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This tag is used if a reference is needed in a paper or textbook on a specific result.
5
votes
Accepted
Trigonometric identity needed for sums involving secants
Two other references to similar sums are
Bruce C. Berndt and Boon Pin Yeap, Explicit evaluations and reciprocity theorems for finite trigonometric sums, Advances in Applied Mathematics
Volume 29, Is …
2
votes
Reference request : an elementary product-sum formula for binomial coefficients
Another very short proof: the left side is a polynomial in $X$ of degree $a+b$ that takes integer values when $X$ is an integer, so it can be expressed in the form of the right side.
The identity is …
6
votes
A certain type of combinatorial identity, involving de Montmort numbers
The first formula is due to Herbert Ryser, who derived it from an inclusion-exclusion formula for the permanent of a matrix. It can be found in his book Combinatorial Mathematics, Mathematical Associa …
5
votes
Accepted
A certain type of combinatorial identity, involving de Montmort numbers
In John Riordan's book Combinatorial Identities, page 21, is the formula
$$\sum_{k=0}^n \binom{n}{k}(x+k)^k (y+n-k)^{n-k}=
\sum_{k=0}^n \binom{n}{k} k!\, (x+y+n)^{n-k}.$$
(There is a typo in the for …
25
votes
Accepted
Eulerian number identity
Here's a proof of the identity. Unfortunately, it doesn't show how anyone would come up with this formula. Like the proofs referred to in the comments, this proof is based on the beta integral
$$\int …
6
votes
Proof of Stirling number symmetric formulas
$\def\sone#1#2{\left[#1\atop #2\right]}
\def\stwo#1#2{\left\{#1\atop #2\right\}}
$
These formulas can be proved by Lagrange interpolation, using the fact that
$\stwo{n}{n-m}$ and $\sone{n}{n-m}$ are …
3
votes
Reference request: enumeration under group action
Thanks to the OEIS, I found a reference to almost the same formula:
Marko V. Jarić and Joseph L. Birman, New algorithms for the Molien function, Journal of Mathematical Physics 18, 1456 (1977); doi: …
1
vote
A list of symmetric statistics
The distribution of descents and leaves in forests of rooted trees is symmetric. See http://www.combinatorics.org/ojs/index.php/eljc/article/view/v3i2r8/pdf.
2
votes
Accepted
Reference request on symmetric polynomials
The fact that the binary operation defined by (2) is associative can be found in the Wikipedia article on formal groups (section 2) http://en.wikipedia.org/wiki/Formal_group. Presumably one might find …
1
vote
Accepted
Number of Ordered Trees of given degree sequence
Is Theorem 6.4 of http://people.brandeis.edu/~gessel/homepage/papers/enum.pdf what you want?
2
votes
Finite differences of Stirling numbers
Let $c(n,k) = |s(n,k)| = (-1)^{n-k} s(n,k)$. It is well known that for fixed $k$, $S(n+k,n)$ and $s(n+k,n)$ are polynomials in $n$ of degree $2k$ with leading coefficient $(2k-1)!!/(2k)!$. If we exten …
5
votes
Accepted
NE-Lattice paths from $(0,0)$ to $(n,n)$ with $k$ peaks
The formula in 2 is a very special case of a result of Richard Stanley's, though it certainly could be older. (I wouldn't be surprised if it can be found in MacMahon's work.) See, e.g., my paper A his …
50
votes
Accepted
New binomial coefficient identity?
In terms of hypergeometric series, the sum is $_3F_2(-n, 1+n, 1/2;1,3/2;1)$ and the identity is a special case of Saalschütz's theorem (also called the Pfaff-Saalschütz theorem), one of the standard h …
4
votes
Is this a known symmetry of lattice paths?
The binomial identity is the well-known Vandermonde's theorem $\sum_{j=0}^n \binom{a}{j}\binom{b}{n-j} = \binom{a+b}{n}$ with $a=-i-1$, $b=i-m-1$.
8
votes
Accepted
The number of lattice paths below y=n/m x for gcd(m,n) = 1
You can use the approach of my paper A factorization for formal Laurent series,
Journal of Combinatorial Theory, Series A
28 (1980) 321-337. Although this problem is not considered in that paper, The …