Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 2106

(Co)chain complexes, abelian Categories, (pre)sheaves, (co)homology in various (possibly highly generalized) settings, spectra, derived functors, resolutions, spectral sequences, homotopy categories. Chain complexes in an abelian category form the heart of homological algebra.

65 votes

What is Koszul duality?

I've spent many years researching Koszul duality in its various versions. To me, Koszul duality is a fundamental homological phenomenon which has many manifestations, e.g. the relation between the h …
Leonid Positselski's user avatar
34 votes
Accepted

Does the derived category remember the homological dimension?

Let $V$ be a finite-dimensional vector space, $\mathcal{A}$ be the abelian category of finitely generated graded modules over the symmetric algebra $S(V)$, and $\mathcal{B}$ be the abelian category of …
Leonid Positselski's user avatar
28 votes
Accepted

Is there an additive functor between abelian categories which isn't exact in the middle?

Consider the abelian category of morphisms of vector spaces, i.e., the objects are linear maps $f:U\to V$, and the morphisms are commutative squares. Let the functor $Im$ assign to a morphism $f$ its …
Leonid Positselski's user avatar
26 votes

"Pick up a homological algebra book and prove all of the theorems yourself" (exercise from L...

In the Russian 1968 translation of Lang's Algebra (which is done from the Addison-Wesley 1965 edition), this exercise is there on page 126, exactly as quoted in Jonas' answer. It is complemented by t …
24 votes
1 answer
2k views

Sums of injective modules, products of projective modules?

Under what assumptions on a noncommutative ring R does a countable direct sum of injective left R-modules necessarily have a finite injective dimension? Analogously, under what assumptions on R does …
Leonid Positselski's user avatar
21 votes

The composition of derived functors - commutation fails hazardly?

My favorite (counter)example is this: let $A$, $B$, $C$ be the categories of left modules over some rings $R$, $S$, $T$ (respectively), and let $F$ and $G$ be the functors of tensor product with some …
Leonid Positselski's user avatar
21 votes
0 answers
1k views

Homotopy flat DG-modules

A right DG-module $F$ over an associative DG-algebra (or DG-category) $A$ is said to be homotopy flat (h-flat for brevity) if for any acyclic left DG-module $M$ over $A$ the complex of abelian groups …
Leonid Positselski's user avatar
19 votes
Accepted

Existence of projective resolutions in abelian categories

Among the standard examples of abelian categories without enough projectives, there are the categories of sheaves of abelian groups on a topological space (as VA said), or sheaves of modules over a …
Leonid Positselski's user avatar
17 votes
Accepted

When is bar-cobar duality an equivalence?

What the references are saying is correct, and you are right. Yes, $\Omega BA \to A$ is always a quasi-isomorphism. No, $\Omega$ does not in general take quasi-isomorphisms to quasi-isomorphisms. A …
Leonid Positselski's user avatar
17 votes

Comodule exercises desired

My favorite exercise is: prove that a comodule (over a coalgebra over a field) is coflat if and only if it is injective. This presumes that you already know that any coalgebra is the union of its fin …
Leonid Positselski's user avatar
16 votes
Accepted

Splitting of exact triangles in derived category

In any triangulated category, the necessary and sufficient condition for a distinguished triangle $A\to B\to C\to A[1]$ to split is that the morphism $C\to A[1]$ in this distinguished triangle vanishe …
Leonid Positselski's user avatar
15 votes
Accepted

Tensored Over Abelian Groups?

Given an object $X$ in an additive category $C$ and an abelian group $A$, define the object $A\otimes X$ in $C$ by the rule $Hom_C(A\otimes X,\:Y) = Hom_{Ab}(A,Hom_C(X,Y))$, where $Ab$ denotes the cat …
Leonid Positselski's user avatar
14 votes

Does homology detect chain homotopy equivalence?

Yes, this is true, and it does not matter whether the complexes are bounded from any side (nor of course does it matter whether the homology is finitely generated). This is so because: The homotopy …
Leonid Positselski's user avatar
14 votes
Accepted

Is there an adjoint to the inclusion of I-adically complete modules to all modules?

Contrary to the skepticism expressed in the question, for a finitely generated ideal $I$ in a commutative ring $R$, the completion functor $\Lambda_I\colon M\longmapsto \varprojlim_n M/I^nM$ is, in fa …
Leonid Positselski's user avatar
13 votes
Accepted

koszul duality and algebras over operads

The situation for graded modules over a pair of Koszul dual algebras is more complicated, actually. What the question says is true for Koszul algebras $A$ and $A^!$ provided that $A$ is Noetherian an …
Leonid Positselski's user avatar

15 30 50 per page