \in \Omega^k(G/K)$. Will $\omega$ necessarily be closed? Might it even be harmonic when $G/K$ is endowed ...
Quin Appleby's user avatar
1 vote
0 answers
517 views

Horizontal lift of fundamental vector field

Suppose $\theta\colon G\times M\to M$ is a transitive smooth left action of a compact Lie group $G$ on a manifold $M$ and $\pi\colon G\to M\cong G/K$ the corresponding smooth submersion for some ...
Sven Pistre's user avatar
4 votes
3 answers
862 views

Is every homogeneous space Riemannian homogeneous?

A manifold $M$ together with a transitive $G$-action is always diffeomorphic a quotient $G/H$ for $H < G$ Lie groups. On the other hand, there might be a proper subgroup of $G$ that also acts ...
Lezkus's user avatar
  • 177
5 votes
1 answer
549 views

Volume of balls in homogeneous manifolds

Let $X=G/H$ be a homogeneous manifold, where $G$ and $H$ are connected Lie groups and assume there is given a $G$-invariant Riemannian metric on $X$. Let $B(R)$ be the closed ball of radius $R>0$ ...
user avatar
3 votes
0 answers
154 views

Classification of Euclidian-like Klein geometries in spirit of Erlangen program

All we know about Erlangen Program approach to geometry. The main idea is to consider Lie Group $G$ acting transitively on smooth manifold $M$ (e.g. nLab). I really like such style of thinking, but ...
Mykola Pochekai's user avatar
7 votes
3 answers
1k views

Is the group of isometries of a homogeneous Riemannian manifold maximal?

I have a homogeneous Riemannian manifold X with isometry group Iso. Is Iso a maximal group? By maximal group, I mean that there does not exist another group G such that: Iso is a proper subgroup of G,...
Adam's user avatar
  • 71
2 votes
1 answer
484 views

Sobolev norm of distance function on Riemannian manifold

$\DeclareMathOperator\SL{SL}$Suppose $M$ is a Riemannian manifold with distance function $d:M\times M \rightarrow [0,\infty)$. If it helps let $M$ be a Lie group with finite Haar measure $\mu$ and ...
Florek's user avatar
  • 23