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Enumerative combinatorics, graph theory, order theory, posets, matroids, designs and other discrete structures. It also includes algebraic, analytic and probabilistic combinatorics.
5
votes
Proof of a combinatorial equation
Similar questions can also be dealt with using generating functions and Lagrange inversion.
Let $T(z)$ (the "tree function") be the formal power series satisfying $T(z)=z\,e^{T(z)}$.
If $F$ is a fo …
1
vote
Accepted
Asymptotics of coefficients of implicitely defined generating function
Since $a_0\neq 0$ there is (by the (formal) Lagrange theorem) a unique formal power series $x=x(z)$ solving $x={z \over A^3(x)}$, and $A(x(z))=B(z)$ because $A(x)=B(x\,A^3(x))$.
Expanding $A(x)$ using …
2
votes
Accepted
Sum of inverse of multinomial coefficients
I add two hopefully useful remarks.
I consider the general situation. In the sequel $k\geq 1$ and $\lambda=(\lambda_1,\ldots,\lambda_{k+1})$ are fixed, $s:=\sum_{i=1}^{k+1}\lambda_i$ and $n\geq s$.
…
3
votes
Accepted
Birthday inequality for non-uniform distributions for fixed collision probability (random al...
I reformulate slightly, please check.
You are considering a sequence $X_1,X_2,\ldots$ of (discrete) i.i.d
random variables
and want an upper bound for the probability $\mathbb{P}(R>n)$
in terms of $ …
6
votes
A combinatorial identity
Here is a generating-function proof of your conjectured identity (and an answer to question 2).
The main ingredient is a formula for the appearing symmetric sums.
Let $T(z)$ (the ``tree function'') …
1
vote
Mixed moments for the birthday problem
Here is an approach via Lagrange inversion.
Let $N$ denote the time of the first repeat, and let $T(z)$ (the ``tree function'') be the formal power series satisfying $T(z)=z\,e^{T(z)}$.
If $F$ is a …
3
votes
Accepted
Birthday problem extension to unequal probabilities and multiple collisions
Here is a proof using generating functions. Let $c\geq 2$ and $k\geq 2$ be fixed.
Let $X=(X_1(n),\ldots,X_k(n))$ be the $k$-tuple of occupancy numbers at time $n$, i.e. $X_i(n)$ = number of bins of ty …
5
votes
Accepted
Expected number of compositions needed to get constant function
This question was completely settled by J.A. Fill here:
https://citeseerx.ist.psu.edu/viewdoc/summary?doi=10.1.1.8.641
3
votes
Accepted
Bounding the max-loaded bin using${m \choose k} \|A\|_k^k$
The following inequality holds:
$$\mathbb{P}(C_k(m)\geq 1)\geq \mathbb{P}(\mathrm{Bin}(m, \lVert A\rVert_k)\geq k)$$
where here and in the sequel $\mathrm{Bin}(n,p)$ denotes a binomially distributed r …
3
votes
A curious process with positive integers
Here is another way of studying these processes. In the sequel $k=3$ but it is clear how to generalize.
The idea is to look at the matrices formed by three consecutive triples used in the insertion p …
3
votes
1
answer
378
views
Determinant of an "almost cyclic" matrix
Let $n\geq 3$, let $Z$ be the matrix of the cyclic shift (the companion matrix of $X^n-1$), and for $\mathbf{d}\in \mathbb{C}^n$ let
$\operatorname{diag}(\mathbf{d})$ be the diagonal matrix with $\ma …
7
votes
Eigenvalues of a matrix with entries involving combinatorics
Let $F(n,\ell)$ be the matrix with coefficients
$$F_{i,j}(n,\ell)=[t^{\ell j-i}] \left(\frac{1-t^\ell}{1-t}\right)^n,\,\;\;\;1\leq i,j \leq n$$
Above Pat Devlin pointed out that it suffices to show t …
0
votes
Coupon collector targeting a collection among many
There a well known generating function methods (the ''symbolic method'' and ''Poissonization'') which can be used to deal with this kind of question.
However, I am unable to point to a reference for …
4
votes
Accepted
Moments of a combinatorial ensemble of random variables
(You are considering the uniform distribution on a discrete simplex. I'm not aware of specific results in the literature,
and a brief internet search didn't reveal anything.)
A simple way is to use …
7
votes
Comparing two power-series
As in Timothy Budd's answer let $w=w(q)$ denote the (formal) solution of $q=\frac{w}{f(w)}$.
Let $p$ be another variable and consider the sum
\begin{align*}
S(p,q):=\sum_{n,m>0} \sum_{j>0} j[z^{n+j}]\ …