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Complex analysis, holomorphic functions, automorphic group actions and forms, pseudoconvexity, complex geometry, analytic spaces, analytic sheaves.

8 votes
2 answers
373 views

Real analytic subvariety in complex manifold which is complex outside of its singular set

Let $M$ be a complex manifold, and $Z \subset M$ a closed real analytic subvariety. Suppose that the set of smooth points in $Z$ is complex analytic in $M$. Will it follow that $Z$ is complex analytic …
0 votes
Accepted

Holomorphic function on $\mathbb C^n$

This function has constant Jacobian by Liouville. Then it is map of Jacobian 1 composed with a homothety or its differential is degenerate everywhere. The constant Jacobian biholomorphisms are subject …
Misha Verbitsky's user avatar
3 votes
Accepted

Bott-Chern cohomology for singular complex spaces

closed (1,1)-forms and currents on X are not necessary locally $dd^c$-exact in general What makes it different when X is singular? The obstruction to local $dd^c$-lemma is $R^1\pi_*(O_{X'})$, where …
Misha Verbitsky's user avatar
3 votes

Can a non-Kähler complex manifold be rationally connected?

As Jason said already, there are many examples of Moishezon manifolds which are rationally connected. Indeed, any manifold bimeromorphic to a rational connected manifold is again rationally connected, …
Misha Verbitsky's user avatar
2 votes

Holomorphic vector fields acting on Dolbeault cohomology

Klemyatin proved that this action is trivial if the corresponding ${\Bbb C}$-flow is compatible with some metric (hence can be extended to a compact torus action), https://arxiv.org/abs/1909.04075, (N …
Misha Verbitsky's user avatar
7 votes
0 answers
126 views

holomorphic functions on Stein manifolds reaching maxima in a given point on the boundary (S...

Let $M$ be a Stein manifold with smooth, strictly pseudoconvex boundary, and $x$ a point on its boundary. Is there a holomorphic function $f$ on $M$, smooth on the boundary, with strict maximum of $|f …
18 votes
1 answer
810 views

Cohomology of real analytic coherent sheaves

Let $M$ be a real analytic variety (if someone is concerned about distinction between "real analytic spaces" and "real analytic varieties" in real analytic geometry, let's assume that $M$ is both "va …
6 votes

Cohomology of neighborhood of $\mathbb{C}\mathbb{P}^1$ in $\mathbb{C}\mathbb{P}^n$

It is not hard to see that the first cohomology is infinite-dimensional. Take a complement $M:=CP^3 \ CP^1$ and consider a projection $\pi:\; M \mapsto CP^1$. It is not hard to see that $M$ is isomor …
Misha Verbitsky's user avatar
5 votes

Different notions of convergence of complex subvarieties

For Kahler manifold this is true. First, notice that limits in the sense of Barlett or Douady clearly (up to multiplicity) coincide with the limits in Hausdorff topology on the set of compact subsets. …
Misha Verbitsky's user avatar
1 vote
Accepted

Meromorphic extension of local defining equations of a complex submanifold

There are manifolds without non-constant global meromorphic functions, such as generic K3 or a torus. Among these K3 surfaces, there are ones with (-2)-curves, which give a counterexample to the quest …
Misha Verbitsky's user avatar
20 votes
Accepted

Which almost complex manifolds admit a complex structure?

In complex dimension 3 or more it is still an open conjecture (which was re-stated Yau a couple of years ago in his UCLA lectures). There is not a single known example of an almost complex manifold of …
Jim Belk's user avatar
  • 8,493
4 votes

Example of a compact Kähler manifold with non-finitely generated canonical ring?

Most likely the canonical ring in Kahler situation is also finitely generated. You can check the paper http://arxiv.org/abs/1304.4013 "Minimal models for Kaehler threefolds" (Andreas Hoering, Thomas …
Misha Verbitsky's user avatar
12 votes
Accepted

Is the deformation limit of Ricci-flat Kahler manifolds Kahler?

There are counterexamples: a Moishezon manifold, which has trivial canonical class and is birationally equivalent to a hyperkahler manifold, is also deformationally equivalent to a hyperkaehler manif …
Misha Verbitsky's user avatar
7 votes
Accepted

"Simple" Kahler manifolds

A generic deformation of a Hilbert scheme of K3 and a generic torus have no subvarieties, hence they are "simple" in the above sense. For a torus it's well known, for a Hilbert scheme of K3 it's in my …
Misha Verbitsky's user avatar