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5 votes
0 answers
158 views

If $\omega_1$ is not inaccessible in $L$, how hard can it be to find a non-measurable $\Sigma^1_3$ set of reals?

In his wonderfully titled paper Can you take Solovay's inaccessible away? Shelah showed that if every $\mathbf{\Sigma}^1_3$ set of reals is Lebesgue measurable, then $\omega_1$ is an inaccessible ...
James E Hanson's user avatar
2 votes
1 answer
161 views

Are Cohen Generics Minimal Covers?

Are Cohen generics (in $2^\omega$) minimal covers? I'm ultimately interested in this question for some more effective notion of forcing but I realized I wasn't sure how to show this even assuming full ...
Peter Gerdes's user avatar
  • 3,029
2 votes
0 answers
118 views

Uniformization and functions on Turing degrees

Assuming Martin's Conjecture on functions between Turing degrees, is AD + DC consistent with existence of an $f:\mathcal{D}_t → \mathcal{D}_t$ of rank $Θ$ ? $\mathcal{D}_t$ is the set of Turing ...
Dmytro Taranovsky's user avatar
4 votes
3 answers
406 views

Hyperarithmetically least elements in $\Pi^1_1$ sets

My question is: Do we have a hyperarithmetically $\le_H$-least real in any $\Pi^1_1$ set? That is Question. Suppose that $A$ is a non-empty $\Pi^1_1$ set. Then can we find a real $a\in A$ such that $...
Hanul Jeon's user avatar
  • 3,042
6 votes
0 answers
117 views

Reverse mathematics of Banach-Mazur games

Given $\mathcal{A}\subseteq\omega^\omega$, the Banach-Mazur game with payoff set $\mathcal{A}$ consists of players $1$ and $2$ alternately playing nonempty finite strings of naturals with player $1$ ...
Noah Schweber's user avatar
6 votes
0 answers
151 views

Complexity of constructive arithmetical truth vs second order arithmetic

Let us say that an arithmetic statement is constructively true iff it is realized by a computable function under Kleene's function realizability. Does the set of constructively true (first order) ...
Dmytro Taranovsky's user avatar
3 votes
0 answers
203 views

Set-theoretic hierarchy using the uniqueness quantification

Has an equivalent of the set-theoretic hierarchies (arithmetical, hyperarithmetical, Levy etc.) that uses the uniqueness quantification, $\exists !$ (and its dual, $\neg\exists!\neg$) been studied ...
Johan's user avatar
  • 531
5 votes
0 answers
291 views

What is known about when regularity properties only hold for partial boldface pointclasses?

Apologies in advance for a rather vague and open-ended question. Results about regularity properties of the projective pointclasses tend to have a wholesale flavor. By this I mean one tends to be ...
Jason Zesheng Chen's user avatar
7 votes
0 answers
304 views

Which countable ordinals are "Barwise compact" for $\mathcal{L}_{\infty,\omega_1}$?

Barwise compactness says (as a special case) that whenever $\alpha$ is countable and admissible, $T\subseteq\mathcal{L}_{\infty,\omega}\cap L_\alpha$ is $\alpha$-c.e., and every subset of $T$ which is ...
Noah Schweber's user avatar
7 votes
0 answers
471 views

Infinite time Turing machines, semi-decidable sets and descriptive set theory

Definition A set of reals $A$ is said to be ittm-eventually-semi-decidable if there is an Infinite Time Turing Machine programme $P_e$ so that $x\in A$ iff $P_e(x)$ has converged on “1” on its ...
Philip Welch's user avatar
  • 4,839
3 votes
0 answers
223 views

Bimodal determinacy logic for Borel games

This question is intended to be a first step towards answering this old question of mine. Let $K$ be the set of pairs $(\Sigma,\Pi)$ of quasistrategies, in the usual sense of games on $\omega$, for ...
Noah Schweber's user avatar
2 votes
0 answers
258 views

Can we have a "very strong" cone phenomenon in the Turing degrees (and a related question)?

By Borel determinacy + Martin's cone theorem, for every countable fragment $\mathcal{A}$ of $\mathcal{L}_{\omega_1,\omega}$ there is a turing degree ${\bf c}$ such that for all ${\bf d}\ge_T{\bf c}$ ...
Noah Schweber's user avatar
14 votes
1 answer
1k views

Descriptive set theory for computer scientists?

