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8 votes
1 answer
455 views

On commutator of bounded operators

Let $\mathbb H$ be a Hilbert space and let $\mathcal B(\mathbb H)$ be the bounded operators on $\mathbb H$. Let $J,K\in \mathcal B(\mathbb H)$ such that $ J=J^*, K=-K^*. $ Then the commutator $[J,K]$ …
Bazin's user avatar
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6 votes
Accepted

Hormander's bracket condition for the adjoint of an operator

The hypoellipticity result is more precise: you have $$ Lu \in H^s_{loc}\Longrightarrow u\in H^{s+2-\delta}_{loc}\quad\text{ for some $\delta\in [0,2)$,} $$ and that $\delta$ is linked to the number o …
Bazin's user avatar
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6 votes
Accepted

When is the adjoint of a hypoelliptic operator also hypoelliptic?

Hormander's operator $L=X_0+\sum_{1\le j\le k} X_j^2$, where the $X_j$ are real smooth vector fields with the Lie algebra of $\{(X_j)\}_{0\le j\le k}$ generating the tangent space is hypoelliptic as …
Bazin's user avatar
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4 votes

How to define Laplacian on $L_2$

(1) Let me answer first to the last question: $\Delta \vert x\vert$ is homogeneous of degree $-1$ and radial. On $\mathbb R^d$ ($d\ge 2$) it is $$ (\partial_r^2+\frac{d-1}{r}\partial_r)(r)=\frac{d-1}{ …
Bazin's user avatar
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1 vote

$L^p$ boundedness for pseudo-differential operators

I must apologize for answering my own question since I should have checked the classical results in the literature before asking these two questions. However, let me summarize the situation: we always …
Bazin's user avatar
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0 votes

ordered exponential of unbounded operators

Certainly, one should pay attention to the domain of the operator. However, the following argument should survive a reasonable assumption. We have $$ \frac{d}{dt}(E^\ast(t)E(t))=-2 E^\ast(t) A(t) E(t …
Bazin's user avatar
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0 votes
1 answer
122 views

$L^p$ boundedness for pseudo-differential operators

Let $\rho, \delta, m$ be real parameters such that $0\le \delta\le \rho\le 1, \delta<1$. The set $S^m_{\rho, \delta}(\mathbb R^{2n})$ is defined as the set of smooth functions $a$ on $\mathbb R^n\time …
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