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35 votes
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Does every sheaf embed into a quasicoherent sheaf?

That already fails for $X$ equal to $\text{Spec}\ R$, where $R$ is a DVR with generic point $\eta = \text{Spec}\ K$. Since there are only two nonempty open subsets of $X$, namely all of $X$ and $\{\...
29 votes
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When (or why) is a six-functor formalism enough?

When defining a homotopy-coherent structure, you have to strike the correct balance between supplying enough data (so that all isomorphisms (between isomorphisms, ...) that you need later are actually ...
Peter Scholze's user avatar
21 votes
Accepted

Is there a complex which computes Cech cohomology?

This is the kind of thing sieves are good for. For an open cover, let $S$ denote the sieve it generates, so $S$ is poset of open subsets $V$ such that $V$ is contained in some element of the cover. ...
Dustin Clausen's user avatar
16 votes

Poincare duality on the level of complexes

One way of finding a "fully derived" version of Poincaré duality is Atiyah duality. This says that for any closed manifold $M$ there is an equivalence of spectra (in the sense of algebraic topology) $$...
Denis Nardin's user avatar
  • 16.5k
14 votes

Is there a complex which computes Cech cohomology?

While I'm sure a hocolim solution also exists (and works in general), one can avoid it, at least for compact topological spaces, by using open covers which are indexed by the points of your space $X$ (...
John Pardon's user avatar
  • 18.7k
14 votes
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Different definition of sheaf cohomology

Taking global sections is the same thing as computing the hom from $O_X$. In other words, there is an isomorphism of functors $\Gamma(X,-)\cong\hom(O_X,-)$, so both functors have the same derived ...
Mariano Suárez-Álvarez's user avatar
14 votes
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Zorn's lemma for Grothendieck sites

The statement you formulate is not true in this generality. The idea of the following counterexample is to exploit the fact that the assumption "all restriction maps along morphisms of the site ...
Matthias Hutzler's user avatar
13 votes

How to compute the cohomology of a local system?

Suppose $X$ is a connected CW complex with fundamental group $\pi:=\pi_1(X,x)$. Then the cellular chain complex $C_*(\widetilde{X})$ of the universal cover is a chain complex of free $\mathbb{Z}\pi$-...
Mark Grant's user avatar
  • 35.9k
12 votes
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Cohomology of Grothendieck topology

Artin, M. Grothendieck topologies. (English) Zbl 0208.48701 Cambridge, Mass.: Harvard University. 133 p. (1962). (pdf copy) These notes seem to fit your description precisely. They are concise, start ...
10 votes
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Algebraic groups without torsors

I am just posting my comment as an answer. If you want to produce a nontrivial torsor, it suffices to produce a nontrivial torsor after base change to the algebraic closure of a residue field of the ...
10 votes
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First cohomology of tangent sheaf of rational curve

Let $C$ be the union of 5 lines in general position in $\mathbb{P}^2$ (hence with 10 pairwise intersection points $P_{ij}$, $1 \le i < j \le 5$) and let $F$ be the equation of $C$. We have the ...
Sasha's user avatar
  • 39.3k
10 votes
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Clarification on smooth de Rham theorem

The following statements are true: The complex $0 \to \mathbb{R}_X \to \Omega^0_X \to \Omega^1_X \to \dots$ is an acyclic complex (of sheaves), i.e. it is exact at each step. This is the content of ...
David Loeffler's user avatar
10 votes

Converses to Cartan's Theorem B

For (4), there are finite CW complexes $X$ which are not contractible, but such that $H^q(X, \mathcal{F})$ vanishes for all (finite rank) locally constant sheaves $\mathcal{F}$. Specifically, take $X$ ...
David E Speyer's user avatar
9 votes
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Sheaf cohomology of a complement of finitely many points

For what follows, I recommend SGA 2 (available on Arxiv). There is an exact sequence $$0\rightarrow H^1(X,\mathcal{O}_X)\rightarrow H^1(X\smallsetminus p,\mathcal{O}_X)\rightarrow H^2_{p}(X,\mathcal{O}...
abx's user avatar
  • 38k
9 votes

difference between the small and big étale/flat/... site

You can always compute the cohomology as the limit over hypercoverings of the final object. But the hypercoverings of the final object are the same in both categories, so it seems that the cohomology ...
Piotr Achinger's user avatar
9 votes
Accepted

Elementary way to compute Hodge numbers of Grassmanian

One of the ways is to use the projective bundle theorem that says that if $X = \mathbb{P}_Y(E)$ is a projectivization of a rank $r$ vector bundle $E$ over $Y$ then $$ H^\bullet(X) = H^\bullet(Y) \...
Sasha's user avatar
  • 39.3k
9 votes

Estimates for certain double-Kloosterman sums

I can do it for $q$ prime, and thus $q$ squarefree, by a long but elementary manipulation followed by the Weil bound. Until the end, the elementary manipulations will work for $q$ arbitrary. Taking ...
Will Sawin's user avatar
  • 148k
8 votes
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Do the cohomology groups of the structure sheaf of a smooth resolution depend on the resolution?

