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Topology of cell complexes and manifolds, classification of manifolds (e.g. smoothing, surgery), low dimensional topology (e.g. knot theory, invariants of 4-manifolds), embedding theory, combinatorial and PL topology, geometric group theory, infinite dimensional topology (e.g. Hilbert cube manifolds, theory of retracts).

7 votes
Accepted

Kirby diagram of the complement of a subhandlebody of a smooth closed 4-manifold

When the decomposition of $X$ has no 3-handles, this is often feasible. The trick is to turn the handle decomposition of $X$ upside down (see Example 5.5.5 in Gompf and Stipsicz's 4-manifolds and Kirb …
Marco Golla's user avatar
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5 votes
Accepted

Why is this Brieskorn manifold a rational homology sphere?

The key is pointed out by HJRW in his comment: there's a missing piece in your explanation, which is the genus of the base $B$ of the Seifert fibration. Némethi writes: $$ 2g-2 = (n−2)A/a−\sum q_i, $$ …
Marco Golla's user avatar
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7 votes
Accepted

If a lattice can be embedded into $\mathbb Q^n,\langle-1\rangle^n$, then can it be embedded ...

As Ian Agol points out in his comment, $-E_8$ is an example of a lattice that embeds in $\mathbb{Q}^8$ but not in $\mathbb{Z}^n$ for any $n$. The embedding in $\mathbb{Q}^8$ is given explicitly in Con …
Marco Golla's user avatar
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1 vote

Necessary condition for invertible knot concordance from both ends

No, this is not true: any doubly-slice knots gives a counterexample to your statement. A knot $K$ is doubly-slice if there is an unknotted 2-sphere $F$ in $S^4$ such that $(S^3,K)$ is diffeomorphic to …
Marco Golla's user avatar
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7 votes

$3$-manifold that is a surgery on a knot

About your third question: Are there any partial results for branched double covers of knots? The Montesinos trick tells you that if $K$ has unknotting number 1, then its double cover is $\pm\frac{\ …
Marco Golla's user avatar
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5 votes

Euler number of a Seifert bundle as a generalization of an Euler number of a circle bundle o...

Why is the Euler number of a Seifert bundle a "natural" generalization of a circle bundle over a surface? I can see at least three reasons: A circle bundle is a Seifert manifold with no singular fi …
Marco Golla's user avatar
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7 votes

Generalization of the sphere theorem in dimension at least 4

Aru Ray and Danny Ruberman wrote a paper (here the arxiv version) about Dehn's lemma in dimension 4. From the abstract: We investigate certain 4-dimensional analogues of the classical 3-dimensional D …
Marco Golla's user avatar
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7 votes

Detecting a "bad map" in Fintushel-Stern knot surgery

There is nothing inherently "bad" with other choices. My guess is that Fintushel and Stern chose this identification for three reasons: first, they can give a nice formula for how the Seiberg–Witten i …
Marco Golla's user avatar
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7 votes
Accepted

Picture of the isotopy class of a degree $d$ smooth complex curve

This might be a bit annoying to justify (see below), but I'm quite sure that the surface you're looking for is constructed as follows. (And in any case this is too long for a comment.) Start with the …
Marco Golla's user avatar
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9 votes
Accepted

Are two slice surfaces with minimal genus isotopic?

The question is very loaded and the question would almost require a survey... Anyway, the answer to your questions is mostly no. Let $S \subset S^4$ be a 2-knot (i.e. an embedded 2-sphere), $p \in S$ …
Marco Golla's user avatar
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6 votes
Accepted

A Mazur manifold bounded by $\Sigma(2,3,13)$

I don't know where you took the picture from, but that link is not symmetric (and it likely does not describe the correct manifold). Indeed, the 0-framed component of the link you drew is a trefoil: i …
Marco Golla's user avatar
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10 votes
Accepted

Two surfaces in a 4-manifold whose algebraic intersection number is zero

Yes, this can be done by tubing one surface along the other. Suppose that you have two intersection points $p_+, p_- \in \Sigma_1 \cap \Sigma_2$ of opposite signs. Suppose also that $\Sigma_1$ and $\S …
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6 votes
Accepted

Homology classes in connected sum of $\Bbb CP^2$'s that can be represented by smoothly embed...

As Mike says in his comment, the answer is not known in full generality, not even for $n=2$, so for classes in $\mathbb{CP}^2\#\mathbb{CP}^2$. I think the paper that he links (https://arxiv.org/abs/22 …
Marco Golla's user avatar
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5 votes
Accepted

Examples of homology sphere that bound a nonsmoothable contractible 4-manifold

There are certainly lots of obstructions coming from gauge theory, for instance Frøyshov's $h$-invariant or Ozsváth and Szabó's $d$-invariant. If an integer homology sphere $P$ has $d(P) \neq 0$, then …
Marco Golla's user avatar
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2 votes
Accepted

Are all exact Lagrangian spheres, vanishing cycles?

No, this is not necessarily true. In fact, this is never the case if $E = B^4$, and $F$ has connected boundary and genus $g \ge 2$. Since $H_1(E) = 0$, the vanishing cycles span $H_1(F)$. An Euler cha …
Marco Golla's user avatar
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