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-2 votes
0 answers
43 views

About the uniqueness of the Taylor polynomial

I'm in trouble understanding this theorem: For a given function, differentiable n times at a given point $x_0$, there exist a unique polynomial $P_n$ (of degree $\le$n) such that $$\forall \; k=0,...,...
Sapo's user avatar
  • 1
2 votes
1 answer
136 views

Expressing a vector valued function in terms of its derivatives

Consider a function $$ f:\mathbb{R}^n\rightarrow\mathbb{R}^m $$ given by $m$ functions $f_i:\mathbb{R}^n\rightarrow \mathbb{R}$ that we can assume to be polynomials in $x_1,\dots,x_n$. Does there ...
R_O's user avatar
  • 23
8 votes
1 answer
2k views

Polynomial approximation for square root function with fast convergence and bounded coefficients

Let $\delta, \varepsilon \in (0,1)$. I am interested in a sequence $\{f_n\}$ of polynomial approximations of the square root function $x \to x^{1/2}$ on $[\delta,1]$, of the form $$ f_n(x) = \sum_{i=0}...
Mark M. Wilde's user avatar
1 vote
0 answers
72 views

Approximation Rates for Multivariate Taylor Series

Let $k,n,m$ be positive integers and suppose that $f$ is $C^{k}(\mathbb{R}^n,\mathbb{R}^m)$ functions. For any given $\epsilon>0$ and $x_0\in \mathbb{R}^n$, are there known sharp approximation ...
ABIM's user avatar
  • 5,405
0 votes
1 answer
662 views

A polynomial and its reciprocal expansion [closed]

Suppose $f(x)=\prod_{k=1}^n(x-a_k)$ where all $a_k>0$. Expand the function $\frac1f$ at $\infty$ so that $$\frac1{f(x)}=\frac{b_n}{x^n}+\frac{b_{n+1}}{x^{n+1}}+\cdots.$$ Does it follow that each $...
Lewi_Sol's user avatar
  • 309
1 vote
0 answers
121 views

Properties and name of some polynomials

I have encountered in a problem some polynomials given by $P_k(x) = \prod_{j=0}^{k-2} (kx-j)$. I need to understand if these polynomials are known, and if they have certain special properties, as ...
Geno Whirl's user avatar
78 votes
7 answers
8k views

Roots of truncations of $ e^x - 1$

During a talk I was at today, the speaker mentioned that if you truncate the Taylor series for $e^x - 1$, you'll get lots of roots with nonzero real part, even though the full Taylor series only has ...
Vectornaut's user avatar
  • 2,284