Skip to main content
31 votes
Accepted

Embedding abelian varieties into projective spaces of small dimension

Recall that any smooth projective variety of dimension $g$ embeds into $\mathbf{P}^{2g+1}$. Consider now an abelian variety $A$ of dimension $g$ which embeds into $\mathbf{P}^{2g}$. Van de Ven proves (...
ssx's user avatar
  • 2,808
23 votes
Accepted

Square root of the determinant line

There is no such isomorphism (at least for $g \geq 9$). In O. Randal-Williams, The Picard group of the moduli space of r-Spin Riemann surfaces. Advances in Mathematics 231 (1) (2012) 482-515. I ...
Oscar Randal-Williams's user avatar
15 votes

Classification of line bundles by second cohomology of a manifold

For what it is worth, here is another approach, in the algebraic geometry style. By taking out the zero section, complex line bundles correspond bijectively to $\mathbb{C}^*\!$-principal bundles on $M$...
abx's user avatar
  • 38k
12 votes

Square root of the determinant line

I'm not sure what you mean by 'canonical'. For example, when $\Sigma$ has genus $1$, there are 4 distinct spin structures, one representing the trivial line bundle, whose space of holomorphic ...
Robert Bryant's user avatar
11 votes
Accepted

Classification of line bundles by second cohomology of a manifold

I think $H^2(M;\mathbb{Z})$ cannot mean the de Rham cohomology group. The coefficients are wrong. Anyway: $\mathbb{CP}^\infty$ is an amazing space. It is both a model for $K(\mathbb{Z},2)$ and a ...
Thomas Rot's user avatar
  • 7,583
11 votes
Accepted

One-point compactification of ample line bundle

This is EGA 2, Prop. 8.8.2. It basically says that if $L$ is ample then one can contract the zero section of the geometric realization $\mathbb V(L)$ of $L$ to a point. The result is called the affine ...
Friedrich Knop's user avatar
10 votes
Accepted

Conceptual understanding of the Néron–Severi group

$\DeclareMathOperator\NS{NS}$Your understanding is correct — the only error is the word "just" which seems to reflect the assumption that because the Néron–Severi group can be explicitly ...
Will Sawin's user avatar
  • 148k
9 votes

Is a torsion free sheave of rank one on a reducible curve the pushforward of a line bundle on a normalization?

This is (exactly as stated in your question) for example in Proposition 10.1 of Oda, Tadao; Seshadri, C. S. Compactifications of the generalized Jacobian variety. Trans. Amer. Math. Soc. 253 (1979), ...
Reimundo Heluani's user avatar
9 votes
Accepted

A question on "Ample subvarieties of algebraic varieties"

I suspect that you are supposed to view the projective variety $X$ as being given with a chosen projective embedding $X\subset \mathbb P^n$, and therefore a distinguished ample divisor $\mathcal{O}_X(...
Tom Ducat's user avatar
  • 1,306
8 votes
Accepted

The existence of the extension of a non-trivial line bundle

This is a bordism problem, and as such can be answered using algebraic topology. I'll answer in the unoriented setting, then indicate how to modify things if $M$ and $W$ are required to be oriented. ...
Mark Grant's user avatar
  • 35.9k
8 votes
Accepted

Compact complex non-Kähler manifolds with nef canonical bundle

Let $X$ and $Y$ be compact complex manifolds. Note that $K_{X\times Y} \cong \pi_1^*K_X\otimes \pi_2^*K_Y$. If $Y$ has trivial canonical bundle, then $K_{X\times Y} \cong \pi_1^*K_X$. Now the pullback ...
Michael Albanese's user avatar
7 votes
Accepted

The kernel of a nef line bundle

Consider $V=\mathbb{P}^1\times \mathbb{P}^2$ with projections $p_1\colon V \rightarrow \mathbb{P}^1 \text{ and } p_2\colon V \rightarrow\mathbb{P}^2.$ Let $L = p_1^*(\mathcal{O}_{\mathbb{P}^1}(1))$, ...
Chiles's user avatar
  • 86
7 votes
Accepted

Pull-back of the canonical divisor via a rational map

There are several issues with this question. One issue is that if $f$ is a rational map and not a morphism, then you have to say what you mean by $f^*$. Another issue is that if $K_Y$ is not at least ...
Sándor Kovács's user avatar
7 votes
Accepted

Global choice of eigenvectors on an open surface

Not necessarily. To construct a counter-example, start from the other direction. Suppose that the tangent bundle of $M$ can be split as the direct sum $TM = L_1\oplus L_2$ where $L_1$ and $L_2$ are ...
Robert Bryant's user avatar
7 votes

Question regarding the definition of linearization of line bundles

I think that you should regard the first definition as an imprecise version of the second definition. For example, suppose that $ X $ is a point and so $ L $ is simply a 1-dimensional vector space. ...
Joel Kamnitzer's user avatar
7 votes
Accepted

Is the square of a special line bundle also special?

