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Continuum theory, point-set topology, spaces with algebraic structure, foundations, dimension theory, local and global properties.

5 votes
2 answers
696 views

profinite spaces are the pro-completion of finite sets

The title sounds tautological, right? Perhaps I'm missing something completely trivial here ... Assume $X$ is a compact totally disconnected hausdorff space. It is known that $X$ can be written as di …
Martin Brandenburg's user avatar
6 votes
2 answers
262 views

Partial orders arising from $l$-spaces

Let $X$ be a $l$-space, i.e. a locally compact totally disconnected hausdorff space, which is not compact. Then $P = \{K : K \subseteq X \text{ compact-open}\}$ is a basis for the topology. Regard $P$ …
Martin Brandenburg's user avatar
13 votes
4 answers
1k views

nonhausdorff dimension

if $X$ is a topological space, a first step in making $X$ hausdorff is taking the quotient $H(X)=X/\sim$, where $\sim$ is the equivalence relation generated by: if $x,y$ cannot be seperated by disjoin …
Martin Brandenburg's user avatar
5 votes
1 answer
436 views

Fixed points sets of pushouts

Let $G$ be a group and $X \to Y, X \to Z$ morphisms of $G$-sets with pushout $P=Y \cup_X Z$. Is then $P^G$ the pushout of $X^G \to Y^G, X^G \to Z^G$? This is not clear from general category theory, be …
Martin Brandenburg's user avatar
6 votes
1 answer
254 views

p-adic noninvariance of dimension

Let $p$ be a prime number. Let $n,m \geq 1$ be such that the topological spaces $\mathbb{Q}_p^n$ and $\mathbb{Q}_p^m$ are homeomorphic. Can we conclude $n=m$? For $\mathbb{Z}_p$ it's false: In fact, …
Martin Brandenburg's user avatar
9 votes
2 answers
3k views

Topological proof of the Compactness Theorem in propositional logic without the Axiom of Choice

There is a well-known proof of the Compactness Theorem in propositional logic which uses the compactness of the space $\{0,1\}^P$, where $P$ is the set of propositional variables in consideration. In …
Martin Brandenburg's user avatar
4 votes
1 answer
1k views

Is "second-countable implies separable" equivalent to the Axiom of countable Choice?

It is well-known that a secound-countable topological space is separable. The proof goes like this: Let $(B_n)$ be a (at most) countable base for the topology. We may assume that $B_n$ is nonempty for …
Martin Brandenburg's user avatar
6 votes
3 answers
573 views

profinite spaces coming from profinite groups

This is probably well-known: Does every nonempty profinite space occur as the underlying space of a profinite group? If not, which conditions have to be imposed? - Is every profinite group isomorphi …
Martin Brandenburg's user avatar
5 votes
0 answers
335 views

Defining a topology by means of closed subsets in a topos

In the following we fix a topos. I'll speak of sets instead of objects and of subsets instead of subobjects. Let $X$ be a set and assume $F$ is a set of subsets of $X$ that contains $\emptyset, X$, i …
Martin Brandenburg's user avatar
17 votes
2 answers
1k views

Counterexample for associativity of smash product

In Section 1.7 of Parametrized Homotopy Theory by May and Sigurdsson it is stated that the smash product of pointed topological spaces is not associative (which is just another hint that $\mathrm{Top} …
Martin Brandenburg's user avatar
3 votes
2 answers
408 views

Ultrafilter comonad on the category of Stone spaces

Let $\mathsf{Stone}$ denote the category of Stone spaces (compact, totally disconnected Hausdorff spaces) and continuous maps. The forgetful functor $U : \mathsf{Stone} \to \mathsf{Set}$ has a left ad …
Martin Brandenburg's user avatar
51 votes
5 answers
9k views

Fundamental group as topological group

Background Let $(X,x)$ be a pointed topological space. Then the fundamental group $\pi_1(X,x)$ becomes a topological space: Endow the set of maps $S^1 \to X$ with the compact-open topology, endow the …
Martin Brandenburg's user avatar
14 votes
2 answers
755 views

Is there a large colimit-sketch for topological spaces?

Question. Is there a large colimit-sketch $\mathcal{S}$ such that $\mathrm{Mod}(\mathcal{S}) \simeq \mathbf{Top}$? In other words, is there a category $\mathcal{E}$ with a class of cocones $\mathcal{S …
Martin Brandenburg's user avatar