Edit. This follows from the Elkik-Fujita Vanishing Theorem. There is a more general vanishing theorem due to Elkik and Fujita. One version of this theorem (where I read the theorem) is Theorem 1.3.1 ...
8 votes

How to compute the cohomology of a local system?

In general you should have $H^1(\pi_1(X,x),V)\cong H^1(X,L)\,,$ where on the left we have the group cohomology of $\pi_1(X,x)$ acting on $V$ according to the representation. You will also have an ...
Josh Lackman's user avatar
  • 1,198
8 votes
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$H^1(X, GL(n, \mathcal{O}_X))$ and Vector Bundles

Yes, this is called non-abelian sheaf cohomology. If $X$ is a topological space and $\mathcal{G}$ is a sheaf of groups, then $H^0(X, \mathcal{G})$ is the global sections of $\mathcal{G}$, and there is ...
David E Speyer's user avatar
8 votes

Reference request: Kleiman's proof of Snapper's Lemma

Note that Nitsure's paper is part of the book FGA Explained. There is a proof of Snapper's lemma in Theorem B.7 of Appendix B ("Basic intersection theory" by Kleiman) in the same book. ...
R. van Dobben de Bruyn's user avatar
8 votes

Geometric meaning of coherent sheaves $\mathcal{F} \otimes \mathcal{O}_{\mathbb{P}^n}(d)$ over $\mathbb{P}^n$

Let $x_0,\ldots, x_n$ be homogeneous coordinates, then a section of $H^0(\mathbb{P}^n,\mathcal{T}_{\mathbb{P}^n}(d))$ can be expanded as a sum $$\sum_i f_i(x_0,\ldots, x_n) \frac{\partial}{\partial ...
Donu Arapura's user avatar
  • 35.2k
7 votes

Computation of cohomology of ideal sheaves

The computation of the restriction morphism $H^i(Y,O_Y) \to H^i(X,O_X)$ is usually non-trivial (unless you know for instance an explicit locally free resolution of the ideal sheaf of $X$ in $Y$). On ...
Sasha's user avatar
  • 39.3k
7 votes
Accepted

Can one determine the trace map for a nonsingular projective variety explicitly?

This is a good question. It's one that my colleague Joe Lipman spent a lot of time thinking about. You can look at some of his papers for a more explicit answer for computing the trace. Probably you ...
Donu Arapura's user avatar
  • 35.2k
7 votes

Divisors whose restriction is big

Take $Y=\mathbb{P}^1$ and let $X=\mathbb{F}_n=\mathbb{P}(\mathcal{O} \oplus \mathcal{O}(-n))$ be the Hirzebruch surface with a section $C_0$ such that $C_0^2=-n$. Let $H$ be an ample divisor on $\...
Francesco Polizzi's user avatar
7 votes
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Cohomology of divisors on Hirzebruch surfaces

Sure. To compute $H^0$ one can first pushforward to the base $\mathbb{P}^1$. If $a \ge 0$ one obtains $$ p_*\mathcal{O}(a\Gamma + bF) \cong p_*\mathcal{O}(a\Gamma) \otimes \mathcal{O}(b) \cong S^a(\...
Sasha's user avatar
  • 39.3k
7 votes
Accepted

First Chern class of torsion sheaves

The coefficient $r$ is equal to the length of $\mathcal{T}$ at the generic point of $Z$, so it is positive.
Sasha's user avatar
  • 39.3k
7 votes

On the upper-bound for a type of quintuple Kloosterman sums

The Newton polyhedron method for your sum is as follows: We first replace the quadratic character with an additive character and a simpler quadratic character using a Gauss sum, then introduce a ...
Will Sawin's user avatar
  • 148k
7 votes
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Smooth analogue of Cartan's Theorem B

It seems like Gro-Tsen's comment pretty much answers your main question, doesn't it? If "simple" = $C^\infty$ manifold, and "nice" = sheaf of modules over $C^\infty_X$. Then such a ...
Donu Arapura's user avatar
  • 35.2k
7 votes
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Is the square of a special line bundle also special?

In general, the answer is no. If $C$ has genus $g \geq 3$, take any effective divisor $D$ of degree $d$ such that $g - 1 < d < 2g-2$ and the support of $D$ is contained in an effective canonical ...
Francesco Polizzi's user avatar

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