It seems to me that there are scattered references of deep relationships between descriptive set theory and computability theory. For one, the relationship between the Borel hierarchy and the ...
Siddharth Bhat's user avatar
8 votes
1 answer
514 views

How big is the least non-$\Sigma^1_1$-pointwise-definable ordinal?

There's a large countable ordinal which has cropped up (as a lower bound!) in a computable structure theory problem I'm playing with. At present I don't really understand how big it is, and I'm ...
Noah Schweber's user avatar
9 votes
1 answer
495 views

Can two versions of $\omega_1^{CK}(\mathsf{Ord})$ ever coincide?

The goal of this question is to fill in the gap in this old answer of mine. For a transitive set $M$, thought of as an $\{\in\}$-structure, we define the following ordinals (this is not the notation ...
Noah Schweber's user avatar
4 votes
0 answers
177 views

When is validity definable in $L_\alpha$?

Below, $\alpha$ is a countable p.r.-closed ordinal $>\omega$. Let $\mathcal{L}_\alpha=\mathcal{L}_{\infty,\omega}\cap L_\alpha$ (note that this is not the same as $\mathcal{L}_{\omega_1,\omega}\...
Noah Schweber's user avatar
2 votes
1 answer
207 views

The measure of ideals generated by random reals

We assume that for every real $x$, $L[x]$ only contains countably many reals. Given a set $X$ of reals, then $L$-ideal generated by $X$ is the smallest set $I$ of reals so that For any reals $x\in ...
喻 良's user avatar
  • 4,201
7 votes
1 answer
490 views

"Robinson arithmetic" for (some) levels of $L$?

I'll write "$\mathcal{L}_\alpha$" for the fragment $\mathcal{L}_{\infty,\omega}\cap L_\alpha$. Say that a countable admissible $\alpha$ is Robinsonian if there is some sentence $\varphi\in\mathcal{L}...
Noah Schweber's user avatar
6 votes
1 answer
503 views

Regularity properties of Turing-invariant and arbitrary sets of reals

The question whether Turing determinacy implies $AD$ is a well-known open problem. I was wondering if anything is known about the following analogous question: Let $\Gamma$ be a regularity property (...
Haim's user avatar
  • 391
5 votes
0 answers
196 views

A slight extension of Sacks theorem

Sacks proves the following theorem first. Theorem 1: If $\alpha$ is a countable admissible ordinal, then there is a real $x$ so that $\omega_1^x=\alpha$. Anyone knows who proves the following ...
喻 良's user avatar
  • 4,201
6 votes
0 answers
806 views

A strong plus-one hypothesis

To make this more easily readable, I'll start with the question and then give the explanation/motivation. Question. Is the following principle (or its weakening, with "for every real $r$" ...
Noah Schweber's user avatar
7 votes
0 answers
284 views

Co-cones in the Turing degrees

Let the cocone of a Turing degree ${\bf d}$ be the set $cc({\bf d}):\{{\bf c}: {\bf c}\not\ge_T {\bf d}\}$. I'm curious what's known about the various partial orders (isomorphic to ones) of the form $...
Noah Schweber's user avatar
31 votes
2 answers
2k views

How (non-)computable is set theory?

Here is a naive outsiders perspective on set theory: A typical set-theoretical result involves constructing new models of set theory from given ones (typically with different theories for the original ...
Arno's user avatar
  • 4,717
9 votes
1 answer
739 views

Can the Turing degrees be linearly ordered?

Assuming the axiom of choice, every set can be linearly (indeed, well-) ordered. However, without choice this can fail, as witnessed most drastically by the consistency of amorphous sets. More ...
Noah Schweber's user avatar
15 votes
1 answer
616 views

Does Kechris' conjecture contradict both parts of Martin's conjecture, or just part 1?

By Kechris' conjecture (KC) I mean the assertion that Turing equivalence $\equiv_T$ is a universal countable Borel equivalence relation. On the other hand, Martin's conjecture (MC) is a long-lasting ...
V. Bard's user avatar
  • 151
8 votes
0 answers
451 views

The cone property in the enumeration degrees

A Borel partial order is the partial order corresponding to a Borel preorder of some Polish space. For example, the Turing and enumeration degrees, $\mathcal{D}$ and $\mathcal{E}$ respectively, are ...
Noah Schweber's user avatar
8 votes
1 answer
432 views

Which reals are "hyperarithmetic modulo ordinals"?

