Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options answers only not deleted user 5801

Continuum theory, point-set topology, spaces with algebraic structure, foundations, dimension theory, local and global properties.

4 votes
Accepted

Are open sets determined by paths?

A space $X$ is called $\Delta$-generated if $U$ is open in $X$ if and only if $\alpha^{-1}(U)$ is open in $[0,1]$ for every path $\alpha:[0,1]\to X$. It's easy to see that a space $X$ is $\Delta$-gen …
Jeremy Brazas's user avatar
7 votes

Which spaces have enough curves

A space $X$ whose topology agrees with the final topology with respect to all maps $I\to X$ is often called a delta-generated ($\Delta$-generated) space. The category of $\Delta$-generated spaces is a …
Jeremy Brazas's user avatar
10 votes
Accepted

Fundamental groups and homology groups of closed subsets of the plane

Fundamental Group: The fundamental group of a planar set naturally injects into the first Cech homotopy group, which is an inverse limit of free groups. In particular, the algebraic restrictions gaine …
Jeremy Brazas's user avatar
2 votes

covering theory with compact open topology

$p^{\ast}$ may not be surjective without extra assumptions. For example, you can check out Zeeman's example in Spanier's textbook of non-equivalent coverings corresponding to the same subgroup of $\pi …
Jeremy Brazas's user avatar
3 votes
Accepted

Let $U$ be a simply connected open subset of ${\Bbb S}^2$, is the complement of $U$ also sim...

$F=S^2\backslash U$ need not be path connected, e.g. $F$ could be homeomorphic to the closed topologists sine curve. However, every path component of $F$ must be simply connected. By identifying $U$ …
Jeremy Brazas's user avatar
37 votes

Is there a "universal" connected compact metric space?

There is no such continuum. See Z. Waraszkiewicz, Sur un problème de M.H. Hahn, Fund. Math. 22 (1934) 180–205. Waraszkiewicz constructed an uncountable family $W$ of continua in the plane called Wa …
Jeremy Brazas's user avatar
15 votes
Accepted

when is a locally homeo a covering map?

This answer takes a more general viewpoint than Alexandre's. The generality is in response to the small number of assumptions on the spaces involved. First, you should assume that $Y$ is locally path …
Jeremy Brazas's user avatar
7 votes
Accepted

Lifts across covering maps

Suppose you have basepoints $x_0\in X$, $z_0\in Z$ and $p(z_0)=f(x_0)$. The lift $\tilde{f}:X\to Z$ such that $p\circ \tilde{f}=f$ exists and is continuous if and only if 1) $f_{\ast}(\pi_1(X,x_0))\ …
Jeremy Brazas's user avatar
1 vote

Looking for general approaches to show connectedness of topological groups

Perhaps this is helpful for the locally compact case. Corollary 3.1.12 in "Topological groups and related structures" by Arhangel'skii and Tkachenko gives a nice characterization of connectedness in …
Jeremy Brazas's user avatar
4 votes

Is the wedge sum of two cones over the hawaiian earring contractible?

The space you are talking about is sometimes called the Griffiths space. As Henry Horton suggests, to prove it is not contractible you can show the fundamental group is non-trivial (even though its Ce …
Jeremy Brazas's user avatar
8 votes
Accepted

Construction of the universal covering space via compact-open topology

Here is the key step you need to finish the proof: We are supposing $X$ is locally path-connected and semilocally simply connected, $\pi:P(X,x_0)\to \widetilde{X}$ is the quotient map identifying path …
Jeremy Brazas's user avatar
4 votes
Accepted

fundamental groups of complements to countable subsets of the plane

Thanks to the comments, my original cardinality bound $\aleph_1\leq |S|\leq \mathfrak{c}$ has been refined to the equality $|S|=\mathfrak{c}$ that I originally suspected. For Question 1: $S$ has the …
Jeremy Brazas's user avatar
6 votes
Accepted

Homotopy equivalent fibers and Fibrations

The figure below gives a simple but extreme counterexample, which I think has all the lifting properties one might want except for actually being a true fibration. The map is the identity everywhere e …
Jeremy Brazas's user avatar
22 votes
Accepted

Universal covering space for non-semilocally simply connected spaces

My answer to this question gives an example of a locally path connected (but non-semilocally simply connected) space $HA\subset\mathbb{R}^3$ called the Harmonic archipelago: draw the Hawaiian earring …
Jeremy Brazas's user avatar
14 votes
Accepted

In a subset of $\mathbb{R}^2$ which is not simply connected does there exist a simple loop t...

One-dimensional metric spaces and planar sets do have the property that you're interested in. To explain why this works out in such generality requires a combination of planar topology, continuum theo …
Jeremy Brazas's user avatar

15 30 50 per page