All Questions
7 questions
0
votes
0
answers
80
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Minimizing coefficients in a product related to the Rogers Ramanujan identity
Start with the product for partitions into parts congruent to $1$ or $4$ modulo $5$:
$(1 + x + x^2 + x^3 + ...)(1 + x^4 + x^8 + x^{12} +...)(1 + x^6 + x^{12} + x^{18} +...)$...
Now replace some of the ...
- 4,589
19
votes
3
answers
1k
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The sum of integers being a bijection
What are the pairs $(P,Q)$ of subsets of $\mathbb N$ for which the map
\begin{eqnarray*}
P\times Q & \rightarrow & {\mathbb N} \\\\
(p,q) & \mapsto & p+q
\end{eqnarray*}
is a bijection ...
- 52.3k
29
votes
0
answers
1k
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Linking formulas by Euler, Pólya, Nekrasov-Okounkov
Consider the formal product
$$F(t,x,z):=\prod_{j=0}^{\infty}(1-tx^j)^{z-1}.$$
(a) If $z=2$ then on the one hand we get Euler's
$$F(t,x,2)=\sum_{n\geq0}\frac{(-1)^nx^{\binom{n}2}}{(x;x)_n}t^n,$$
on the ...
CommunityBot
- 1
6
votes
0
answers
136
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On a certain $(-1)$-Eulerian polynomials of type $B$
Let $(q)_n=(1-q)(1-q^2)\cdots(1-q^n)$ with $(q)_0:=1$. Define a $q$-exponential by
$$e_q(z)=\sum_{n\geq0}\frac{z^n}{(q)_n}.$$
There is a notion of $q$-Eulerian polynomials of type $A$, see the ...
CommunityBot
- 1
6
votes
2
answers
581
views
Partitions, $q$-polynomials and generating functions
Recall the integer partition function $P(n)$ with generating function
$$\sum_{n\geq0}P(n)x^n=\prod_{k=1}^{\infty}\frac1{1-x^k}.$$
Let $[n]_q=\frac{1-q^n}{1-q}$ denote the $q$-analogue of the integer $...
CommunityBot
- 1
7
votes
1
answer
240
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$q$-Eulerian type B enjoy symmetry
Let $(q;q)_n=(1-q)(1-q^2)\cdots(1-q^n)$ with $(q;q)_0:=1$. Define a $q$-exponential by
$$e(z;q)=\sum_{n\geq0}\frac{z^n}{(q;q)_n}.$$
There is a notion of $q$-Eulerian polynomials, see the reference. I ...
- 5,624
16
votes
0
answers
454
views
A Product Related to Unrestricted Partitions
Start with the product for unrestricted partitions:
$(1+x+x^2+...)(1+x^2+x^4+...)(1+x^3+x^6+...)...$
Now replace some of the plus signs with minus signs and expand the product into a series. Is it ...
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