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Homotopy theory, homological algebra, algebraic treatments of manifolds.
80
votes
1
answer
3k
views
Topological cobordisms between smooth manifolds
Wall has calculated enough about the cobordism ring of oriented smooth manifolds that we know that two oriented smooth manifolds are oriented cobordant if and only if they have the same Stiefel--Whitn …
58
votes
Examples where it's useful to know that a mathematical object belongs to some family of objects
This is similar to Dan Petersen's answer, but more elementary. A fact I always mention when talking to students about matrix groups is that the diagonalisable matrices (over $\mathbb{C}$) are dense in …
37
votes
Accepted
All fiber bundles over $S^2$ extendable to $\mathbb{C}P^\infty$?
No it isn't, but I had to dig quite deep to get a counterexample. Let us look at smooth $(D^7, \partial D^7)$-bundles over $S^2$, i.e $D^7 \to E \overset{\pi} \to S^2$ with an identification $\partial …
32
votes
Accepted
Fundamental group of a topological pullback
There is a ``Mayer--Vietoris" sequence
$$\cdots \to \pi_2(Z, z) \to \pi_1(E, e) \to \pi_1(X, x) \times \pi_1(Y, y) \to \pi_1(Z,z) \to \pi_0(E) \to \cdots$$
that can be developed by fitting together th …
31
votes
Does a "Chern character" exist for any generalized cohomology theory?
For any (connective) spectrum $E$ one may rationalise it to get a rational spectrum $E_\mathbb{Q}$, and a map $E \to E_\mathbb{Q}$. Now rational spectra split as wedges of Eilenberg-Mac Lane spectra, …
26
votes
Accepted
Mumford conjecture: Heuristic reasons? Generalizations? ... Algebraic geometry approaches?
All current proofs of Mumford's conjecture in fact prove a far stronger result, the "Strong Mumford conjecture", first formulated by Ib Madsen. This says the following (where by "moduli space" in the …
26
votes
Accepted
Approximation of homeomorphism by diffeomorphism
No. The space of homeomorphisms of a compact manifold is locally contractible:
A. V. Černavskiı̆. Local contractibility of the group of homeomorphisms of a manifold. Mat.
Sb. (N.S.), 79 (121):307–356 …
26
votes
Accepted
Homology theory represented by Madsen-Tillmann spectra
This is an exercise in understanding the Pontrjagin--Thom correspondence. The group $\pi_k(MTO(n) \wedge X_+)$ is in bijection with tuples of
a $(n+k)$-manifold $M$,
an $n$-dimensional vector bund …
22
votes
Accepted
Group completion theorem
The statement that $M \to \Omega BM$ is a weak equivalence when $M$ is a group-like topological monoid is indeed easier: the map $EM = B(M \wr M) \to BM$ is then a quasi-fibration, has geometric fibre …
20
votes
Accepted
Uniqueness of compactification of an end of a manifold
Suppose $\overline{M}_i$, $i=0,1$, are compact smooth manifolds with boundary whose interiors are diffeomorphic: let $\psi$ be such a diffeomorphism, and $M$ for either interior (identified via $\psi$ …
20
votes
Can one give an immersion of exotic sphere $S^7$ in a standard sphere $S^8$ of radius $1$?
Yes. By Smale-Hirsch theory it is enough to find a bundle injection $T\Sigma \to \epsilon^8$, so it is enough to find a trivialisation of $T\Sigma \oplus \epsilon^1$. It is a theorem of Kervaire and M …
19
votes
Accepted
Product-like structures on spheres
Your condition determines the map $a_1 \vee a_2 : S^n \vee S^n \to S^n$ on the $n$-skeleton, so the question is when does this extend over the $2n$-cell of $S^n \times S^n$. The $2n$-cell is by defini …
18
votes
Accepted
Are the associative grassmannian and the quaternionic projective plane diffeomorphic?
According to
Characteristic Classes and Homogeneous Spaces, I
A. Borel and F. Hirzebruch,
Section 17, they are not even homotopy equivalent: $G_2 / SO(4)$ has mod $2$ homology in degree 2, whereas …
18
votes
Accepted
Loop spaces and infinite braids
Yes, $B \beta_\infty$ is homology equivalent to $\Omega^2_0 S^2$, the zero component of the double loop space of $S^2$. The map $B_\infty \to S_\infty$ induces the obvious stablisation map $\Omega^2_0 …
18
votes
Accepted
Is every ''group-completion'' map an acyclic map?
I think I have been able to reproduce the "argument by Wagoner" (perhaps it was removed from the published version?). It certainly holds in more generality that what I have written below, using the no …