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A stochastic process is a collection of random variables usually indexed by a totally ordered set.

3 votes

Another curious martingale

Partial answer. Continuous (local) martingales are time-changed Brownian motion. A way to obtain funny local martingales which also are Markov processes is to start from a Brownian motion $B$ and its …
Christophe Leuridan's user avatar
1 vote
Accepted

Example of random walk in a random environment (RWRE) saying things on the environment

An example: Matzinger studied the revocery of the environment from the second factor of a RWRE. https://arxiv.org/pdf/1110.6853.pdf https://matzi.math.gatech.edu/overview.pdf
Christophe Leuridan's user avatar
3 votes
Accepted

Brownian bridges as conditioning

If $X$ and $Y$ are independent random variables taking values in arbitrary spaces $E$ and $F$, if $Z = f(X,Y)$ for any measurable map $f : E \times F \to G$, then the family of distributions of the ra …
Christophe Leuridan's user avatar
0 votes
Accepted

Phase space Brownian bridge

I use capital letters for random variables and small letters for possible values. Let $W$ be a brownian motion, defined on the canonical space $\mathcal{C}(\mathbb{R}_+)$ endowed with the Wiener measu …
Christophe Leuridan's user avatar
0 votes

Is integral of adapted separable process adapted?

Partial answer The question may be whether the process $f$ is progressively measurable under the assumptions. If yes, we can conclude as follows. Fix $t \ge 0$. For each $\omega$, $f(\cdot,\omega)$ is …
Christophe Leuridan's user avatar
2 votes

Density of $W_t$ assuming it stayed above a line $L$

As I mentionned in my comment, there is an ambiguity in the statement of you question. Anyway, if $B$ is a standard one dimensional Brownian motion, if $\lambda$ is a real number, then $(B_t-\lambda t …
Christophe Leuridan's user avatar
2 votes

Integrated square difference of Brownian bridges

For every Gaussian centered process $X$, if one takes an independent copy $X'$, then the process $X+X'$ has the same distribution as $\sqrt{2}X$ (to see that, compare their finite dimensional marginal …
Christophe Leuridan's user avatar
1 vote
Accepted

Can an a.s. non constant continuous martingale be differentiable with nonzero probability?

Almost surely, we can write for every $t \ge 0$, $M_t=M_0+\beta_{\langle M,M \rangle_t}$, where $\beta$ is some Brownian motion. By Kahane's theorem, almost surely, for every $s \ge 0$, $\limsup_{\del …
Christophe Leuridan's user avatar
0 votes
Accepted

Is the number of uncrossing invariant under time-change?

We have $U_{a,b}^T(Y) = U_{a,b}^{h(T)}(X)$. By construction, the function $h$ maps $[0,T]$ onto $[0,h(T)]$. More precisely, each $t' \in [0,h(T)]$ can be written $h(h^\leftarrow(t'))$, where $h^\lefta …
Christophe Leuridan's user avatar
4 votes
Accepted

Enlargement of filtration

I think that I have a counterexample. Let $(X,Y)$ be a Brownian motion in $\mathbb{R}^2$. Then $M = \int_0^\cdot X_s \mathrm{d}Y_s$ is a martingale, in the natural filtration of $(X,Y)$, in its own fi …
Christophe Leuridan's user avatar
1 vote

Solution to SDE conditional on high maxima of driving Brownian motion

Partial answer First, an heuristic argument. When we condition by events with low probability, the main is given by behaviour the less improbable situation. Here we condition by $S_1 := \max_{0 \le s …
Christophe Leuridan's user avatar