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10 votes
2 answers
767 views

Intuition for the Drift Term of the Laplace-Beltrami Operator

In coordinates, the Laplace-Beltrami operator on a Riemannian manifold $(M,g)$ can be written as: $$ \Delta_g = g^{ij}\partial_{ij} - g^{jk}\Gamma^\ell_{jk}\partial_\ell $$ The second term: $$ \mu^\...
user3658307's user avatar
2 votes
0 answers
137 views

Heat-Flow on continuous differential forms and the Feller peroperty

Let (M,g) be a complete Riemannian manifold. It is well known that the Laplace operator is essentially self-adjoint on $C^\infty_c(M)$. This extends to the (de Rahm) Laplace operator on forms. Thus in ...
Nathanael Schilling's user avatar
5 votes
1 answer
444 views

heat kernel on closed manifolds - error in Chavel's book?

first of all, I am not sure if this question fits here. I asked this question on math.stackexchange also but didn't get an answer so far. In Isaac Chavel's book Eigenvalues in Riemannian Geometry, ...
heatoperator's user avatar
4 votes
1 answer
137 views

Geodesic-like curves stemming from the heat kernel on a manifold

Consider a smooth $n$-dimensional Riemannian manifold $M$ with sufficiently nice geometric and topological properties such that there exist a unique heat kernel $(t,x,y) \mapsto p(t,x,y)$ on it ($t>...
Alex M.'s user avatar
  • 5,407
4 votes
1 answer
797 views

The heat kernel as an exponential of an integral

In $\mathbb{R}^n$, if $\gamma$ is a line segment between $x_0 = \gamma (0)$ and $x = \gamma (t)$, one has the following formula: $$\frac {\mathbb{e}^{- \frac{1}{4} \int_0^t <\dot{\gamma}, \dot{\...
Alex M.'s user avatar
  • 5,407