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Continuum theory, point-set topology, spaces with algebraic structure, foundations, dimension theory, local and global properties.

17 votes
2 answers
1k views

Homeomorphisms and "mod finite"

Suppose $f:C\to C$ is a homeomorphism, where $C=\{0,1\}^{\mathbb N}$ is Cantor space. Suppose $f$ preserves $=^*$ (equality on all but finitely many coordinates). Does it follow that $f$ also reflects …
8 votes
1 answer
479 views

VC dimension of standard topology on the reals

Can there be an uncountable set $S\subseteq\mathbb R$ such that for each subset $D\subseteq S$, there is an open set $U$ with $D=S\cap U$? I'm asking merely out of curiosity, but I'll mention that thi …
3 votes
Accepted

Finding 1-generic paths through a tree $T \subseteq 2^{<\omega}$

What conditions can we impose on $T$ that guarantee $[T]$ contains a 1-generic member? An element that is 1-generic relative to $T$ will not be on $[T]$ unless $[T]$ contains a whole clopen cone $[\ …
Bjørn Kjos-Hanssen's user avatar
2 votes

Source on smooth equivalence relations under continuous reducibility?

Seems like this structure must be pretty complicated. For example, consider Brownian motion $\{W_t\}_{t\ge 0}$ with the equivalence relations $$t\sim_\omega s\iff W_t(\omega)=W_s(\omega).$$ Here $\ome …
Bjørn Kjos-Hanssen's user avatar
0 votes
Accepted

How to define "interior" for the unit arc?

This seems well described by the notion of interior $\mathrm{Int\ }M$ of a manifold with boundary $M$. See the Wikipedia subentry Manifold: Boundary and interior.
Bjørn Kjos-Hanssen's user avatar
4 votes

General topological space with closure operation as in Russian translation of Hausdorff's 19...

Couldn't read the Russian image text but I'll take a stab at it: If there are no restrictions on $M\mapsto\overline M$ at all then it's just a unary set operation: a function from the power set of $R …
Bjørn Kjos-Hanssen's user avatar
0 votes
Accepted

Subsets of reals which are both $F_{\sigma\delta}$ and $G_{\delta\sigma}$

No, let $X$ be the set of those irrationals in $x\in (0,1)$ with binary expansion $$x=0.x_1x_2\dots$$ such that if we define $x^{\text{even}}, x^{\text{odd}}$ by $$x^{\text{even}}=0.x_2x_4x_6\dots$$ $ …
Bjørn Kjos-Hanssen's user avatar
6 votes

Does the lattice of all topologies embed into the lattice of $T_1$-topologies?

Claim: Any such $\varphi$ would have to map into a set on which all homomorphisms of $\text{Top}^{T_1}(\kappa)$ are constant. This follows from Theorems 1 and 2 of Hartmanis, Juris, On the latti …
Bjørn Kjos-Hanssen's user avatar
2 votes
1 answer
201 views

Non-uniqueness in Krylov-Bogoliubov theorem

So apparently the Krylov-Bogoliubov theorem says that every continuous function $f:X\to X$ on a compact metrizable space $X$ has an invariant probability measure $\mu$. Of course, if $X$ is just a si …
4 votes
Accepted

Hausdorff interval topology on distributive lattices

The countable atomless Boolean algebra is a counterexample. See E.S. Northam, The interval topology of a lattice, 1953 (Propositions 2 and 3).
Bjørn Kjos-Hanssen's user avatar
5 votes

Is there a standard term for this graph/set theoretic concept?

In philosophy, this would be called family resemblance -- if $E_i\cap E_j\ne\emptyset$ and $E_j\cap E_k\ne\emptyset$ then $E_i$ and $E_k$ have a family resemblance. That is, perhaps I have no common …
Bjørn Kjos-Hanssen's user avatar
20 votes
Accepted

Are countable dense subspaces of $\mathbb{R}^n$ homeomorphic to ${\mathbb Q}^n$?

According to https://arxiv.org/abs/1210.1008 Example 2(c)... yes, they are all homeomorphic to $\mathbb Q$!
Emil Jeřábek's user avatar
4 votes
Accepted

Are the closed and unbounded subsets of $\mathbb{R}$ known up to homeomorphism?

Infinite, complete, separable linear order with at most countably many jumps and not both a greatest and least element. See http://www.math.uni-hamburg.de/home/geschke/papers/SeparableLinearOrders2. …
Bjørn Kjos-Hanssen's user avatar
3 votes

Sets $X,Y \subset [0,1]$, stronger than being measure $0$, such that $X+Y = [0,2]$

Inspired by Hausdorff dimension, we can try to let $X$ consist of numbers whose decimal expansion is of the form $$ 0.x_100x_4x_5x_60000\dots $$ and $Y$ consist of the "complementary" numbers: $$ 0.0x …
Bjørn Kjos-Hanssen's user avatar
5 votes

Closure of the graph of a function

According to https://mathoverflow.net/a/8994/4600, $\log_2$ of the number of topologies on $n$ elements is $\sim n^2/4$. So let's say there are $2^{n^2/4}$ topologies. Then the number of topologies on …
Community's user avatar
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