Skip to main content

All Questions

Filter by
Sorted by
Tagged with
22 votes
3 answers
2k views

Hecke equidistribution

For a prime $p\equiv 1\pmod{4}$, we can write $p=a^2+b^2=N(a+bi)$. Therefore $$ a+bi=p^{1/2}e^{i\varphi} $$ where $\varphi\in [0,2\pi]$. I know that Hecke proved that $\varphi$ is equidistributed. I ...
M.B's user avatar
  • 2,508
23 votes
3 answers
2k views

Why are values of Eisenstein $E_2^*$ algebraic integers?

I'm looking for a proof that the following term is an algebraic integer whenever $\tau_N=\frac{N+\sqrt{-N}}{2}$ is a quadratic irrationality with class number $1$: $$A_N:=\sqrt{-N}\cdot\frac{E_2(\...
L. Milla's user avatar
  • 598
4 votes
1 answer
504 views

How does this calculation of Siegel make sense?

I am reading Siegel's paper Zum Beweise des Starkschen Satzes. Let $K$ be an imaginary quadratic field with $d_K=-p$, $p=4k+3$ a prime, and such that $h_K=1$. Let $f=4m+1$ be a prime inert in $K$, ...
Shimrod's user avatar
  • 2,375
3 votes
1 answer
363 views

How many non principal prime ideals does a number field contain?

Let $K$ be a number field with ring of integers $O_K$ is not PID. Can we estimate the cardinality of the following sets $$\mathcal{A}= \{\mathcal{P}\subset O_K \ |\ Nm(\mathcal{P})\leq x, \mathcal{P}\...
SUNIL PASUPULATI's user avatar
47 votes
3 answers
5k views

Class Numbers and 163

This is a bit fluffier of a question than I usually aim for, so apologies in advance if this doesn't pass the smell test for suitability. Likely my favorite fun fact in all of number theory is the ...
Cam McLeman's user avatar
  • 8,467
13 votes
2 answers
2k views

Why is $\frac{\sqrt{6}}{32}(29 + \sqrt{145}) \approx \pi$ ?

Apologies in advance if this is a stupid question; also, disclaimer: this is purely for fun; but: Why is $\frac{\sqrt{6}}{32}(29 + \sqrt{145})$ such a good approximation to $\pi$? (Correct to 8 ...
Zen Harper's user avatar
  • 1,990
11 votes
1 answer
1k views

Upper bounds for regulators of real quadratic fields

We have an elementary sharp lower bound for the regulator of a real quadratic field as a function of the discriminant $$R\geq \tfrac{1}{2}(\sqrt{d-4}+\sqrt{d})$$ It is sharp because the equality ...
Myshkin's user avatar
  • 17.6k
8 votes
2 answers
973 views

Easiest way to see that $\zeta_{\mathbb{Z}[i]}(s) = \zeta(s) L(s, \chi)$?

As the question suggests, what is the easiest way to see that$$\zeta_{\mathbb{Z}[i]}(s) = \zeta(s)L(s, \chi)?$$Here, $\chi$ is the homomorphism $(\mathbb{Z}/4\mathbb{Z})^\times \to \mathbb{C}^\times$ ...
user avatar
5 votes
0 answers
136 views

When are the Artin symbols of two primes equal?

Let $K$ be an abelian number field. Let $p$, $q$ be rational primes. Is there some condition like $p\equiv q$ modulo some integer which depends on conductor of $K$ or $\operatorname{disc}(K)$ that ...
user11333's user avatar
  • 343
4 votes
1 answer
545 views

class number of biquadratic fields

Can any one provide some references which treat the relation between the class number of a biquadratic field and the class numbers of its sub-fields using the analytic class number formula ?
Zakariae.B's user avatar