The context for this question is the theory ZFC + a measurable cardinal, although answers not in this context would also be interesting to me. In a project I'm working on, the following class of ...
Noah Schweber's user avatar
9 votes
0 answers
471 views

(A little bit) Beyond the E-recursive

The E-recursive functions are a particular generalization of classical recursion theory to the entire set-theoretic universe, $V$. They are defined via a schemes: see Sacks' $E$-recursive intuitions. ...
Noah Schweber's user avatar
14 votes
2 answers
719 views

Woodin on Posner-Robinson for the hyperjump and sharp

The Posner-Robinson theorem states that, if $X$ is noncomputable, there is some $G$ such that $X\oplus G=G'$; that is, even though genuine jump inversion only works above $0'$, every (nontrivial) $X$ ...
Noah Schweber's user avatar
10 votes
1 answer
411 views

The least admissible above a dominating real

Let $\mathbb{P}$ be the usual forcing which adds a dominating real: conditions in $\mathbb{P}$ are pairs $(p, f)$ with $p:\omega\rightarrow\omega$ finite partial and $f:\omega\rightarrow\omega$ total, ...
Noah Schweber's user avatar
7 votes
2 answers
657 views

Topological tameness beyond the Gandy-Harrington topology

The Gandy-Harrington topology on $\omega^\omega$ is the topology generated by all lightface $\Sigma^1_1$ sets; that is, all sets which are continuous-in-the-usual-sense images of $\omega^\omega$. ...
Noah Schweber's user avatar
14 votes
2 answers
1k views

Does Turing determinacy imply full determinacy?

The axiom of Turing determinacy is a weakening of the full axiom of determinacy, $AD$, in which only games with payoff sets which are $\equiv_T$-invariant are demanded to be determined. In "...
Noah Schweber's user avatar
11 votes
1 answer
441 views

Concerning Silver's result

Jack Silver proved that if $x$ is a real so that every $x$-admissible ordinal is a cardinal in $L$, then $0^{\sharp}$ exists. I wonder whether various weaker or stronger versions of Silver's result ...
喻 良's user avatar
  • 4,201
4 votes
1 answer
572 views

Definition of HYP in $L_{\omega_1^{CK}}[a]$?

The structure $L_{\omega_1^{CK}}$ consists of only HYP sets (I believe) and HYP in this structure is the same as the actual hyperaritmetic sets. Now if I move to the structure $L_{\omega_1^{CK}}[a]$ ...
Peter Gerdes's user avatar
  • 3,029
6 votes
0 answers
248 views

$\omega$-models of $\mathbf{\Sigma^1_1}-DC$ and $\mathbf{\Delta^1_1}-CA$

So what is needed to demonstrate something (say like $L_{\omega_1^{CK}}[a]$ is a $\omega$-models of $\mathbf{\Sigma^1_1}$-$DC$ or $\mathbf{\Delta^1_1}$-$CA$? It's not like I don't understand what the ...
Peter Gerdes's user avatar
  • 3,029
5 votes
1 answer
284 views

Companion of the pointclass of inductive sets

This question is about the notion of a companion for a Spector class, as defined in Moschovakis's book Elementary Induction on Abstract Structures. I am interested in Spector classes on $\mathbb{R}$, ...
Trevor Wilson's user avatar
5 votes
2 answers
656 views

Is the Turing equivalence relation the orbit equiv. relation of the action of a countable group?

The Turing equivalence relation on $\cal P(\mathbb{N})$ is defined by $A\equiv_T B$ iff $A\leq_T B$ and $B\leq_T A$. This is a countable Borel equivalence relation on the polish space $\cal P(\mathbb{...
Francis Adams's user avatar
5 votes
1 answer
878 views

Countable admissible ordinals

Jensen claimed that for any finite increasing sequence countable admissible ordinals $\omega= \alpha_0<\alpha_1\cdots <\alpha_n$, there is a real $x$ so that, for each $m\leq n$, $\alpha_m$ is ...
喻 良's user avatar
  • 4,201
5 votes
1 answer
416 views

Higher computability : Constructive ordinal and $\Delta^1_1$ predicates

Everything I know on this subject comes from Sacks book : "Higher recursion theory" Let $\mathcal{O^Y}$ be the set of codes for ordinals constructive in $Y$. We should have the result that $A \...
Archimondain's user avatar