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In mathematics, the spectral radius of a square matrix or a bounded linear operator is the supremum among the absolute values of the elements in its spectrum.

12 votes
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The spectral radius of a binary matrix

Perron-Frobenius theory clarifies this quickly. Observe first of all that if $M$ is irreducible in the sense that it cannot be made a block upper triangular matrix by a permutation of the standard bas …
Christian Remling's user avatar
3 votes
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Uniform decay of operator norm for smooth family of operators

This works, essentially because $\|T^k\|^{1/k}$ for a given $k=n$ also controls this quantity for $k\ge n$. More specifically, suppose that $\|T^n\|^{1/n}\le 1-\delta$. Clearly, $\|T^{kn}\|^{1/kn}\le …
Christian Remling's user avatar