Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 24309

Prime numbers, diophantine equations, diophantine approximations, analytic or algebraic number theory, arithmetic geometry, Galois theory, transcendental number theory, continued fractions

2 votes
0 answers
147 views

Quadratic extension of an irrational number

Let $\alpha\in\mathbb R_{>2}\setminus\mathbb Q$ be an irrational number and let $\beta$ be such that $$\alpha+\beta+\frac{1}{\beta}=0.$$ Is there a known relationship between the irrationality measure …
Loïc Teyssier's user avatar
8 votes
1 answer
864 views

"Explicit" examples of Irrational numbers very well approximated by rational numbers

This question relates to this one and that one. Some background In the setting of discrete holomorphic dynamics (say, Julia sets) an irrational $\lambda$ is said to be well approximated by rational nu …
Loïc Teyssier's user avatar
9 votes

Can the sum of two roots of unity be a root of unity?

True. For three terms $1+i-i=1$, all of which are $4^{th}$-root of $1$. For two terms you can also write $-\frac{1+\sqrt{3}i}{2}-\frac{1-\sqrt{3}i}{2}=-1$, all of which are $6^{th}$-root of $1$. And …
Loïc Teyssier's user avatar
6 votes
Accepted

Can infinite polynomials be expressed as a product of its linear factors?

Hello Gabriel, I think you should indeed have a look at the theory of (entire) holomorphic/meromorphic functions, since $x\mapsto (x-1)\zeta(x)$ belongs to that class. You more particularly wish to l …
Loïc Teyssier's user avatar