In general, the answer is no. If $C$ has genus $g \geq 3$, take any effective divisor $D$ of degree $d$ such that $g - 1 < d < 2g-2$ and the support of $D$ is contained in an effective canonical ...
Francesco Polizzi's user avatar
6 votes

Classification of line bundles by second cohomology of a manifold

Although Milnor and Stasheff is an excellent suggestion, I was also led to wonder where one would find this result in more recent textbooks. Most ingredients are in May's "Concise introduction to ...
Neil Strickland's user avatar
6 votes
Accepted

Picard group of toric varieties

Edit: I have elaborated on this approach to the Picard group in Section 2 of my preprint. The question was answered in the comments above, but only for the case of torsion-free Picard group. However, ...
Justus Springer's user avatar
6 votes
Accepted

Universal covering of symmetric product

In fact, the universal cover of $C^{(n)}$ will not be $\mathcal H^n$ once $n \gg 0$. Indeed, if $C$ is a compact Riemann surface of genus $g \geq 2$ (so the universal cover is $\mathcal H$) with a ...
R. van Dobben de Bruyn's user avatar
6 votes

Characterizing principal polarizations of abelian surfaces

The usual way of presenting elements of the Neron-Severi group of an abelian variety is as Hermitian forms on the tangent space at the identity (subject to the condition that the imaginary part of the ...
Will Sawin's user avatar
  • 148k
5 votes
Accepted

Lifting line bundles

This cannot always be done. If $X$ is a supersingular K3 surface then there are $22$ ample line bundles $L$ that give independent classes; if every $L^{\otimes p}$ lifted to char. zero, then you'd ...
inkspot's user avatar
  • 3,137
5 votes
Accepted

Existence of a connection $A$ on a holomorphic line bundle $L$, s.t $F(A)=(\deg L)\omega$

Let me expand a bit Henri's (hi Henri!) answer, even if this is completely standard. In general, given a compact Kähler manifold $X$ of any dimension, given a holomorphic line bundle $L\to X$, and ...
diverietti's user avatar
  • 7,902
5 votes
Accepted

Line bundles trivial outside of codimension 3

This will hold for CW structures on manifolds coming from handle decompositions, e.g. induced by a Morse function. Complex line bundles on $X$ are classified by the homotopy class of maps to $\mathbb{...
Ian Agol's user avatar
  • 68.8k
5 votes
Accepted

Extension of first order deformations of a line bundle

Under some conditions on $X,V$, your line bundle can be extended to $X_{\varepsilon}$. Indeed, let $\imath_X:X\hookrightarrow X_{\varepsilon}$ and $\imath_V:V\hookrightarrow V_{\varepsilon}$ be two ...
nariri's user avatar
  • 392
5 votes

What are meromorphic line bundles?

You can define "meromorphic vector bundle" as locally free sheaf of modules over a sheaf of meromorphic functions. This is a highly non-trivial object, because (in contrast with rational ...
Misha Verbitsky's user avatar
4 votes

Existence of a connection $A$ on a holomorphic line bundle $L$, s.t $F(A)=(\deg L)\omega$

Let $h_0$ be any hermitian metric on $L$, with curvature $F(h_0)$. By Hodge theory, there exists a function $f\in \mathcal C^{\infty}(X)$ such that $$\Delta_{\omega} f =\Lambda_{\omega} F(h_0) - \...
Henri's user avatar
  • 2,727
4 votes
Accepted

Weights on the linearization

If your $\mathbb{P}^2$ is $\mathbb{P}(\mathbb{C}^3)$, you can identify the complement of the zero section in $L^{-1}$ with $\mathbb{C}^3\smallsetminus 0$, viewed as a bundle over $\mathbb{P}^2$ via ...
abx's user avatar
  • 38k
4 votes
Accepted

The set of isomorphism classes of Z/nZ-equivariant line bundles over a 2 dimensional Z/nZ-CW complex

You can replace $GL_1(\mathbb C)$ with its maximal compact subgroup, which is $S^1$. Since $S^1$ is an abelian compact Lie group, there is a natural $\mathbb Z/n$-equivariant equivalence $$B_{\mathbb ...
Gregory Arone's user avatar
4 votes

Differential refinement of homology

Differential cohomology groups are computed as homotopy groups $\hat{\rm H}^n(M)=π_0(F_n(M))$, where $F_n\colon{\sf Man}^{\rm op}\to{\sf Sp}$ is a sheaf of spectra on the site of smooth manifolds. (...
Dmitri Pavlov's user avatar
4 votes
Accepted

Galois invariant line bundle and base change

I am posting my comment as an answer. This result is discussed in many sources. I do not have Serre's "Galois cohomology" with me at this moment, but I am certain that it is discussed ...

Only top scored, non community-wiki answers of a minimum length are eligible