-1
$\begingroup$

Does there exist a smooth orthonormal frame $X_1,X_2,X_3$ on $\mathbb{S}^3$ such that the distribution spanned by $X_i$ and $X_j$ is integrable for all $1\leq i,j\leq 3$?

$\endgroup$
2
  • 1
    $\begingroup$ This is essentially the same as your previous question mathoverflow.net/questions/385393/… $\endgroup$ Commented Mar 9, 2021 at 17:03
  • 2
    $\begingroup$ If such a frame do exist, I'm afraid it cannot be constructed as the frame $\left\{\mathcal{X}_i\right\}$ associated to an orthonormal basis $\left\{X_i\right\}$ of $\mathfrak{p}$ as in mathoverflow.net/questions/284318/… Hopefully the Reeb foliation might help construct such a frame. $\endgroup$
    – SubGeo
    Commented Mar 9, 2021 at 18:06

1 Answer 1

5
$\begingroup$

I assume that you are asking about the global problem of existence on the round $3$-sphere, as the local existence of such frame fields is well-known and goes by the name 'triply orthogonal systems' in the classical literature.

Because the problem is conformally invariant, the local problem is the same as finding such orthonormal frame fields in $\mathbb{R}^3$. There, the existence and uniqueness theorem can be stated as follows:

If $S\subset\mathbb{R}^3$ is an embedded smooth surface and $X_1,X_2,X_3$ are a smooth orthonormal frame field along $S$ with the property that each of the $X_i$ is nowhere tangent to $S$ along $S$, then there is an open neighborhood $U$ of $S$ in $\mathbb{R}^3$ on which the $X_i$ extend uniquely to $U$ as an orthonormal frame field such that the 2-plane fields $D_{ij}$ spanned by $X_i$ and $X_j$ for $i\not=j$ are integrable in $U$.

In the real-analytic category, this result was known to Darboux, but, in the smooth category, the first place I know of a proof is in a 1984 paper by Dennis DeTurck and Deane Yang, Existence of elastic deformations with prescribed principal strains and triply orthogonal systems, Duke Math. J. $\mathbf{51}$, 243–260.

Globally on $S^3$, as far as I'm aware, there is no known solution. It is interesting to note that by a 1964 result of Novikov, any codimension $1$ foliation of the $3$-sphere has a compact leaf that is a torus. This can be used to show that there is no real-analytic codimension $1$ foliation of the $3$-sphere. (See H. Blaine Lawson, Jr. The Qualitative Theory of Foliations, CBMS Regional Conference Series in Mathematics, Volume 27 (1977), AMS/CBMS.)

Thus, while there might be a global smooth solution on the $3$-sphere, there cannot be a global real-analytic one.

$\endgroup$
3
  • $\begingroup$ Thanks for your careful answer. I was aware of the results you mentioned, including Novikov's. I was really looking for a global smooth solution on the 3-sphere. $\endgroup$
    – SubGeo
    Commented Mar 9, 2021 at 18:12
  • $\begingroup$ @SubGeo: If you knew all this information and had divulged some of it in your question, you might have avoided the 'close' votes that it provoked. I'm afraid that several people have read your question and mistakenly concluded that it was either trivial or already answered in another question. $\endgroup$ Commented Mar 9, 2021 at 20:25
  • $\begingroup$ You're right. I thought it was evident that I had meant the global problem, since the problem is conformally invariant and even the stereographic projection would do the job in the sphere minus a point. I'll consider giving more details next time. $\endgroup$
    – SubGeo
    Commented Mar 12, 2021 at 14:09

Not the answer you're looking for? Browse other questions tagged .