Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 18263

Banach spaces, function spaces, real functions, integral transforms, theory of distributions, measure theory.

47 votes
6 answers
5k views

Can we actually find any fixed points with Brouwer's theorem?

Background At the risk of greatly oversimplifying matters, let me state a heuristic from Granas and Dugundji's beautiful book: fixed point theorems fall into two broad categories. The first class is …
Vidit Nanda's user avatar
  • 15.5k
8 votes
3 answers
481 views

Does the metric space of compact metric spaces satisfy the binary intersection property?

A metric space $Y$ has the binary intersection property provided that whenever a collection of closed balls in $Y$ intersects pairwise, then there is a common intersection point. Does the metric s …
Vidit Nanda's user avatar
  • 15.5k
7 votes

Between Tietze's and Dugundji's extension theorems

Bad News The answer to Q3 as stated is no. Let $X$ be the Michael line, and let $Y$ be the closed subset consisting of all the rationals. Then, there is no bounded linear extension $C(Y,\mathbb{R}) \t …
Vidit Nanda's user avatar
  • 15.5k
3 votes
Accepted

A Fixed point Theorem that does not need the convexity of set valued map?

In the absence of convex images, one typically relies on algebraic topology as you have guessed. If your set-valued map has a reasonably nice domain and contractible images, then you can easily string …
Vidit Nanda's user avatar
  • 15.5k
2 votes

Representation of Banach spaces partially ordered by solid, normal, minihedral cones

Most of the proofs of this result are stated in terms of Banach lattices rather than in terms of solid, normal and minihedral cones; this might explain why Google searches are being unfriendly. In an …
Vidit Nanda's user avatar
  • 15.5k