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Questions about abstract measure and Lebesgue integral theory. Also concerns such properties as measurability of maps and sets.

5 votes

Solving interval problems without outer measure

I give an elementary solution to Problem 1 in $\mathbb{R}^n$ in my book Measure Theory and Functional Analysis (Proposition 2.16, p. 48). Here is the one-dimensional version. I guess it's clear that t …
Nik Weaver's user avatar
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6 votes
Accepted

A characterisation of continuous real functions

Edit: the proof can be made a little simpler. Yes, this condition is equivalent to $f$ being continuous. The reverse direction is easy because if $f$ is continuous at $x$ then all of the limits in que …
Nik Weaver's user avatar
  • 42.8k
29 votes
Accepted

Equivalence between Lebesgue integrable and Riemann integrable functions

Let $A$ be a measurable subset of $[0,1]$ such that both it and its complement have positive measure in every open interval in $[0,1]$ (see here for example). Its characteristic function is dominated …
Nik Weaver's user avatar
  • 42.8k
4 votes
Accepted

A “compactness theorem” for measurable functions

Counterexample. For each $n$ let $k_n$ be the characteristic function of $[0,\frac{1}{2^n}] \cup [\frac{2}{2^n},\frac{3}{2^n}] \cup \cdots$. Next observe that there are only countably many subsets of …
Nik Weaver's user avatar
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2 votes
Accepted

Strong measurability of operator-valued map induced by a kernel

It helps to note that $\mathcal{T}_tf(s) = K(s,t)\langle f(\cdot), \overline{K}(\cdot,t)\rangle$. If $K_n = \sum a_i1_{A_i\times B_i}$ is a finite linear combination of characteristic functions of rec …
Nik Weaver's user avatar
  • 42.8k
4 votes
Accepted

Conditions for the existence of von Neumann-Morgenstern utility on a Polish space

There exists a continuous, bounded utility function if and only if the relation is continuous in the stronger sense of being closed in $P(X) \times P(X)$, using the weak${}^*$ topology on each factor. …
Nik Weaver's user avatar
  • 42.8k
3 votes
Accepted

Does $\mathbb R^n$ equipped with a sum of Dirac delta measures admit nowhere locally constan...

Partition $(a_n)$ into two subsequences $(a_n')$ and $(a_n'')$ with $\sum a_n' < \infty$, and partition $(d_i)$ into two subsequences $(d_i')$ and $(d_i'')$ such that $d_i'' \to \infty$. Pair the $a_i …
Nik Weaver's user avatar
  • 42.8k
8 votes
Accepted

Does the space of Lipschitz functions have the Radon-Nikodym property?

Let $X$ be a metric space consisting of a countable set of points, the distance between any two of which is $2$, together with one additional point $e$ whose distance to any of the other points is $1$ …
Nik Weaver's user avatar
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8 votes
Accepted

Differentiability of the map $x\mapsto \delta_x$ in the Arens-Eells/Lipschitz-free space

This fails for $X = \mathbb{R}$, and hence for every nonzero Banach space, since they all contain copies of $\mathbb{R}$. If the map $t \mapsto \delta_t$ were differentiable in either sense then for e …
Nik Weaver's user avatar
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9 votes
Accepted

Explicit example of a certain weak-* limit

(reading "sequence" as "net", as suggested in the comments) Well, $C_b(\mathbb{R}^+) \cong C(\beta\mathbb{R}^+)$, so any such $L$ will arise from a probability measure on the Stone-Cech remainder $\be …
Nik Weaver's user avatar
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2 votes
Accepted

Is integration against an indicator Wasserstein-Continuous

Assuming $C$ isn't also open, find a sequence $(x_n)$ in $X\setminus C$ which converges to a point $x$ in $C$. Then the point measures $\delta_{x_n}$ converge to $\delta_x$ but their integrals against …
Nik Weaver's user avatar
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3 votes
Accepted

Convergence in weak dual topology $\sigma(L^\infty, L^1)$

It isn't research level, but $f(t) = \sin(e^{t^2})$ is a counterexample. (The uniform distance between $f$ and any shift of $f$ is $1$.)
Nik Weaver's user avatar
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10 votes
Accepted

Are lattice operations in a Lipschitz space sequentially continuous in the weak* topology?

Yes. If $f_n \to f$ weak* then the sequence $(f_n)$ must be bounded in ${\rm Lip}_0(X)$ (Banach-Steinhaus), and for bounded nets weak* convergence is the same as pointwise convergence. So $f_n \to f$ …
Nik Weaver's user avatar
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11 votes
Accepted

Completion of spaces of measures w.r.t. weak norms

This is known as the Arens-Eells space $AE(X)$. In the nonlinear Banach space literature it's also called the Lipschitz-free space $\mathcal{F}(X)$. It is not a dual space in general, but rather the p …
Nik Weaver's user avatar
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1 vote

From point-wise to essential supremum of a set of real-valued measurable functions

The question is not clear. Are you asking whether the complete distributive law holds in (probably the unit ball of) $L^\infty(X,\mu)$? The answer is no: complete distributivity is characteristic of a …
Nik Weaver's user avatar
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