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Topology of cell complexes and manifolds, classification of manifolds (e.g. smoothing, surgery), low dimensional topology (e.g. knot theory, invariants of 4-manifolds), embedding theory, combinatorial and PL topology, geometric group theory, infinite dimensional topology (e.g. Hilbert cube manifolds, theory of retracts).

36 votes

Compactification theorem for differentiable manifolds ?

No. A surface of infinite genus is not a submanifold of a compact surface.
Autumn Kent's user avatar
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29 votes

Fundamental group of 3-manifold with boundary

No. The Baumslag--Solitar groups $\langle a, b | ab^m a^{-1} = b^n \rangle$ are not three-manifold groups when $m \neq n$. See: Heil, Wolfgang H. Some finitely presented non-$3$-manifold groups. Proc …
Autumn Kent's user avatar
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26 votes
Accepted

Diffeomorphisms vs homeomorphisms of 3-manifolds

$\mathsf{Diff}(S^3)$ is homotopy equivalent to $O(4)$, by Hatcher's solution to the Smale Conjecture: Hatcher, Allen E. A proof of the Smale conjecture, Diff(S3)≃O(4). Ann. of Math. (2) 117 (1983), no …
Autumn Kent's user avatar
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23 votes

Elegant proof that any closed, oriented 3-manifold is the boundary of some oriented 4-manifold?

Maybe overkill, but elegant: By a theorem of Hirsch, an oriented $3$-manifold $M$ embeds in the $5$-sphere (nonorientable case: Rohlin and Wall, independently). By Alexander duality, $M$ bounds a "S …
Autumn Kent's user avatar
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21 votes
Accepted

For which surfaces is Penner's conjecture known to be true?

Shin and Strenner have shown that the conjecture is false when 3g + n > 4. See http://arxiv.org/abs/1410.6974
19 votes

Fibers of fibrations of a 3-manifold over $S^1$

As you suspect, the answer is no. There are $3$-manifolds that fiber over the circle in infinitely many ways, with fibers of unbounded genera. Thurston constructed a seminorm on $H_2(M,\partial M; \ …
Autumn Kent's user avatar
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17 votes
Accepted

Homology generated by lifts of simple curves

As far as I know, this is open. In fact, I think the following weaker question is open. Let $\Theta$ be the set of loops $\gamma$ in $\widetilde \Sigma$ such that the image of $\gamma$ in $\Sigma$ …
Autumn Kent's user avatar
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15 votes
Accepted

Word problem for fundamental group of submanifolds of the 4-sphere

Update: My memory was quite blurry about this when I originally answered. See Gonzáles-Acuña, Gordon, Simon, ``Unsolvable problems about higher-dimensional knots and related groups,'' L’Enseigneme …
Autumn Kent's user avatar
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15 votes
Accepted

Is the spectrum of closed geodesics in a closed hyperbolic 3-manifold asymptotically homogen...

I think this should just follow from the exponential mixing of the geodesic flow (due to Pollicott). Exponential mixing says that there is a constant $q$ such that if you have two smooth functions $f …
Autumn Kent's user avatar
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14 votes

When is a extension of $\mathbb{Z}$ by a free group a CAT(0) group?

You'll find some examples of CAT(0) free-by-cyclics in Samuelson, "On CAT(0) structures for free-by-cyclic groups" and Barnard and Brady, "Distorsion of surface groups in CAT(0) free-by-cyclic grou …
Autumn Kent's user avatar
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14 votes
Accepted

Do different Dehn fillings produce homeomorphic 3-manifolds ?

This phenomenon is called "cosmetic surgery." If $K$ is an amphichiral knot in the $3$--sphere with exterior $M_K$, then $M_K(p/q) \cong - M_K(-p/q)$. So if $p/q$ is a hyperbolic filling slope, the …
Autumn Kent's user avatar
  • 10.6k
14 votes

Torsion in homology or fundamental group of subsets of Euclidean 3-space

I'll assume that the subset is compact. Then, if you use Cech cohomology, Alexander duality turns this into a question about the complement, which is a 3-manifold. So, I answer with another question: …
Autumn Kent's user avatar
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13 votes
Accepted

Hyperbolic structures on $S\times\mathbb{R}$

It follows from Thurston's Covering Theorem that there are no such examples. The covering theorem says that if a degenerate end is infinite-to-one under a covering map, then you are (virtually) in th …
Autumn Kent's user avatar
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12 votes
Accepted

Topological rigidity of compact manifolds in dimension three

Yes. When the manifolds are Haken this is a theorem of Waldhausen. See Ian Agol's answer here. Since your manifolds are aspherical, they are irreducible by the Poincaré conjecture. Since they have …
Autumn Kent's user avatar
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12 votes
Accepted

Examples of acylindrical 3-manifolds

     (source) The exterior of Suzuki's Brunnian graph on $n$-edges, here pictured with $n=7$, is irreducible, atoroidal, boundary incompressible, and acylindrical. See Luisa Paoluzzi and Bruno Zi …
Autumn Kent's user avatar
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