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Complex, contact, Riemannian, pseudo-Riemannian and Finsler geometry, relativity, gauge theory, global analysis.

2 votes
0 answers
93 views

Does any warped product metric with harmonic Weyl curvature admit a structure of zero radial...

A Riemannian manifold $(M, g)$ has harmonic Weyl curvature iff its Schouten tensor is Codazzi, and if there exists $f: M \to \mathbb{R}$ such that $W(\bullet, \bullet, \bullet, \nabla f) = 0$, one say …
0 votes
1 answer
107 views

Does any warped product metric admit a function with hessian proportional to the metric?

It is known that the existence of a function with hessian proportional to the metric implies that the metric is a warped product metric. Is the reciprocal true as well? I.e, if $(B \times N, g = g_B + …
2 votes
0 answers
103 views

What is known about warped product metrics satisfying conditions more general than conformal...

In this paper, the authors characterize warped product metrics which are conformally flat (the fibers must have constant sectional curvature, on some cases there is a limitation on the number of possi …
2 votes
1 answer
104 views

Why is this subset associated to a $2$-tensor dense?

Let $S$ be a symmetric $(0, 2)$ tensor on a Riemannian manifold $M$. Define $E_S : M \to \mathbb{Z}$ by $E_S(x) = \left(\text{the number of distinct eigenvalues of } S_x\right)$. I've seen the followi …
4 votes
2 answers
554 views

What are some explicit examples of nontrivial gradient almost Ricci solitons with harmonic c...

A Riemannian manifold $(M, g)$ is said to be an almost Ricci soliton if there exists a complete vector field $X \in \Gamma(TM)$ and a smooth function $\lambda: M \to \mathbb{R}$ such that $$\operatorn …
3 votes
1 answer
163 views

Curvature estimate in Hamilton's Ricci flow paper for traceless $\operatorname{Rm}$ on $4$-d...

In dimension $4$, it is known that the curvature operator $\operatorname{Rm} : \Lambda^2(M) \to \Lambda^2(M)$ admits a block decomposition of the form $$\operatorname{Rm} = \begin{pmatrix} A & B \\ B^ …
1 vote

Curvature estimate in Hamilton's Ricci flow paper for traceless $\operatorname{Rm}$ on $4$-d...

After a lot more time thinking about it, I think I've figured it out. Let $\Gamma$ be a constant such that $ \Gamma \|g \odot g \| = 1$ (where $\odot$ denotes the Kulkarni Nomizu product, and the only …
Matheus Andrade's user avatar
3 votes
0 answers
115 views

Geometric intuition behind definition of $\delta$-necklike points of the Ricci flow

In "The Ricci Flow: An Introduction", the authors define a $\delta$-necklike point of the Ricci flow as a point $(x, t)$ where $$\|\text{Rm} - R (\theta \otimes \theta)\| \leq \delta \|\text{Rm}\|$$ f …
0 votes
1 answer
305 views

Estimating scalar curvature by norm of Riemannian curvature tensor under the Ricci flow

In B. Chow and D. Knopf's book "The Ricci Flow: An Introduction", the authors claim that for any dimension $n$ and any Riemannian manifold $M^n$, there is a constant $C_n$ depending only on $n$ such t …
4 votes
0 answers
188 views

Classifying singularities of the Ricci flow

Context: A solution $(M^n, g(t))$ of the Ricci flow is said to encounter a Type III Singularity if $g(t)$ is defined for all $t \geq 0$ and: $$ \sup _{\mathcal{M}^{n} \times[0, \infty)} \|\operatorna …
13 votes
1 answer
632 views

Are there examples of Einstein manifolds with unbounded curvature?

Are there any known examples of Einstein manifolds $(M, g)$ such that $$\sup_{x \in M} \|\text{Rm}(x) \| = \infty$$ I'm looking for these examples because they might provide a counter-example to a pro …
3 votes
0 answers
89 views

Proving some identities about the time derivative of the k-th covariant derivatives of scala...

I'm trying to prove the following identities (under the normalized Ricci flow on surfaces, on which $\partial_t g = (r-R)g$ holds true, where $r$ denotes the average scalar curvature and has the same …
12 votes
3 answers
1k views

Does the mean curvature flow naturally come with less applications than intrinsic curvature ...

I know studying the mean curvature flow is a very interesting area of research, I've fooled around with it a bit myself. But it honestly doesn't look like it has much applications within mathematics i …
0 votes
0 answers
284 views

What exactly does it mean for Hamilton's cigar soliton to have linear volume growth?

In a couple articles I've read lately, I've seen it mentioned that the cigar soliton has linear volume growth. What does this mean? I thought maybe, if you compute the volume of geodesic balls and inc …
1 vote
1 answer
198 views

How can one smoothly close a non closed curve?

Let $\alpha: [0, L] \to \mathbb{R}^2$ be smooth and such that $\langle\alpha(L) - \alpha(0), (0,1) \rangle = 0$, $\alpha(0) \neq \alpha(L)$ and $\alpha'(0) = k\alpha'(L)$ for some $k$. We know that $ …

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