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31 votes
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Embedding abelian varieties into projective spaces of small dimension

Recall that any smooth projective variety of dimension $g$ embeds into $\mathbf{P}^{2g+1}$. Consider now an abelian variety $A$ of dimension $g$ which embeds into $\mathbf{P}^{2g}$. Van de Ven proves (...
ssx's user avatar
  • 2,808
23 votes
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When $k = \mathbb{F}_q$ finite field, $X$ always has $k$-rational point, and so $A \simeq X$?

This is a theorem of Lang's from 1956. Here's an online document giving a proof (in the form $H^1(A,k)=0$): Lecture 14: Galois Cohomology of Abelian Varieties over Finite Fields, William Stein. http:...
Joe Silverman's user avatar
23 votes
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On Tate's "Endomorphisms of Abelian Varieties over Finite Fields", sketch of proof of main result?

I don't have any contribution for the intuition beyond the fact that, I can't construct something outside the image of (1) so I hope it's surjective. Here is a sketch of the central idea of Tate's ...
Felipe Voloch's user avatar
18 votes

Is every abelian variety a subvariety of a Jacobian?

Embed the dual abelian variety into projective space. Take a smooth hyperplane section and interate until it's one-dimensional, obtaining a smooth curve $C$. By Lefschetz $C$ is irreducible, and the ...
Will Sawin's user avatar
  • 148k
18 votes
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Is the complement of an affine open in an abelian variety ample?

Welcome new contributor. Yes, that is true. Let $k$ be any field, let $A$ be an Abelian variety over $k$, and let $U\subset A$ be a dense open affine. Denote by $D\subset A$ the complementary ...
16 votes
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Tate-Shafarevich group over number fields

No. It is always difficult to "prove" that something is "not known", but this may do: I claim it is not even known when $K=\mathbb Q$, $A$ is an elliptic curve $E$. In fact in this case, the result ...
Joël's user avatar
  • 26k
16 votes
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Points of abelian varieties over purely transcendental extensions

This follows from the following well-known lemma. Lemma. Let $A$ be an abelian variety over $k$. Then any map $f \colon \mathbb P^1 \to A$ is constant. Proof 1. The map $f$ induces a map on the ...
R. van Dobben de Bruyn's user avatar
15 votes
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Canonical lift of the deformation of an ordinary abelian variety

No. The picture over a general base is this: let $A_0\to S_0$ be an ordinary abelian variety over a characteristic $p$ scheme $S_0$, and let $S_n$ ($n\geq 0$) be compatible flat liftings of $S_0$ over ...
Piotr Achinger's user avatar
15 votes
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Torsion points of abelian variety as zeros of a section of a vector bundle?

The crucial case is $m=1$: if you have a vector bundle $E$ on $A$ of rank $\dim(A)$ and a section $s$ of $E$ whose zero locus is $\{0\} $, pulling back $(E,s)$ by multiplication by $m$ gives the ...
abx's user avatar
  • 38k
14 votes

When $k = \mathbb{F}_q$ finite field, $X$ always has $k$-rational point, and so $A \simeq X$?

A bit of overkill, but it follows from the Weil conjectures. The structure of cohomology ($H^i = \wedge^i H^1$) is computed over the algebraic closure and it follows that the number of points is $\...
Felipe Voloch's user avatar
14 votes
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Albanese variety over non-perfect fields

The arguments of Serre can be in fact made to work over any separably closed field. The result in the general case can then be deduced using Galois descent. Details can be found in Section 2 and the ...
Daniel Loughran's user avatar
14 votes

Albanese variety over non-perfect fields

The answer is affirmative (in Serre's formulation via principal homogeneous spaces) for proper, geometrically reduced, and geometrically connected schemes $X$ over any field $k$, giving a strong ...
14 votes
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On the moduli stack of abelian varieties without polarization

First, when defining the stack you will have the issue that there are formal deformations of abelian varieties which do not extend to families of abelian varieties over any reduced scheme. These are ...
Will Sawin's user avatar
  • 148k
14 votes
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Is a complex algebraic set with a Zariski dense subset of algebraic points already defined over the algebraic numbers?

More is true. Let $K/F$ be a field extension. Let $X$ be the vanishing set of some polynomials in $K[X_1,\dots, X_n]$. If $X$ contains a Zariski dense set of points with coordinates in $F$, then $X$ ...
Will Sawin's user avatar
  • 148k
13 votes

Bhargava's work on the BSD conjecture

For a prime $p$ and an elliptic curve $E/\mathbb{Q}$, we have the exact sequence $$\displaystyle 0 \rightarrow E(\mathbb{Q})/p E(\mathbb{Q}) \rightarrow S_p(E) \rightarrow \text{Sha}_E[p]\rightarrow ...
Stanley Yao Xiao's user avatar
13 votes

Is every abelian variety a subvariety of a Jacobian?

