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A branch of algebraic topology concerning the study of cocycles and coboundaries. It is in some sense a dual theory to homology theory. This tag can be further specialized by using it in conjunction with the tags group-cohomology, etale-cohomology, sheaf-cohomology, galois-cohomology, lie-algebra-cohomology, motivic-cohomology, equivariant-cohomology, ...

6 votes

Group cohomology version of Deligne-Beilinson cohomology

cohomology. … It is equivalent to the Segal-Mitchison smooth group cohomology. References on general simplicial Deligne cohomology are: Brylinski, J.-L.; McLaughlin, D. …
Konrad Waldorf's user avatar
2 votes
Accepted

Low dimensional integral cohomology of $BPSO(4n)$

Gawedzki and I have investigated this question for all compact simple Lie groups using the descent of multiplicative bundle gerbes from simply connected covers to quotients by subgroups of the center: …
Konrad Waldorf's user avatar
8 votes

Interpretation of the monomorphism $H^2(\pi_1(X),\mathbb{Z}) \rightarrow H^2(X,\mathbb{Z})$

If $X$ has a universal cover $\widetilde{X}$, then $\widetilde X$ is a prinicpal $\pi_1(X)$-bundle over $X$. Suppose $$ A \to E \to \pi_1(X) $$ is a central extension. Then, the corresponding class in …
Konrad Waldorf's user avatar
3 votes
Accepted

Connection Transformation Formula; Degree 3 Cech Cohomology

The equality follows directly from the definition of a connection, and is independent of the context of lifting structure groups, or degree three cohomology. …
Konrad Waldorf's user avatar
4 votes

Continuous cohomology of semi-simple Lie group

For $K=G$ in the compact case, this relative Lie algebra cohomology is identically zero. A good place to look is Stasheff's "Continuous cohomology of groups and classifying spaces". …
Konrad Waldorf's user avatar
5 votes

Group Extensions and Line Bundles on $BG$

Your line bundle $L$ over $BG$ can be seen as a $G$-equivariant line bundle over a point. That is, up to isomorphism, just a continuous group homomorphism $f:G \to \mathbb{C}^{\times}$. Try to lift $f …
Konrad Waldorf's user avatar
14 votes

Why do gerbes live in H^2?

The point is that there is an isomorphism $$ H^1(X,B\mathbb{C}^\times) = H^2(X,\mathbb{C}^\times), $$ which explains the relation to the second cohomology group. … All this is very nicely explained in Gajer's Inventiones paper "Geometry of Deligne cohomology". …
Konrad Waldorf's user avatar