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Homotopy theory, homological algebra, algebraic treatments of manifolds.
17
votes
Why torsion is important in (co)homology ?
[[ Sorry I missed that the question was also concerned with the question in an algebraic topological context. This answer is only concerned with algebraic geometry.]]
I think the first question is mu …
15
votes
Accepted
$Sq^1$ cohomology of spaces
I think the easiest way to understand the Bockstein spectral sequence is through the exact couple coming from the long exact sequence of cohomology associated to $0\to\mathbb Z\to\mathbb Z\to \mathbb …
15
votes
Accepted
Complex vector bundles with trivial Chern classes on k-tori
As the cohomology of $(S^1)^n$ is torsion free every stable bundle on $(S^1)^n$ is
determined by Chern classes (this also follows from the $K$-theory Künneth
formula) so just as for the spheres it is …
12
votes
Torsion for Lie algebras and Lie groups
I don't know the answer to the actual question but here is a situation which
should be similar but simpler. Consider an integral polynomial group law $G$,
i.e., a group scheme structure on the affine …
12
votes
A ring such that all projectives are stably free but not all projectives are free?
This is an attempt to complete Tyler's argument. We first note that
$KO^0(S^5)=\mathbb Z$ (note this true for all spheres of dimension $\equiv 5,6,7 \bmod 8$). This means that every topological vector …
12
votes
Request: intermediate-level proof: every 2-homology class of a 4-manifold is generated by a...
I do not know if this provides more details:
I assume the closed ($4$-)manifold $M$ to
be oriented (we need the submanifold to be oriented to have an integral homology
class and the construction I a …
11
votes
Accepted
Leray-Hirsch principle for étale cohomology
[[ I have added a discussion of when $p$ is smooth or has quotient singularities. ]]
[[ I added a discussion on the cohomology of $[X/G]$. ]]
The étale case follows in a way that is altogether analog …
11
votes
Accepted
Group Completions and Infinite-Loop Spaces
A well-written discussion of the group completion can be found on pp. 89--95 of
J.F. Adam: Infinite loop spaces, Ann. of Math. studies 90 (even though he only
discusses a particular group completion o …
11
votes
Accepted
Topological dimension versus cohomological dimension
Well, I think it depends on which dimension you mean and which cohomology. The best fit I think is covering dimension and Čech cohomology. The Čech cohomological dimension is indeed bounded (more or l …
10
votes
Accepted
Sheaves over simplicial sets
Clearly looking at sheaves on the geometric realisation gives something too far
removed from the simplicial picture. This is essentially because there are too
many sheaves on a simplex have (most of w …
10
votes
Accepted
Can the class of the canonical bundle be recovered from the total space of the cotangent bun...
The reduction mod $2$ of $e(X)$ is the second Stiefel-Whitney class of $X$ which by Wu's formula can be recovered from the homotopy type of $X$ (Steenrod operations and the Poincaré duality for the mo …
9
votes
The etale fundamental group of a field
Also for the étale fundamental group there is in fact always some universal
cover. However, in the abstract way that Grothendieck formulated the theory of
coverings a universal cover would only exist …
9
votes
Splitting of the Universal Coefficients sequence
I would claim that the splitting (and indeed the whole universal coefficient
theorem) is not really a topological theorem. If we take the homological version
one really works with the chain complex $C …
8
votes
On the cohomology of a finite covering map
There is a precise relation at the level of complexes: $C^\ast(X,\mathbb Z)$ is a $G$-complex and as such it is perfect (that is quasi-isomorphic to a finite complex consisting of projective modules) …
7
votes
Accepted
When are the homology and cohomology Hopf algebras of topological groups equal?
The mod $2$ cohomology of $\mathrm{SO}_n$ is not an exterior algebra as soon
as $n\geq3$ (there is a unique non-zero element in degree $1$ whose square is
non-zero, think of the case $\mathrm{SO}_{3}$ …