Let me give an answer for $k = \mathbb{C}$. By a theorem of Matsusaka, every abelian variety $A$ over an algebraic closed field $k$ is a quotient of a Jacobian. Now just apply Matsusaka's theorem to ...
Francesco Polizzi's user avatar
13 votes
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Conceptual explanations of the class numbers for the first few $\mathbb{Q}(\sqrt{p})$ with odd conductor

We give a uniform approach to $p \leq 61$ by applying analytic discriminant bounds to the Hilbert class field. To be sure this is not entirely "conceptual", but then some computation is needed even to ...
Noam D. Elkies's user avatar
12 votes
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Galois action on $p$-adic Tate module of Abelian variety over finite field semisimple?

You're just asking whether Frobenius acts semsimply on the $p$-adic Tate module. We know from Tate's theorem that Frobenius acts semisimply on the $\ell$-adic Tate module, and hence satisfies some ...
Will Sawin's user avatar
  • 148k
12 votes
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Are there infinitely many real multiplication fields of abelian surfaces over $\mathbb Q$?

A conjecture of Coleman asserts that only finitely many rings arise as the endomorphism ring of an abelian variety of given dimension defined over a number field of given degree. See [1] for an ...
François Brunault's user avatar
11 votes
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Do all simple factors of jacobians of curves come from correspondences?

This argument is mostly contained in t3suji's comments, but with some of the proofs somewhat expanded. As a convention (consistent with that of the theory of Chow motives), all actions of ...
R. van Dobben de Bruyn's user avatar
11 votes

Torsion points of abelian varieties in the perfect closure of a function field

The answer to question (*) is yes. It is Theorem 1.2.2 in the following preprint.
Emiliano Ambrosi's user avatar
11 votes
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Is the symmetric product of an abelian variety a CY variety?

When $\dim A = 1$, $S^nA$ is a $\mathbb{P}^{n-1}$-bundle over $A$, so its Kodaira dimension is $-\infty$. When $\dim A = 2$, the minimal resolution of $S^nA$ is given by the Hilbert scheme $A^{[n]}$, ...
Sasha's user avatar
  • 39.3k
11 votes
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Tamagawa numbers

Denote by $\Phi$ the quotient of $\mathcal A^\vee$, the special fiber of the smooth (but not necessarily proper) model of the dual abelian variety $A^\vee$, by the connected component of $0$ of $\...
Olivier's user avatar
  • 10.9k
11 votes
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Which schemes are divisors of an abelian variety?

Any curve of genus greater than two, whose Jacobian $J$ is simple, will do. If it were a divisor on an abelian surface $S$, then there would be a surjection $J\to S$ with positive dimensional kernel, ...
Ari Shnidman's user avatar
  • 2,606
11 votes

A geometric definition of the addition law on abelian surfaces

This must be standard, I don't have a reference but the construction is easy: let $y^2=f(x)$ be a genus 2 hyperelliptic curve with $f$ squarefree of degree $5$ or $6$. As a set the Jacobian is the ...
Henri Cohen's user avatar
  • 13.1k
11 votes
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Do there exist elliptic curves over $H_K$ having everywhere good reduction and CM by $\mathcal{O}_K$?

Here is an example. Let $K = \mathbf{Q}(\sqrt{-21})$. Then the class group of $K$ is $C_2 \times C_2$ and its Hilbert class field is $H_K = \mathbf{Q}(\sqrt{-1}, \sqrt{3}, \sqrt{7})$. In particular, $...
David Loeffler's user avatar
11 votes
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A "comprehensive" family of abelian varieties

Welcome new contributor. The idea of such "comprehensive" families goes back very far. These were studied by Amitsur under the name "generic splitting varieties", primarily in ...
10 votes
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How to compute the formal group law of a Shimura variety (using its invariant differentials)?

I don't know how to do this purely with invariant differentials. One of the main reasons is that, in order to solve this problem, you need to construct an "algebraic" lift of this variety from the ...
Tyler Lawson's user avatar
  • 52.6k
10 votes

Geometry of Albanese image

The first natural observation is the following. Set as usual $q(X):=h^{1, \,0}(X)$, so that $q(X)= \dim \mathrm{Alb}(X)$. Then the Albanese map of $X$ cannot be surjective if $\dim X < q(X)$, and ...
Francesco Polizzi's user avatar
10 votes
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Can an abelian variety dominate a variety of general type?

Theorem: Let $A$ be an abelian variety and $f:A\to X$ a dominant morphism to a projective variety of general type, then $\dim X=0$. Proof: Replacing $f$ by a birational model of the Stein ...
Hacon's user avatar
  • 2,427

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