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The orthogonal group of a riemannian metric

Let the inner product of the vectors X and Y on a given four dimensional manifold (EDIT: make this R4) be defined as (X*Y) = gikXiYk; using the summation convention for repeated indicies. Let A be a ...
Matt's user avatar
  • 251
20 votes
3 answers
9k views

Curvature of a Lie group

Since a lie group is a manifold with the structure of a continuous group, then each point of the manifold [Edit: provided we fix a metric, for example an invariant or bi-invariant one] has some scalar ...
Matt's user avatar
  • 251
6 votes
3 answers
2k views

Action of the group of isometries on a manifold

Hi guys, I am able to prove that any symmetric manifold is complete (Consider a local geodesic and use the symmetry to flip it, effectively doubling the length of the geodesic, ad infinitum). I want ...
kangdon's user avatar
  • 516
2 votes
1 answer
826 views

Frobenius Theorem

Say a manifold M has 3 vector fields S,T and R whose Lie brackets satisfy the equations $[S,T]=R$, $[R,S]=T$ and $[T,R]=S$ Then I suppose the following properties hold for M, There exists a metric ...
Anirbit's user avatar
  • 3,541
6 votes
4 answers
3k views

Killing fields on homogeneous spaces

Let $G$ be a compact lie group and $H$ a closed subgroup and hence think of $G/H$ as a homogeneous space. Then how are the Killing fields on $G/H$ the projection of the right-invariant vector fields ...
Anirbit's user avatar
  • 3,541

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