A manifold $M$ together with a transitive $G$-action is always diffeomorphic a quotient $G/H$ for $H < G$ Lie groups. On the other hand, there might be a proper subgroup of $G$ that also acts transitively on $M$, so this representation may not be unique.

If $H$ is compact, we may choose a metric on $G$ that descends into $G/H$ and makes it into a Riemannian homogeneous space, that is, we may choose a metric on $M \cong G/H$ such that the action is by isometries.

Is it always possible to choose a representation of a homogeneous space as a quotient of Lie groups $G/H$ such that $H$ is a compact Lie group? Or in other words, given a manifold $M$ with a transitive $G$-action, is there always a $G'$-action with $G' \leq G$ such that the isotropy group is compact?

Riemannian homogeneous spaces are in particular reductive, so this would imply that every homogeneous space has a representation as a reductive quotient. I have read that this is a non-trivial condition for homogeneous spaces, so this makes me think that this may not be true, but I have never seen an explicit counterexample either.

On matrix Lie groups one has that every connected Lie algebra closed under transposes is reductive, so I am assuming that the counterexamples may not be very nice-looking?