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Algebras of operators on Hilbert space, $C^*-$algebras, von Neumann algebras, non-commutative geometry

1 vote

Applying positive maps to $K$-theory

This is not really an answer, but an idea. I am not sure if it works, plus you need an extra assumption on the completely positive map. Definition: We call a completely positive map $\psi \colon A \ …
Ulrich Pennig's user avatar
5 votes
Accepted

Local cross sections for Unitary group in a hilbert space

You are basically asking: When is $p \colon U(\mathcal{H}) \to U(\mathcal{H})/H$ a principal $H$-bundle. Equipped with the norm topology $U(\mathcal{H})$ is a Banach-Lie group. There is a theorem for …
Ulrich Pennig's user avatar
7 votes
Accepted

Operator Theoretical Models for $K(\mathbb{Z}, 3)$

Here is a $C^*$-algebraic version of the model described in Andre Henriques' answer (the latter was linked by David Corfield in the accepted answer above): Let $\mathcal{O}_2$ be the Cuntz algebra g …
Ulrich Pennig's user avatar
4 votes
1 answer
126 views

Automorphisms of "rational" Kirchberg algebras

Let $M_{\mathbb{Q}}$ be the universal UHF-algebra and let $\mathcal{O}_{\infty}$ be the infinite Cuntz algebra. Let $A$ be a Kirchberg algebra that satisfies the UCT with $K_0(A) \cong \mathbb{Q}^n$ a …
Ulrich Pennig's user avatar
4 votes

Is the space of *-homomorphisms between two $C^*$-algebras locally path connected

If you restrict to automorphisms of a $C^*$-algebra $A$ instead of endomorphisms $f \colon A \to B$, then I think what you suspect is true due to a paper by Kadison and Ringrose called "Derivations an …
Ulrich Pennig's user avatar
2 votes

Stabilization in Banach algebras

This is not an answer, but too long for a comment: Even for $C^*$-algebras there is more than one method of stabilization. The critical feature of the compact operators is that $K(H) \otimes K(H) \con …
Ulrich Pennig's user avatar
9 votes
1 answer
994 views

topology on the automorphism group of a C* algebra

Let $A$ be a $C^*$-algebra. The group $Aut(A)$ of $\ast$-automorphisms of $A$ is usually equipped either with the pointwise norm topology, i.e. the topology generated by the semi-norms $\lVert \varphi …
Ulrich Pennig's user avatar
3 votes

Questions about special $C^*$-subalgebras and ideals.

$B$ does not have to be unital. Think of the case $A = M(I)$. Then $p =1$ is a reasonable projection in $A \backslash I$. In this case $B= I$. Since a unit $1$ in $B$ has to satisfy $1 = p\cdot 1\cdot …
Ulrich Pennig's user avatar
10 votes

Multiplier algebra of $A \otimes \mathcal{K}$

The fact stated in the answer by vap is proven in the paper "Multipliers of C*-algebras" by Akemann, Pedersen and Tomiyama (see Theorem 3.3, I guess). Moreover, they prove in Theorem 3.8 that multipli …
Ulrich Pennig's user avatar
9 votes
Accepted

simple and non nuclear $C^*$-algebra

Following Yemon Choi's suggestion I turn my comment into an answer: Lance gave a characterization of amenability in terms of the reduced group $C^*$-algebra: A discrete group $G$ is amenable if and o …
Ulrich Pennig's user avatar
4 votes
1 answer
441 views

von Neumann algebras generated by commutators

Let $A$ be a UHF-algebra of type $n^{\infty}$ and denote its unique and faithful trace by $\tau$. Let $L^2(A)$ be the Hilbert space of the GNS-representation associated to $\tau$. We have two commutin …
Ulrich Pennig's user avatar
2 votes
Accepted

K-homology of Cantor set and abelian AF-algebras

As David Handelman already pointed out, by continuity of $K$-theory we obtain that $K_0(C(X)) \cong \bigoplus_{\mathbb{N}} \mathbb{Z}$ and $K_1(C(X)) = 0$. Since $C(X)$ is commutative, it lies in the …
Ulrich Pennig's user avatar
3 votes
Accepted

Tensoring with a CAR-algebra

The CAR-algebra is isomorphic to the UHF-algebra $M_{2^{\infty}}$, i.e. the infinite tensor products of $M_2(\mathbb{C})$. This is explained in Example 1.2.6 in the book Classification of Nuclear, Sim …
Ulrich Pennig's user avatar
4 votes
1 answer
145 views

Crossed Products by Permutation Groups

What can be said about the following crossed product $C^*$-algebra? Let $A$ be a Kirchberg algebra with $K_0(A) = \mathbb{Q}$ and $K_1(A) = 0$. Consider the direct sum of $n$ copies of $A$, i.e. $B = …
Ulrich Pennig's user avatar
2 votes

Endomorphism of type III factor: can it satisfy $\phi\circ\phi = \phi\oplus\phi$?

I think the situation you describe is impossible: Let $\bar{\phi}$ be the conjugate endomorphism to $\phi$. From the equation $d(\phi)^2 = 2d(\phi)$ we get $d(\phi) = 2$. Denote by $\langle \rho, \sig …
Ulrich Pennig's user avatar

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