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15 votes

dichotomy in hyperbolic groups

No, there is no such dichotomy. If $G$ is an infinite group with Property (T) and $H$ is any non-trivial group, then $G*H$ has neither of the two properties. This is because groups with Property (T) ...
Giles Gardam's user avatar
  • 2,386
12 votes

4-manifold $M$ with intersection form of Leech lattice

If you're assuming $M$ is simply-connected, then it would be spin (since the Leech lattice is even). So a smooth manifold would violate Rokhlin's theorem. In the topological case (still assuming ...
Danny Ruberman's user avatar
9 votes
Accepted

Abstract simplicial complexes - Reference for an elementary definition of mapping degree for simplicial maps?

I think the right generality to restrict to is the following: Let $n$ be a positive integer, and let $X$ and $Y$ be $n$-dimensional oriented simplicial complexes, with the following properties: Every ...
Achim Krause's user avatar
  • 7,279
6 votes

0-surgery on a fibered hyperbolic ribbon knot

I had a quick look at Maggie Miller's thesis. It appears that the pretzel knots $(\pm 2, n, -n)$ where $n$ is odd are fibered ribbon knots (and they are also hyperbolic). Moreover, it appears that the ...
Ian Agol's user avatar
  • 64.2k
5 votes

Finding a hyperbolic metric with geodesic boundary on a given Riemann surface

See Theorem 1(b) in the following paper; it is enough that the boundary is smooth. Osgood, B.; Phillips, R.; Sarnak, P. Extremals of determinants of Laplacians. J. Funct. Anal. 80 (1988), no. 1, 148--...
Jeffrey Case's user avatar
  • 1,338
5 votes

Knot theory in handlebodies of arbitrary genus

You example of graphs in the plane "becoming embedded via local operations" is not modelled by handle attachment. (For example, if you immerse $K_5$ in a disk $D^2$ and then attach one-...
Sam Nead's user avatar
  • 22.8k
5 votes

Knot theory in handlebodies of arbitrary genus

If you mean adding 1 and 2 handles to the boundary of the ball, that will never change the (non)triviality of the knot in the 3-ball. On the other hand, perhaps the notion of tunnel number is what you ...
Scott Taylor's user avatar
5 votes

Does every triangulable manifold have a vertex-transitive triangulation?

This is to supplement Ian's answer and get examples in all dimensions $\ge 3$. Let $M={\mathbb H}^n/\Gamma$ be a compact hyperbolic $n$-manifold; suppose that $f\in Homeo(M)$ is a homeomorphism of ...
Misha's user avatar
  • 30.6k
5 votes

Does every triangulable manifold have a vertex-transitive triangulation?

There exists many closed connected hyperbolic 3-manifolds $M$ with trivial symmetry group, and hence trivial mapping class group. $M$ cannot be homeomorphic to a simplicial complex $\tau$ which admits ...
Ian Agol's user avatar
  • 64.2k
5 votes
Accepted

Does $\overline{\mathbb{C}P^2 \setminus B^4}$ embed (smoothly/topologically) in $\mathbb R^5$?

$\def\RR{\mathbb{R}}\def\CC{\mathbb{C}}\def\PP{\mathbb{P}}$I think the answer is no. Topology isn't my strength, so check this argument. Let $\infty$ be the point $[0:0:1]$ in $\CC \PP^2$ and put $U = ...
David E Speyer's user avatar
4 votes
Accepted

Finding a hyperbolic metric with geodesic boundary on a given Riemann surface

A good reference is W. Abikoff, The real analytic theory of Teichmuller space, Springer, 1980. (Chap. II section 1). The idea is that you construct the double: it is the result of gluing of your ...
Alexandre Eremenko's user avatar
1 vote
Accepted

Bring's curve $\sum_{i=1}^5 x_i^k = 0$ for $k = 1,2,3$ and an analogue $\sum_{i=1}^6 y_i^k = 0$ for $k = 1,2,4,7$

The equations $\sum_{i=1}^6 y_i^k = 0$ for $k=1,2,4,7$ do not cut out a curve because the $k=1,2,4$ equations imply the one for $k=7$. (The 7th power sum is a polynomial in the power sums of degree 1 ...
Noam D. Elkies's user avatar

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